A box contains 2 white, 3 black and 4 red balls . In how many ways can...
Solution:
Step 1: Find the total number of ways of drawing 3 balls
The total number of ways of drawing 3 balls from a box containing 9 balls is:
C(9,3) = (9!)/(3!6!) = 84
Step 2: Find the number of ways of drawing 3 balls with no restrictions
The number of ways of drawing 3 balls with no restrictions is:
C(2,3) + C(3,3) + C(4,3) = 0 + 1 + 4 = 5
Step 3: Find the number of ways of drawing 3 balls with at least one white ball
The number of ways of drawing 3 balls with at least one white ball is:
C(2,1) * C(7,2) = 2 * 21 = 42
Step 4: Find the number of ways of drawing 3 balls with at least one black ball
The number of ways of drawing 3 balls with at least one black ball is:
C(3,1) * C(6,2) = 3 * 15 = 45
Step 5: Find the number of ways of drawing 3 balls with at least one red ball
The number of ways of drawing 3 balls with at least one red ball is:
C(4,1) * C(5,2) = 4 * 10 = 40
Step 6: Find the number of ways of drawing 3 balls with at least one white ball and one black ball
The number of ways of drawing 3 balls with at least one white ball and one black ball is:
[C(2,1) * C(3,1)] * C(4,1) = 2 * 3 * 4 = 24
Step 7: Find the number of ways of drawing 3 balls with at least one white ball and one red ball
The number of ways of drawing 3 balls with at least one white ball and one red ball is:
[C(2,1) * C(4,1)] * C(3,1) = 2 * 4 * 3 = 24
Step 8: Find the number of ways of drawing 3 balls with at least one black ball and one red ball
The number of ways of drawing 3 balls with at least one black ball and one red ball is:
[C(3,1) * C(4,1)] * C(2,1) = 3 * 4 * 2 = 24
Step 9: Find the number of ways of drawing 3 balls with at least one white ball, one black ball, and one red ball
The number of ways of drawing 3 balls with at least one white ball, one black ball, and one red ball is:
C(2