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Use Euclid's division lemma to show that thw cube pf any positive integer is of the form 9m,9m 1, or 9m 8?
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Use Euclid's division lemma to show that thw cube pf any positive inte...
Let a and b be two positive integergs such that a is greater than b; then :

a = bq + r;

where q and r are positive integers 0 ≤ r < b.

Taking b = 3, we get

a = 3q + r ; where 0 ≤ r < 3.

⇒ Different values of integer a are 3q, 3q + 1 or 3q + 2.

Cube of 3q = (3q)^3

= 27q^3 = 9(3q^3) = 9m ;

where m is some integer.

Cube of 3q + 1 = (3q + 1)^3

= (3q + 3(3q)^2 � 1 + 3(3q) � 12+ l3

[∵ (a + b)^3 = a^3 + 3a^2b + 3ab^2 + 1]

= 27q^3 + 27q^2 + 9q + 1

= 9(3q^3 + 3q^2 + q) + 1

= 9m + 1; where m is some integer.

Cube of 3q + 2 = (3q + 2)^3

= (3q)^3 + 3(3q)^2 � 2 + 3 � 3q � 22 + 23

= 27q^3 + 54q^2 + 36q + 8

= 9(3q^3 + 6q^2 + 4q) + 8 = 9m + 8; where m is some integer.

∴ Cube of any positive integer is of the form 9m or 9m + 1 or 9m + 8.
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Use Euclid's division lemma to show that thw cube pf any positive integer is of the form 9m,9m 1, or 9m 8?
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