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J.J. Thomson’s cathode-ray tube experimentdemonstrated that [2003]a)the e/m ratio of the cathode-ray particleschanges when a different gas is placed inthe discharge tubeb)cathode rays are streams of negativelycharged ionsc)all the mass of an atom is essentially in thenucleusd)the e/m of electrons is much greater thanthe e/m of protonsCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about J.J. Thomson’s cathode-ray tube experimentdemonstrated that [2003]a)the e/m ratio of the cathode-ray particleschanges when a different gas is placed inthe discharge tubeb)cathode rays are streams of negativelycharged ionsc)all the mass of an atom is essentially in thenucleusd)the e/m of electrons is much greater thanthe e/m of protonsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for J.J. Thomson’s cathode-ray tube experimentdemonstrated that [2003]a)the e/m ratio of the cathode-ray particleschanges when a different gas is placed inthe discharge tubeb)cathode rays are streams of negativelycharged ionsc)all the mass of an atom is essentially in thenucleusd)the e/m of electrons is much greater thanthe e/m of protonsCorrect answer is option 'B'. Can you explain this answer?.

Solutions for J.J. Thomson’s cathode-ray tube experimentdemonstrated that [2003]a)the e/m ratio of the cathode-ray particleschanges when a different gas is placed inthe discharge tubeb)cathode rays are streams of negativelycharged ionsc)all the mass of an atom is essentially in thenucleusd)the e/m of electrons is much greater thanthe e/m of protonsCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

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