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Four resistors of 50 Ω, 50 Ω, 100 Ω and 100 Ω each are connected in parallel across 100 V dc supply. What is the current though each branch if both the resistors of 50 Ω burn out?
  • a)
    1 A
  • b)
    6 A
  • c)
    4 A
  • d)
    2 A
Correct answer is option 'A'. Can you explain this answer?
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Four resistors of 50 Ω, 50 Ω, 100 Ω and 100 Ω ...
Current flowing through 100 Ω resistance,
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Four resistors of 50 Ω, 50 Ω, 100 Ω and 100 Ω ...
To determine the total resistance of four resistors of 50Ω each, we need to use the formula for resistors in parallel.

The formula for resistors in parallel is:

1/RTotal = 1/R1 + 1/R2 + 1/R3 + 1/R4

Substituting the values, we get:

1/RTotal = 1/50 + 1/50 + 1/50 + 1/50

Simplifying, we get:

1/RTotal = 4/50

To solve for RTotal, we take the reciprocal of both sides:

RTotal = 50/4

Simplifying, we get:

RTotal = 12.5Ω

Therefore, the total resistance of four resistors of 50Ω each is 12.5Ω.
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