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In this module we will deal with basic concepts of time and distance, speed, average speed, conversion from km/h to m/s and vice versa. This chapter will form the basis of further concept of relative speed which is used in train and boat problems.
Important Formulas
Solved Examples
1. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?  
A. 8.2  B. 4.2 
C. 6.1  D. 7.2 
Answer : Option D
Explanation :
Distance = 600 meter
time = 5 minutes = 5 x 60 seconds = 300 seconds
Speed = distance/time=600/300=2m/s=(2×18)/5 km/hr=36/5 km/hr=7.2 km/hr
2. Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart?  
A. 17 hr  B. 14 hr 
C. 12 hr  D. 19 hr 
Answer : Option A
Explanation :
Relative speed = 5.5  5 = .5 kmph (because they walk in the same direction)
distance = 8.5 km
Time = distance/speed=8.5/.5=17 hr.
3. Walking 6/7^{th} of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance?  
A. 1 hr 42 min  B. 1 hr 
C. 2 hr  D. 1 hr 12 min 
Answer : Option D
Explanation :
New speed = 6/7 of usual speed
Speed and time are inversely proportional.
Hence new time = 7/6 of usual time
Hence, 7/6 of usual time  usual time = 12 minutes
=> 1/6 of usual time = 12 minutes => usual time = 12 x 6 = 72 minutes = 1 hour 12 minutes
4. A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, what is the distance between his house and office?  
A. 3 km  B. 4 km 
C. 5 km  D. 6 km 
Answer : Option D
Explanation :
If a car covers a certain distance at x kmph and an equal distance at y kmph,the average speed of the whole journey = 2xy/(x+y) kmph
Hence, average speed = (2×3×2)/(2+3)=12/5 km/hr .
Total time taken = 5 hours
⇒Distance travelled = (12/5)×5=12 km
⇒Distance between his house and office =12/2=6 km
5. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. What is the actual distance travelled by him?  
A. 80 km  B. 70 km 
C. 60 km  D. 50 km 
Answer : Option D
Explanation :
Assume that the person would have covered x km if travelled at 10 km/hr
⇒Speed = Distance/Time=x/10..... (Equation1)
Give that the person would have covered (x + 20) km if travelled at 14 km/hr
⇒Speed = Distance/Time=(x+20)/14..... (Equation2)
From Equations 1 and 2,
X/10=(x+20)/14 ⇒14x=10x+200 ⇒4x=200 ⇒x=200/4=50
6. A car travels at an average of 50 miles per hour for 212 hours and then travels at a speed of 70 miles per hour for 112 hours. How far did the car travel in the entire 4 hours?  
A. 210 miles  B. 230 miles 
C. 250 miles  D. 260 miles 
Answer : Option B
Explanation :
Speed1 = 50 miles/hour
Time1 = 2*(1/2) hour=5/2 hour
⇒ Distance1 = Speed1 × Time1 = (50×5)/2=25×5=125 miles
⇒Speed2 = 70 miles/hour
Time2 = 1*1/2 hour=3/2 hour
Distance2 = Speed2 × Time2 = 70×3/2=35×3=105 miles
Total Distance = Distance1 + Distance2 =125+105=230 miles
7. Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, ^{11}/_{5} seconds after he sees it strike the tree. How far is the man from the wood chopper?  
A. 1800 ft  B. 2810 ft 
C. 3020 ft  D. 2420 ft 
Answer : Option D
Explanation :
Speed of the sound = 1100 ft/s ⇒Time = ^{11}/_{5} second
Distance = Speed × Time = 1100 ×11/5=220×11=2420 ft
8. A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. What is the length of the bridge (in meters)?  
A. 1250  B. 1280 
C. 1320  D. 1340 
Answer : Option A
Explanation :
Speed = 5 km/hr
Time = 15 minutes = 1/4 hour
Length of the bridge = Distance Travelled by the man
= Speed × Time = 5×1/4 km
=5×1/4×1000 metre=1250 metre
9. A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is  
A. 11 hrs  B. 8 hrs 45 min 
C. 7 hrs 45 min  D. 9 hts 20 min 
Answer : Option C
Explanation :
Given that time taken for riding both ways will be 2 hours lesser than the time needed for waking one way and riding back
From this, we can understand that time needed for riding one way = time needed for waking one way  2 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min
In fact, you can do all these calculations mentally and save a lot of time which will be a real benefit for you.
10. A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.  
A. 121 km  B. 242 km 
C. 224 km  D. 112 km 
Answer : Option C
Explanation :
distance = speed x time
Let time taken to travel the first half = x hr
then time taken to travel the second half = (10  x) hr
Distance covered in the first half = 21x
Distance covered in the second half = 24(10  x)
But distance covered in the first half = Distance covered in the second half
=> 21x = 24(10  x) => 21x = 240  24x => 45x = 240 => 9x = 48 => 3x = 16 ⇒x=16/3
Hence Distance covered in the first half = 21x=21×16/3=7×16=112 km. Total distance = 2×112=224 km
109 docs21 tests
