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Arithmetic Progression & Geometric Progression Video Lecture - CSAT Preparation - UPSC
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FAQs on Arithmetic Progression & Geometric Progression Video Lecture - CSAT Preparation - UPSC
| 1. What is an arithmetic progression? |  |
Ans. An arithmetic progression is a sequence of numbers in which the difference between any two consecutive terms is constant. For example, 2, 5, 8, 11, 14 is an arithmetic progression with a common difference of 3.
| 2. How can I find the nth term of an arithmetic progression? | |
Ans. To find the nth term of an arithmetic progression, you can use the formula: a + (n - 1)d, where 'a' is the first term and 'd' is the common difference. For example, in the sequence 2, 5, 8, 11, 14, the 6th term can be found using the formula as 2 + (6 - 1)3 = 17.
| 3. What is a geometric progression? | |
Ans. A geometric progression is a sequence of numbers in which each term is found by multiplying the previous term by a constant ratio. For example, 2, 6, 18, 54, 162 is a geometric progression with a common ratio of 3.
| 4. How can I find the nth term of a geometric progression? | |
Ans. To find the nth term of a geometric progression, you can use the formula: a * r^(n-1), where 'a' is the first term and 'r' is the common ratio. For example, in the sequence 2, 6, 18, 54, 162, the 6th term can be found using the formula as 2 * 3^(6-1) = 486.
| 5. What is the sum of terms in an arithmetic progression? | |
Ans. The sum of terms in an arithmetic progression can be found using the formula: (n/2)(2a + (n - 1)d), where 'n' is the number of terms, 'a' is the first term, and 'd' is the common difference. For example, the sum of the terms in the arithmetic progression 2, 5, 8, 11, 14 up to the 6th term can be calculated as (6/2)(2*2 + (6-1)3) = 51.
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