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12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is
(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)
- a)149.20 C
- b)113.30 C
- c)116.70C
- d)111.10C
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boi...
(b) When (Kz) mole fraction boiling point elevation constant is given, then
Thus,boiling point of solution =110+ 3.28 =113.28°C
Most Upvoted Answer
12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boi...
°C, Kb of toluene = 2.53°C/m)
To calculate the boiling point of the solution, we need to use the following formula:
ΔTb = Kb x molality
where ΔTb is the change in boiling point, Kb is the boiling point elevation constant of toluene, and molality is the concentration of the solution in moles of solute per kilogram of solvent.
First, we need to calculate the molality of the solution:
molality = moles of solute / mass of solvent in kg
The moles of naphthalene can be calculated as follows:
moles of naphthalene = mass of naphthalene / molar mass of naphthalene
moles of naphthalene = 12.8 g / 128.17 g/mol
moles of naphthalene = 0.1 mol
The mass of toluene in kg can be calculated as follows:
mass of toluene = 92 g / 1000 g/kg
mass of toluene = 0.092 kg
Therefore, the molality of the solution is:
molality = 0.1 mol / 0.092 kg
molality = 1.09 mol/kg
Now we can calculate the change in boiling point:
ΔTb = Kb x molality
ΔTb = 2.53°C/m x 1.09 mol/kg
ΔTb = 2.76°C
Finally, we can calculate the boiling point of the solution:
boiling point of solution = boiling point of pure solvent + ΔTb
boiling point of solution = 110°C + 2.76°C
boiling point of solution = 112.76°C
Therefore, the boiling point of the solution is 112.76°C.
To calculate the boiling point of the solution, we need to use the following formula:
ΔTb = Kb x molality
where ΔTb is the change in boiling point, Kb is the boiling point elevation constant of toluene, and molality is the concentration of the solution in moles of solute per kilogram of solvent.
First, we need to calculate the molality of the solution:
molality = moles of solute / mass of solvent in kg
The moles of naphthalene can be calculated as follows:
moles of naphthalene = mass of naphthalene / molar mass of naphthalene
moles of naphthalene = 12.8 g / 128.17 g/mol
moles of naphthalene = 0.1 mol
The mass of toluene in kg can be calculated as follows:
mass of toluene = 92 g / 1000 g/kg
mass of toluene = 0.092 kg
Therefore, the molality of the solution is:
molality = 0.1 mol / 0.092 kg
molality = 1.09 mol/kg
Now we can calculate the change in boiling point:
ΔTb = Kb x molality
ΔTb = 2.53°C/m x 1.09 mol/kg
ΔTb = 2.76°C
Finally, we can calculate the boiling point of the solution:
boiling point of solution = boiling point of pure solvent + ΔTb
boiling point of solution = 110°C + 2.76°C
boiling point of solution = 112.76°C
Therefore, the boiling point of the solution is 112.76°C.
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Community Answer
12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boi...
(b) When (Kz) mole fraction boiling point elevation constant is given, then
Thus,boiling point of solution =110+ 3.28 =113.28°C
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12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer?
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12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer?.
12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer?.
Solutions for 12.8 g of naphthalene (C10H8) is dissolved in 92 g toluene (C7H8). Boiling point of this solution is(boiling point of toluene = 110°Cand mole fraction boiling point elevation constant of toluene is 36.1 K)a)149.20Cb)113.30Cc)116.70Cd)111.10CCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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