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# 8. Percentage, Quantitative Aptitude, Civil Service Examination, RPSC UPSC Notes | EduRev

## RAS RPSC Prelims Preparation - Notes, Study Material & Tests

Created by: Notes Wala

## UPSC : 8. Percentage, Quantitative Aptitude, Civil Service Examination, RPSC UPSC Notes | EduRev

The document 8. Percentage, Quantitative Aptitude, Civil Service Examination, RPSC UPSC Notes | EduRev is a part of the UPSC Course RAS RPSC Prelims Preparation - Notes, Study Material & Tests.
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• Percentage

Percent means for every 100

So, when percent is calculated for any value, it means that we calculate the value for every 100 of the reference value.

percent is denoted by the symbol %. For example, x percent is denoted by x%
• x%=x/100

Example : 25%=25/100=1/4
• To express x/y as a percent, we have x/y=(x/y×100)%

Example : 1/4=(1/4×100)%=25%

• If the price of a commodity increases by R%, the reduction in consumption so as not to increase the expenditure = [R/(100+R)×100]%
• If the price of a commodity decreases by R%, the increase in consumptions o as not to decrease the expenditure = [R/(100−R)×100]%
• If the population of a town = P and it increases at the rate of R% per annum, then Population after n years = P((1+R)/100))n
• If the population of a town = P and it increases at the rate of R% per annum, then Population before n years = P((1+R)/100))n

Then Value of the machine after n years = P((1-R)/100))n

If the present value of a machine = P and it depreciates at the rate of R% per annum,

Solved Examples

 1. If A = x% of y and B = y% of x, then which of the following is true? A. None of these B. A is smaller than B. C. Relationship between A and B cannot be determined. D. If x is smaller than y, then A is greater than B. E. A is greater than B.

Explanation :

A = xy/100 ………….(Equation 1)

B = yx/100.................(Equation 2)

From these equations, it is clear that A = B

 2. If 20% of a = b, then b% of 20 is the same as: A. None of these B. 10% of a C. 4% of a D. 20% of a

Explanation :

20% of a = b

=> b = 20a/100

b% of 20 = 20b/100=(20a/100) × 20/100

=(20×20×a)/(100×100)=4a/100 = 4% of a

 3. Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B. A. 2 : 1 B. 1 : 2 C. 1 : 1 D. 4 : 3

Explanation :

5% of A + 4% of B = 2/3(6% of A + 8% of B)

5A/100+4B/100=2/3(6A/100+8B/100)

⇒5A+4B=2/3(6A+8B)

⇒15A+12B=12A+16B

⇒3A=4B

⇒AB=43⇒A:B=4:3

 4. The population of a town increased from 1,75,000 to 2,62,500 in a decade. What is the average percent increase of population per year? A. 4% B. 6% C. 5% D. 50%

Explanation :

Increase in the population in 10 years = 2,62,500 - 1,75,000 = 87500

% increase in the population in 10 years = (87500/175000)×100=8750/175=50%

Average % increase of population per year = 50%/10=5%

 5. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get? A. 57% B. 50% C. 52% D. 60%

Explanation :

Total votes = 1136 + 7636 + 11628 = 20400

Required percentage = (11628/20400)×100=11628/204=2907/51=969/17=57%

 6. A fruit seller had some oranges. He sells 40% oranges and still has 420 oranges. How many oranges he had originally? A. 420 B. 700 C. 220 D. 400

Explanation :

He sells 40% of oranges and still there are 420 oranges remaining

=> 60% of oranges = 420

⇒(60×Total Oranges)/100=420

⇒Total Oranges/100=7

⇒ Total Oranges = 7×100=700

 7. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets? A. 499/11 % B. 45 % C. 500/11 % D. 489/11 %

Explanation :

Total runs scored = 110

Total runs scored from boundaries and sixes = 3 x 4 + 8 x 6 = 60

Total runs scored by running between the wickets = 110 - 60 = 50

Required % = (50/110)×100=500/11%

 8. What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit? A. 2023% B. 20% C. 21% D. 2223%

Explanation :

Total numbers = 70

Total numbers in 1 to 70 which has 1 in the unit digit = 7

Total numbers in 1 to 70 which has 9 in the unit digit = 7

Total numbers in 1 to 70 which has 1 or 9 in the unit digit = 7 + 7 = 14

Required percentage = (14/70)×100=140/7=20%

 9. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got? A. 2800 B. 2700 C. 2100 D. 2500

Explanation :

Total number of votes = 7500

Given that 20% of Percentage votes were invalid

1st candidate got 55% of the total valid votes.

Hence the 2nd candidate should have got 45% of the total valid votes

=> Valid votes that 2nd candidate got = (total valid votes ×45)/100

=7500×(80/100)×(45/100)=75×(4/5)×45=75×4×9=300×9=2700

 10. In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State? A. 8200 B. 7500 C. 7000 D. 8000

Explanation :

State A and State B had an equal number of candidates appeared.

In state A, 6% candidates got selected from the total appeared candidates

In state B, 7% candidates got selected from the total appeared candidates

But in State B, 80 more candidates got selected than State A

From these, it is clear that 1% of the total appeared candidates in State B = 80

=> total appeared candidates in State B = 80 x 100 = 8000

=> total appeared candidates in State A = total appeared candidates in State B = 8000

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## RAS RPSC Prelims Preparation - Notes, Study Material & Tests

109 docs|21 tests

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