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The “spin-only” magnetic moment [in units of Bohr magneton, (μB)] of Fe2+ in aqueous solution would be
(At. No. Fe = 26)
  • a)
    2.84
  • b)
    4.90
  • c)
    0
  • d)
    1.73
Correct answer is option 'B'. Can you explain this answer?
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The “spin-only” magnetic moment [in units of Bohr magneton, (μB)] of Fe2+ in aqueous solution would be(At. No. Fe = 26)a)2.84b)4.90c)0d)1.73Correct answer is option 'B'. Can you explain this answer?
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The “spin-only” magnetic moment [in units of Bohr magneton, (μB)] of Fe2+ in aqueous solution would be(At. No. Fe = 26)a)2.84b)4.90c)0d)1.73Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The “spin-only” magnetic moment [in units of Bohr magneton, (μB)] of Fe2+ in aqueous solution would be(At. No. Fe = 26)a)2.84b)4.90c)0d)1.73Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The “spin-only” magnetic moment [in units of Bohr magneton, (μB)] of Fe2+ in aqueous solution would be(At. No. Fe = 26)a)2.84b)4.90c)0d)1.73Correct answer is option 'B'. Can you explain this answer?.
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