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a open knife edge of mass 200g is dropped from height 5m on a cardboard. if the knife penetrates distance 2m into cardboard , the average resistance offered by the cardboard to the knife edge is?(g=10m/s2)
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a open knife edge of mass 200g is dropped from height 5m on a cardboa...
The problem states that an open knife edge with a mass of 200g is dropped from a height of 5m onto a cardboard. The knife penetrates a distance of 2m into the cardboard. We need to find the average resistance offered by the cardboard to the knife edge.
Step 1: Calculate the potential energy of the knife edge
The potential energy (PE) of the knife edge can be calculated using the formula:
PE = mgh
Where m is the mass of the knife edge (200g = 0.2kg), g is the acceleration due to gravity (10m/s^2), and h is the height (5m).
PE = 0.2kg * 10m/s^2 * 5m
= 10J
Step 2: Calculate the work done by the resistance force
The work done by the resistance force (W) can be calculated using the formula:
W = F * d
Where F is the average resistance force offered by the cardboard and d is the distance penetrated by the knife edge (2m).
W = F * 2m
Step 3: Equate the potential energy to the work done
Since the potential energy is converted into work done by the resistance force, we can equate the two values:
PE = W
10J = F * 2m
Step 4: Solve for the average resistance force
Dividing both sides of the equation by 2m, we can solve for the average resistance force:
F = 10J / 2m
= 5N
Therefore, the average resistance offered by the cardboard to the knife edge is 5N.
Explanation:
When the knife edge is dropped, it possesses potential energy due to its height above the ground. As it falls, this potential energy is converted into kinetic energy. When the knife penetrates into the cardboard, the resistance force offered by the cardboard opposes the motion of the knife edge, doing work on it.
By equating the potential energy to the work done, we can find the average resistance force offered by the cardboard. In this case, the average resistance force is found to be 5N. This means that the cardboard exerted an average force of 5N on the knife edge as it penetrated into it.
It's important to note that this calculation assumes that the resistance force offered by the cardboard is constant throughout the penetration distance of 2m. In reality, the resistance force might vary, but this simplified calculation provides an average value.
Step 1: Calculate the potential energy of the knife edge
The potential energy (PE) of the knife edge can be calculated using the formula:
PE = mgh
Where m is the mass of the knife edge (200g = 0.2kg), g is the acceleration due to gravity (10m/s^2), and h is the height (5m).
PE = 0.2kg * 10m/s^2 * 5m
= 10J
Step 2: Calculate the work done by the resistance force
The work done by the resistance force (W) can be calculated using the formula:
W = F * d
Where F is the average resistance force offered by the cardboard and d is the distance penetrated by the knife edge (2m).
W = F * 2m
Step 3: Equate the potential energy to the work done
Since the potential energy is converted into work done by the resistance force, we can equate the two values:
PE = W
10J = F * 2m
Step 4: Solve for the average resistance force
Dividing both sides of the equation by 2m, we can solve for the average resistance force:
F = 10J / 2m
= 5N
Therefore, the average resistance offered by the cardboard to the knife edge is 5N.
Explanation:
When the knife edge is dropped, it possesses potential energy due to its height above the ground. As it falls, this potential energy is converted into kinetic energy. When the knife penetrates into the cardboard, the resistance force offered by the cardboard opposes the motion of the knife edge, doing work on it.
By equating the potential energy to the work done, we can find the average resistance force offered by the cardboard. In this case, the average resistance force is found to be 5N. This means that the cardboard exerted an average force of 5N on the knife edge as it penetrated into it.
It's important to note that this calculation assumes that the resistance force offered by the cardboard is constant throughout the penetration distance of 2m. In reality, the resistance force might vary, but this simplified calculation provides an average value.
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a open knife edge of mass 200g is dropped from height 5m on a cardboard. if the knife penetrates distance 2m into cardboard , the average resistance offered by the cardboard to the knife edge is?(g=10m/s2)
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a open knife edge of mass 200g is dropped from height 5m on a cardboard. if the knife penetrates distance 2m into cardboard , the average resistance offered by the cardboard to the knife edge is?(g=10m/s2) for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about a open knife edge of mass 200g is dropped from height 5m on a cardboard. if the knife penetrates distance 2m into cardboard , the average resistance offered by the cardboard to the knife edge is?(g=10m/s2) covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a open knife edge of mass 200g is dropped from height 5m on a cardboard. if the knife penetrates distance 2m into cardboard , the average resistance offered by the cardboard to the knife edge is?(g=10m/s2).
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