Class 12 Exam > Class 12 Videos > Ampere (Part - 29) - Moving Charges & Magnetism
Ampere (Part - 29) - Moving Charges & Magnetism Video Lecture - Class 12
FAQs on Ampere (Part - 29) - Moving Charges & Magnetism Video Lecture - Class 12
| 1. What is Ampere's law and how is it related to moving charges and magnetism? |  |
Ans. Ampere's law states that the magnetic field created by a current-carrying wire is proportional to the electric current flowing through the wire. It relates to moving charges and magnetism as it helps to determine the magnetic field produced by the movement of charges, such as in a current-carrying wire.
| 2. How can the direction of the magnetic field around a current-carrying wire be determined? | |
Ans. The direction of the magnetic field around a current-carrying wire can be determined using the right-hand rule. If you point your right thumb in the direction of the current, the curling of your fingers around the wire indicates the direction of the magnetic field.
| 3. What is the relationship between the magnetic field and the distance from a current-carrying wire? | |
Ans. The magnetic field produced by a current-carrying wire decreases with increasing distance from the wire. The relationship between the magnetic field strength (B) and the distance (r) from the wire is inversely proportional, following the formula B ∝ 1/r.
| 4. How does the strength of the magnetic field change with an increase in the electric current through a wire? | |
Ans. The strength of the magnetic field around a wire increases with an increase in the electric current flowing through the wire. The relationship between the magnetic field strength (B) and the current (I) is directly proportional, following the formula B ∝ I.
| 5. Can Ampere's law be used to calculate the magnetic field inside a solenoid? | |
Ans. Yes, Ampere's law can be used to calculate the magnetic field inside a solenoid. The law states that the magnetic field around a closed loop is equal to the product of the current enclosed by the loop and a constant called the permeability of free space. By applying Ampere's law to a solenoid, we can determine the magnetic field inside it.
Text Transcript from Video
hello friends this video on matter and
magnetism part 29 is brought to you by
exam feel calm no more fear from exam
please make sure that you have watched
all the videos till part 28 before going
ahead with part 29 the basis of this
concept this observation was of amperes
actually ampere was the one who observed
this parallel and antiparallel currents
attraction and repulsion phenomenon so
ampere was the one so after he was able
to understand the phenomenon behind this
attraction and repulsion of parallel and
antiparallel currents he defined ampere
I mean ampere was any means the unit of
current but he defined ampere in terms
of this force between parallel currents
so how did he define ampere using this
so in the previous slide we saw that the
force experienced by one carry current
carrying conductor due to another
current carrying conductor is equal to
mu knot I a IB divided by 2 PI D into L
this is the force experienced by one
current carrying conductor due to the
other current carrying conductor right
so we can write it as force per unit
length is equal to mu knot I a IB
divided by 2 PI D so how he defined 1
ampere was he said that 1 ampere is the
steady current which when maintained in
each of the two very long straight
parallel conductors of negligible cross
section and placed 1 meter apart in
vacuum would produce on each of these
conductors a force equal to 2 into 10 to
the power minus 7 Newton per meter he
said that one ampere is that amount of
current which if you maintain in two
conductors which are long and have you
negligible cross-sectional area such
that they are placed 1 meters apart in
vacuum the each of these conductor will
experience a force which is equal
two into ten to the power minus 7 Newton
per meter so how did he get this if you
look at this equation F by L if you try
to calculate the value of F by L
considering I current in each of them as
one ampere what do you get and also
considering that the distance between
them is one meter so this will also
become one so you will get this value as
nu naught by 2 pi so that will be equal
to we know that mu naught is equal to 4
PI into 10 to the power minus 7 so this
divided by 2 pi so this will be 2 into
10 to the power minus 7 Newton per meter
so when the current in each of this
conductor is 1 ampere and the distance
between them is 1 meter in that case the
force experienced by each of these
conductors is 2 into 10 to the power
minus 7 Newton per meter so this is how
ampere defined 1 ampere of current after
his observation right thank you please
visit exam few dot-com to watch free
educational videos try 3 online tests
get the best quality study materials
study from the best tutors and mentors
and much more thank you once again
magnetism part 29 is brought to you by
exam feel calm no more fear from exam
please make sure that you have watched
all the videos till part 28 before going
ahead with part 29 the basis of this
concept this observation was of amperes
actually ampere was the one who observed
this parallel and antiparallel currents
attraction and repulsion phenomenon so
ampere was the one so after he was able
to understand the phenomenon behind this
attraction and repulsion of parallel and
antiparallel currents he defined ampere
I mean ampere was any means the unit of
current but he defined ampere in terms
of this force between parallel currents
so how did he define ampere using this
so in the previous slide we saw that the
force experienced by one carry current
carrying conductor due to another
current carrying conductor is equal to
mu knot I a IB divided by 2 PI D into L
this is the force experienced by one
current carrying conductor due to the
other current carrying conductor right
so we can write it as force per unit
length is equal to mu knot I a IB
divided by 2 PI D so how he defined 1
ampere was he said that 1 ampere is the
steady current which when maintained in
each of the two very long straight
parallel conductors of negligible cross
section and placed 1 meter apart in
vacuum would produce on each of these
conductors a force equal to 2 into 10 to
the power minus 7 Newton per meter he
said that one ampere is that amount of
current which if you maintain in two
conductors which are long and have you
negligible cross-sectional area such
that they are placed 1 meters apart in
vacuum the each of these conductor will
experience a force which is equal
two into ten to the power minus 7 Newton
per meter so how did he get this if you
look at this equation F by L if you try
to calculate the value of F by L
considering I current in each of them as
one ampere what do you get and also
considering that the distance between
them is one meter so this will also
become one so you will get this value as
nu naught by 2 pi so that will be equal
to we know that mu naught is equal to 4
PI into 10 to the power minus 7 so this
divided by 2 pi so this will be 2 into
10 to the power minus 7 Newton per meter
so when the current in each of this
conductor is 1 ampere and the distance
between them is 1 meter in that case the
force experienced by each of these
conductors is 2 into 10 to the power
minus 7 Newton per meter so this is how
ampere defined 1 ampere of current after
his observation right thank you please
visit exam few dot-com to watch free
educational videos try 3 online tests
get the best quality study materials
study from the best tutors and mentors
and much more thank you once again
About this Video
Oct 05, 2025
Last updated
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