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In SO3 molecule, 3 oxygen atoms are attached to sulphur atom through double bonds. Hence, the molecules consist 3π-bonds. The types of pi-bonds present in SO3 molecule are
- a)two pπ-dπ and one pπ-pπ
- b)one pπ-dπ and two pπ-pπ
- c)one pπ-pπ and one pπ-dπ
- d)All pπ-pπ bonds
Correct answer is option 'A'. Can you explain this answer?
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In SO3 molecule, 3 oxygen atoms are attached to sulphur atom through d...
In gas phase, SO3 molecule is triangular planar having sp2-hybridisation of the S-atom. There are three sigma bonds formed by sp2-p overlap and three pi-bonds are by pπ-pπ overlap and two pπ-dπ overlap.
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In SO3 molecule, 3 oxygen atoms are attached to sulphur atom through d...
In the SO3 molecule, there are three oxygen atoms attached to a sulfur atom through double bonds. This means that there are three pi bonds present in the molecule. The types of pi bonds present in the SO3 molecule can be determined by examining the hybridization of the atoms involved.
1. Hybridization of sulfur:
- In the SO3 molecule, sulfur is surrounded by three oxygen atoms. In order to accommodate the bonding, sulfur undergoes sp2 hybridization, where one s orbital and two p orbitals hybridize to form three sp2 hybrid orbitals.
- These sp2 hybrid orbitals are arranged in a trigonal planar geometry around the sulfur atom, with each orbital pointing towards one of the oxygen atoms.
2. Hybridization of oxygen:
- Each oxygen atom in the SO3 molecule is attached to the sulfur atom through a double bond.
- To form a double bond, one oxygen orbital and one sulfur orbital must overlap. Since sulfur is sp2 hybridized, it has one unhybridized p orbital available for pi bonding.
- The oxygen atom also has two unhybridized p orbitals available for pi bonding.
3. Types of pi bonds:
- In the SO3 molecule, there are three oxygen atoms attached to the sulfur atom.
- Each oxygen atom forms a pi bond with the sulfur atom, resulting in three pi bonds in total.
- The overlapping orbitals involved in these pi bonds are as follows:
- Two of the pi bonds are formed between a sulfur p orbital and an oxygen p orbital (p-d pi bonds).
- One of the pi bonds is formed between an oxygen p orbital and a sulfur p orbital (p-p pi bond).
Therefore, the correct answer is option 'A' - two p-d pi bonds and one p-p pi bond.
1. Hybridization of sulfur:
- In the SO3 molecule, sulfur is surrounded by three oxygen atoms. In order to accommodate the bonding, sulfur undergoes sp2 hybridization, where one s orbital and two p orbitals hybridize to form three sp2 hybrid orbitals.
- These sp2 hybrid orbitals are arranged in a trigonal planar geometry around the sulfur atom, with each orbital pointing towards one of the oxygen atoms.
2. Hybridization of oxygen:
- Each oxygen atom in the SO3 molecule is attached to the sulfur atom through a double bond.
- To form a double bond, one oxygen orbital and one sulfur orbital must overlap. Since sulfur is sp2 hybridized, it has one unhybridized p orbital available for pi bonding.
- The oxygen atom also has two unhybridized p orbitals available for pi bonding.
3. Types of pi bonds:
- In the SO3 molecule, there are three oxygen atoms attached to the sulfur atom.
- Each oxygen atom forms a pi bond with the sulfur atom, resulting in three pi bonds in total.
- The overlapping orbitals involved in these pi bonds are as follows:
- Two of the pi bonds are formed between a sulfur p orbital and an oxygen p orbital (p-d pi bonds).
- One of the pi bonds is formed between an oxygen p orbital and a sulfur p orbital (p-p pi bond).
Therefore, the correct answer is option 'A' - two p-d pi bonds and one p-p pi bond.
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In SO3 molecule, 3 oxygen atoms are attached to sulphur atom through double bonds. Hence, the molecules consist 3π-bonds. The types of pi-bonds present in SO3 molecule area)two pπ-dπ and one pπ-pπb)one pπ-dπ and two pπ-pπc)one pπ-pπ and one pπ-dπd)All pπ-pπ bondsCorrect answer is option 'A'. Can you explain this answer?
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ample number of questions to practice In SO3 molecule, 3 oxygen atoms are attached to sulphur atom through double bonds. Hence, the molecules consist 3π-bonds. The types of pi-bonds present in SO3 molecule area)two pπ-dπ and one pπ-pπb)one pπ-dπ and two pπ-pπc)one pπ-pπ and one pπ-dπd)All pπ-pπ bondsCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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