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Change of Phase Notes | Study Physics For JEE - JEE

Document Description: Change of Phase for JEE 2022 is part of Physics For JEE preparation. The notes and questions for Change of Phase have been prepared according to the JEE exam syllabus. Information about Change of Phase covers topics like and Change of Phase Example, for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Change of Phase.

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3. Phase change : 

Heat required for the change of phase or state,

Q = mL, L = latent heat.

(a) Latent heat (L) : The heat supplied to a substance which changes its state at constant temperature is called latent heat of the body.

(b) Latent heat of Fusion (Lf) : The heat supplied to a substance which changes it from solid to liquid state at its melting point and 1 atm. pressure is called latent heat of fusion.

(c) Latent heat of vaporisation (Lv) : The heat supplied to a substance which changes it from liquid to vapour state at its boiling point and 1 atm. pressure is called latent heat of vaporization.

If in question latent heat of water are not mentioned and to solve the problem it require to assume that we should consider following values.

Latent heat of ice : L = 80 cal/gm = 80 Kcal/kg = 4200 × 80 J/kg 

Latent heat of steam : L = 540 cal/gm = 540 Kcal/kg = 4200 × 540 J/kg

The given figure, represents the change of state by different lines

Change of Phase Notes | Study Physics For JEE - JEE

Note : If we increases the temperature of liquid (phase) Change of Phase Notes | Study Physics For JEE - JEE ­ but at a later time K .E. stop increasing and the phase of the liquid starts changing.

Ex.5 Find amount of heat released if 100 g ice at - 10°C is converted into 120°C, 100 g steam.

Change of Phase Notes | Study Physics For JEE - JEE

Qnet = 73.5 Kcal.

Ex.6 500 gm of water at 80°C is mixed with 100 gm steam at 120°C. Find out the final mixture. 

Sol. 

120°C steam Change of Phase Notes | Study Physics For JEE - JEE 100°C steam

Req. heat = 100 × Change of Phase Notes | Study Physics For JEE - JEE ×20 = 1 kcal

80°C water Change of Phase Notes | Study Physics For JEE - JEE 100°C water

Req. heat = 500 × 1 × 20 = 10 kcal

100gm steam Change of Phase Notes | Study Physics For JEE - JEE 100 gm water at 100°C

Req. heat = 100 × 540 = 54 kcal

Total heat = 55 kcal.

Remaining heat = 55 - 10 = 45 kcal

Now we have 600 gm water at 100°C ⇒ 4500 = m × 540 ⇒ Change of Phase Notes | Study Physics For JEE - JEE

So at last we have Change of Phase Notes | Study Physics For JEE - JEE gm steam and Change of Phase Notes | Study Physics For JEE - JEE of water

The document Change of Phase Notes | Study Physics For JEE - JEE is a part of the JEE Course Physics For JEE.
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