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Which of the following expressions represents the correct distribution of the electrons in the conduction band? (gc(E)=density of quantum states, fF(E)=Fermi dirac probability
  • a)
    n(E)=gc(E)*fF(E)
  • b)
    n(E)=gc(-E)*fF(E)
  • c)
    n(E)=gc(E)*fF(-E)
  • d)
    n(E)= gc(-E)*fF(-E)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Which of the following expressions represents the correct distribution...
The distribution of the electrons in the conduction band is given by the product of the density into Fermi-dirac distribution.
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Most Upvoted Answer
Which of the following expressions represents the correct distribution...
The correct expression that represents the distribution of electrons in the conduction band is option 'A' which is n(E) = gc(E) * fF(E).

Explanation:
- The distribution of electrons in the conduction band can be determined by considering the density of quantum states (gc(E)) and the Fermi-Dirac probability (fF(E)).

Density of Quantum States (gc(E)):
- The density of quantum states, gc(E), represents the number of available energy states per unit energy range.
- It describes the number of energy states available for electrons to occupy at a given energy level E in the conduction band.

Fermi-Dirac Probability (fF(E)):
- The Fermi-Dirac probability, fF(E), describes the probability of an energy state being occupied by an electron at a given energy level E.
- It takes into account the principle of Pauli exclusion, which states that each energy state can be occupied by a maximum of one electron.
- The Fermi-Dirac probability ranges from 0 to 1, where 0 represents an unoccupied state and 1 represents a fully occupied state.

Combining Density of Quantum States and Fermi-Dirac Probability:
- The expression n(E) = gc(E) * fF(E) represents the number of electrons occupying a particular energy state in the conduction band.
- Multiplying the density of quantum states, gc(E), by the Fermi-Dirac probability, fF(E), gives the number of occupied energy states at a given energy level E.

Explanation of Incorrect Options:
- Option 'B' (n(E) = gc(-E) * fF(E)) does not correctly represent the distribution of electrons in the conduction band because it uses a negative sign for the density of quantum states, which is not physically meaningful.
- Option 'C' (n(E) = gc(E) * fF(-E)) does not correctly represent the distribution of electrons in the conduction band because it uses a negative sign for the Fermi-Dirac probability, which also does not have physical significance.
- Option 'D' (n(E) = gc(-E) * fF(-E)) combines the incorrect aspects of both options 'B' and 'C', and therefore does not represent the correct distribution of electrons in the conduction band.

Conclusion:
- The correct expression to represent the distribution of electrons in the conduction band is option 'A' (n(E) = gc(E) * fF(E)), which correctly combines the density of quantum states and the Fermi-Dirac probability to determine the number of occupied energy states at a given energy level E.
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Which of the following expressions represents the correct distribution of the electrons in the conduction band? (gc(E)=density of quantum states, fF(E)=Fermi dirac probabilitya)n(E)=gc(E)*fF(E)b)n(E)=gc(-E)*fF(E)c)n(E)=gc(E)*fF(-E)d)n(E)= gc(-E)*fF(-E)Correct answer is option 'A'. Can you explain this answer?
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Which of the following expressions represents the correct distribution of the electrons in the conduction band? (gc(E)=density of quantum states, fF(E)=Fermi dirac probabilitya)n(E)=gc(E)*fF(E)b)n(E)=gc(-E)*fF(E)c)n(E)=gc(E)*fF(-E)d)n(E)= gc(-E)*fF(-E)Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Which of the following expressions represents the correct distribution of the electrons in the conduction band? (gc(E)=density of quantum states, fF(E)=Fermi dirac probabilitya)n(E)=gc(E)*fF(E)b)n(E)=gc(-E)*fF(E)c)n(E)=gc(E)*fF(-E)d)n(E)= gc(-E)*fF(-E)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following expressions represents the correct distribution of the electrons in the conduction band? (gc(E)=density of quantum states, fF(E)=Fermi dirac probabilitya)n(E)=gc(E)*fF(E)b)n(E)=gc(-E)*fF(E)c)n(E)=gc(E)*fF(-E)d)n(E)= gc(-E)*fF(-E)Correct answer is option 'A'. Can you explain this answer?.
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