C++ Programming Tutorials - Passing Arrays to Functions Video Lecture | Learn to Program with C++: Beginner to Expert - Back-End Programming

Ans. In C programming, you can pass an array to a function by specifying the array name as the argument. This is because arrays are passed by reference in C, meaning that any changes made to the array inside the function will affect the original array. Here's an example: ```c void printArray(int arr[], int size) { for(int i = 0; i < size; i++) { printf("%d ", arr[i]); } } int main() { int myArray[] = {1, 2, 3, 4, 5}; int length = sizeof(myArray) / sizeof(myArray[0]); printArray(myArray, length); return 0; } ``` In this example, the `printArray` function takes an array `arr` and its size `size` as arguments. The function then prints each element of the array.

Ans. Yes, you can modify an array inside a function in C. Since arrays are passed by reference, any changes made to the array inside the function will affect the original array. However, it's important to note that C does not provide any built-in mechanism to return an array from a function.

Ans. In C, you cannot directly return an entire array from a function. However, you can return a pointer to the first element of the array. Here's an example: ```c int* createArray(int size) { int* arr = (int*)malloc(size * sizeof(int)); for(int i = 0; i < size; i++) { arr[i] = i + 1; } return arr; } int main() { int* myArray = createArray(5); for(int i = 0; i < 5; i++) { printf("%d ", myArray[i]); } free(myArray); return 0; } ``` In this example, the `createArray` function dynamically allocates an array of integers using `malloc` and initializes its elements. It then returns the pointer to the first element of the array. In the `main` function, the returned pointer is stored in `myArray` and the elements are printed.

Ans. Yes, you can pass a multi-dimensional array to a function in C. The syntax for passing a multi-dimensional array is similar to passing a one-dimensional array, but you need to specify the size of the second dimension in the function parameter. Here's an example: ```c void printMatrix(int matrix[][3], int rows) { for(int i = 0; i < rows; i++) { for(int j = 0; j < 3; j++) { printf("%d ", matrix[i][j]); } printf("\n"); } } int main() { int myMatrix[][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}; int rows = sizeof(myMatrix) / sizeof(myMatrix[0]); printMatrix(myMatrix, rows); return 0; } ``` In this example, the `printMatrix` function takes a two-dimensional array `matrix` and the number of rows `rows` as arguments. The function then prints each element of the matrix.

Ans. Yes, you can pass an array of strings to a function in C. In C, strings are represented as arrays of characters. To pass an array of strings, you can use a two-dimensional character array. Here's an example: ```c void printStrings(char strings[][20], int size) { for(int i = 0; i < size; i++) { printf("%s\n", strings[i]); } } int main() { char myStrings[][20] = {"Hello", "World", "C", "Programming"}; int length = sizeof(myStrings) / sizeof(myStrings[0]); printStrings(myStrings, length); return 0; } ``` In this example, the `printStrings` function takes a two-dimensional character array `strings` and its size `size` as arguments. The function then prints each string in the array.