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A 3-f star connected symmetrical load consumes p watts of power from a balancedsupply. If the same load is connected in delta to the same supply, the power consumption will be
a)p
b)√3 p
c)3p
d)P/3
Correct answer is option 'C'. Can you explain this answer?
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A 3-f star connected symmetrical load consumes p watts of power from a...
Solution:
Given, a 3-phase star connected symmetrical load consumes p watts of power from a balanced supply.
To find: the power consumption when the same load is connected in delta to the same supply.
When the same load is connected in delta to the same supply, the phase voltage across each element of the load remains the same as it was in star configuration, i.e., Vph = Vline/√3. But the phase current in delta connection is √3 times the line current in star connection.
Let us consider the load impedance to be Z.
Power consumption in a 3-phase star connected symmetrical load is given by,
P = √3 Vph Iph cosφ
where,
Vph = phase voltage
Iph = phase current
φ = phase angle between voltage and current
In a balanced 3-phase load, the phase impedances are equal, i.e, Z1 = Z2 = Z3 = Z.
In star configuration, the line current is,
Iline = Iph
In delta configuration, the line current is,
Iline = √3 Iph
Power consumption in delta configuration is given by,
P = 3 Vph Iline cosφ
Substituting Vph = Vline/√3 and Iline = √3 Iph, we get
P = 3 Vline Iph cosφ
Thus, the power consumption in delta connection is 3 times the power consumption in star connection.
Therefore, the correct option is (c) 3p.
Given, a 3-phase star connected symmetrical load consumes p watts of power from a balanced supply.
To find: the power consumption when the same load is connected in delta to the same supply.
When the same load is connected in delta to the same supply, the phase voltage across each element of the load remains the same as it was in star configuration, i.e., Vph = Vline/√3. But the phase current in delta connection is √3 times the line current in star connection.
Let us consider the load impedance to be Z.
Power consumption in a 3-phase star connected symmetrical load is given by,
P = √3 Vph Iph cosφ
where,
Vph = phase voltage
Iph = phase current
φ = phase angle between voltage and current
In a balanced 3-phase load, the phase impedances are equal, i.e, Z1 = Z2 = Z3 = Z.
In star configuration, the line current is,
Iline = Iph
In delta configuration, the line current is,
Iline = √3 Iph
Power consumption in delta configuration is given by,
P = 3 Vph Iline cosφ
Substituting Vph = Vline/√3 and Iline = √3 Iph, we get
P = 3 Vline Iph cosφ
Thus, the power consumption in delta connection is 3 times the power consumption in star connection.
Therefore, the correct option is (c) 3p.
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Community Answer
A 3-f star connected symmetrical load consumes p watts of power from a...
In star the resistance is suppose r,
and if reconnect it with in delta the resistance is 3r,
and we know the P=I^2 R
or in star P(prop to) R
and in delta P(prop to) 3R
so loss will increase three times
and if reconnect it with in delta the resistance is 3r,
and we know the P=I^2 R
or in star P(prop to) R
and in delta P(prop to) 3R
so loss will increase three times
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A 3-f star connected symmetrical load consumes p watts of power from a balancedsupply. If the same load is connected in delta to the same supply, the power consumption will bea)pb)√3 pc)3pd)P/3Correct answer is option 'C'. Can you explain this answer?
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