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Area - General Geometry | Additional Topics for IIT JAM Mathematics PDF Download

Area formula
Area is the amount of space inside a two-dimensional shape. If you think about the floor of your bedroom, the area would be the maximum amount of floor you could throw your stuff on before you couldn't see any floor remaining.
Area is always expressed as square units (units2). This is because it is two-dimensional (length and height).
You can find the area of shapes by counting the boxes inside the shapes. In these three figures, each box represents 1 cm2.
Area - General Geometry | Additional Topics for IIT JAM Mathematics

  • Figure A takes up 25 small boxes, so it has an area of 25 cm2
  • Figure B takes up 36 small boxes, so it has an area of 36 cm2
  • Figure C takes up 21 full boxes and 7 half boxes, so it has an area of Area - General Geometry | Additional Topics for IIT JAM Mathematics

Area of Rectangle = Base x Height
Here is a 10 cm x 6 cm rectangle.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
If we break it into section 1 cm wide, it would look like this:
Area - General Geometry | Additional Topics for IIT JAM Mathematics
Each row contains 10 squares and there are 6 rows, which gives a total of 10 × 6 square cm. That's the same as multiplying the base by the height: 6 x 10 = 60 cm2.
Area of Triangle = ½(Base × Height)
Here is a triangle with a base of 5 cm and a height of 6 cm.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
If we place another triangle with the same height and base on top of this one, we get a 6 cm x 5 cm rectangle.
Area - General Geometry | Additional Topics for IIT JAM Mathematics

Now, we already know how to compute the area of a rectangle (base × height). So, the area of the  rectangle is 5 cm x 6 cm = 30 cm2
However, we only want the triangle, which is half of the rectangle, Area - General Geometry | Additional Topics for IIT JAM Mathematics.  Essentially we took ½ of the area of the whole rectangle, or ½ (base × height).
Area of Parallelogram = Base × Height
Now let's look at a parallelogram with a base of 6 cm and a height of 3 cm.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
By moving the small triangle on the left all the way to the right, this shape becomes a rectangle with a base of 6 and a height of 3 cm.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
Since you already know how to find the area of a rectangle (base × height), you have all the tools you need to find the area of this parallelogram.
Area of Trapezoid = ½(Base1 + Base2) x Height
Area - General Geometry | Additional Topics for IIT JAM Mathematics
Imagine cutting off the triangular lower left corner and fitting it onto the upper right corner like this:
Area - General Geometry | Additional Topics for IIT JAM Mathematics
Now, we just have another rectangle, but with a new base. The base of this new figure is the average of the original bases,Area - General Geometry | Additional Topics for IIT JAM Mathematics The area of this new figure is 6 cm x  3 cm = 18 cm2. Just be careful, because the base we are using is the mean of the two original bases!
Area of Circle = πr2
Finally we will examine the beautiful circle. Here is one with a radius of 6 cm.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
Here is the same circle but with lines drawn in at every cm.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
First we combined the portions of square to make complete square, then we very carefully and diligently counted each and every one of those squares and found there to be approximately 113 squares. This is nearly equal to the Area - General Geometry | Additional Topics for IIT JAM Mathematics

Area Of Irregular Shapes
1. Find the area of this room:
Area - General Geometry | Additional Topics for IIT JAM Mathematics
This can be done in two different ways:

Method #1
Method #2
Divide the figure into two rectangles and find all missing lengths.
Draw two lines to make the figure into one large rectangle.
Area - General Geometry | Additional Topics for IIT JAM MathematicsArea - General Geometry | Additional Topics for IIT JAM Mathematics
The larger rectangle has an area of Area - General Geometry | Additional Topics for IIT JAM Mathematics
The area of the large rectangle is Area - General Geometry | Additional Topics for IIT JAM Mathematics
The smaller rectangle has an area of Area - General Geometry | Additional Topics for IIT JAM MathematicsHowever, a Area - General Geometry | Additional Topics for IIT JAM Mathematics rectangle is not included in our original figure, so we need to take out the area of the white rectangle  Area - General Geometry | Additional Topics for IIT JAM Mathematics
If we combine these we will find the total area: Area - General Geometry | Additional Topics for IIT JAM MathematicsArea - General Geometry | Additional Topics for IIT JAM Mathematics

2. Find the area of this portion of a basketball court:
Area - General Geometry | Additional Topics for IIT JAM Mathematics
This figure is already divided into two shapes: a rectangle and half a circle.
We need to find the area of each and add them together.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
3. A 20 foot x 12 foot pool is to be surrounded by a deck 6 feet in width. How many square feet of decking is needed to do this?

As always, we want to draw a picture of what this looks like.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
The dimensions of the large outside rectangle are:
Area - General Geometry | Additional Topics for IIT JAM Mathematics
So, the area of the larger rectangle is Area - General Geometry | Additional Topics for IIT JAM Mathematics
Area - General Geometry | Additional Topics for IIT JAM Mathematics
The amount of decking we need is : 768 - 240 = 528 square feet!

Surface Area
Surface Area of a Cone = πr2 + πrs
To find the surface area of a cone, we need to find the area of the circular base and the area of the curved section. This one involves a new measurement, s, which is the length of the slanted part.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
If you take apart the cone, you get two surfaces, the circular base, and the curved sides. The area of the base is just πr2, and the area of the curved section is πrs. So, the total surface area of a cone is πr2 +πrs.
Area - General Geometry | Additional Topics for IIT JAM Mathematics
Look Out: surface area is only two-dimensional and is expressed as units squared, not units cubed. This is because we are only dealing with the flat surfaces, not the inside space.

The document Area - General Geometry | Additional Topics for IIT JAM Mathematics is a part of the Mathematics Course Additional Topics for IIT JAM Mathematics.
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FAQs on Area - General Geometry - Additional Topics for IIT JAM Mathematics

1. What is the formula to calculate the area of a rectangle?
Ans. The formula to calculate the area of a rectangle is length multiplied by width. So, Area = length × width.
2. How can I find the area of a triangle?
Ans. To find the area of a triangle, you can use the formula: Area = (base × height) / 2. Here, the base is the length of the triangle's base and the height is the perpendicular distance from the base to the opposite vertex.
3. What is the formula for calculating the area of a circle?
Ans. The formula to calculate the area of a circle is: Area = π × radius^2. Here, π (pi) is a mathematical constant approximately equal to 3.14159, and the radius is the distance from the center of the circle to any point on its circumference.
4. How can I determine the area of a trapezoid?
Ans. To determine the area of a trapezoid, you can use the formula: Area = (base1 + base2) × height / 2. Here, base1 and base2 are the lengths of the parallel sides of the trapezoid, and the height is the perpendicular distance between the parallel sides.
5. What is the formula for finding the area of a square?
Ans. The formula to find the area of a square is: Area = side length × side length. In a square, all sides have equal length, so you can also use the formula: Area = side^2.
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