If all three medians of triangle are equal then prove that it is equil...
Let us call our triangle ABC and our medians AD, BE and CF, where D is the mid-point of AB, E is the midpoint of AC and F is the midpoint of AB.
Let us say all the medians intersect at the point M, which would make M the centroid of our triangle ABC.
Now a centroid divides each median in the ratio 2:1. So we now have
AM:MD = BM:ME = CM:MF = 2:1
The question says that the medians are equal in length. So let us say AM = BM = CM = 2 units and MD = ME = MF = 1 unit.
Now consider the triangles, CDM and AFM. They can be proved to be congruent, because the CM = AM, FM = MD and the angle between AMF = angle between CMD. Now since these triangles are congruent, AF = CD.
But F is the mid-point of AB, so AF = FB. So we just proved AF = FB = BD = CD.
Hence, AF + FB = BD + CD. And hence, AB = BC.
You can prove similarly for the side AC and AB too and show that BC = AC, effectively proving that AB = BC = AC and hence its an equilateral triangle.
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If all three medians of triangle are equal then prove that it is equil...
Proof:
To prove that a triangle is equilateral when all three medians are equal, we can use the properties of medians and the concept of congruence.
Definition:
A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side.
Given:
We are given that all three medians of the triangle are equal.
Proof:
Step 1: Let's assume we have a triangle ABC with medians AD, BE, and CF.
Step 2: Since AD is the median, it divides the side BC into two equal segments, BD and DC.
Step 3: Similarly, median BE divides AC into two equal segments, AE and EC.
Step 4: Finally, median CF divides AB into two equal segments, AF and FB.
Step 5: Now, we can consider the triangles ADE, BEF, and CFD.
Step 6: By the properties of medians, we know that the medians of a triangle intersect at a point called the centroid. Let's denote the centroid as G.
Step 7: Since the medians are equal, we can say that AD = BE = CF.
Step 8: Since AD = BE, we can conclude that BD = EC.
Step 9: Similarly, from AD = CF, we can conclude that DC = AF.
Step 10: Finally, from BE = CF, we can conclude that AE = FB.
Step 11: Now, if we consider the triangle AFB, we have AE = FB and AF = FB. Therefore, triangle AFB is an isosceles triangle.
Step 12: Similarly, we can prove that triangles ADE and BEF are also isosceles triangles.
Step 13: Since all three triangles AFB, ADE, and BEF are isosceles triangles, we can conclude that all three angles of each triangle are equal.
Step 14: Therefore, triangle ABC is an equilateral triangle since all three angles are equal and all three sides are equal.
Conclusion:
Hence, we have proved that if all three medians of a triangle are equal, then the triangle is an equilateral triangle.
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