Page 1 1.1 SOLUTIONS TO CONCEPTS CHAPTER – 1 1. a) Linear momentum : mv = [MLT –1 ] b) Frequency : T 1 = [M 0 L 0 T –1 ] c) Pressure : ] L [ ] MLT [ Area Force 2 2 ? ? = [ML –1 T –2 ] 2. a) Angular speed ? = ?/t = [M 0 L 0 T –1 ] b) Angular acceleration ? = ? ? ? ? T T L M t 2 0 0 [M 0 L 0 T –2 ] c) Torque ? = F r = [MLT –2 ] [L] = [ML 2 T –2 ] d) Moment of inertia = Mr 2 = [M] [L 2 ] = [ML 2 T 0 ] 3. a) Electric field E = F/q = ] I MLT [ ] IT [ MLT 1 3 2 ? ? ? ? b) Magnetic field B = ] I MT [ ] LT ][ IT [ MLT qv F 1 2 1 2 ? ? ? ? ? ? c) Magnetic permeability ? 0 = ] I MLT [ ] I [ ] L [ ] I MT I a 2 B 2 2 1 2 ? ? ? ? ? ? ? ? ? 4. a) Electric dipole moment P = qI = [IT] × [L] = [LTI] b) Magnetic dipole moment M = IA = [I] [L 2 ] [L 2 I] 5. E = h ? where E = energy and ? = frequency. h = ] T ML [ ] T [ ] T ML [ E 1 2 1 2 2 ? ? ? ? ? 6. a) Specific heat capacity = C = ] K T L [ ] K ][ M [ ] T ML [ T m Q 1 2 2 2 2 ? ? ? ? ? ? b) Coefficient of linear expansion = ? = ] K [ ] R ][ L [ ] L [ T L L L 1 0 2 1 ? ? ? ? ? c) Gas constant = R = ] ) mol ( K T ML [ ] K )][ mol [( ] L ][ T ML [ nT PV 1 1 2 2 3 2 1 ? ? ? ? ? ? ? ? 7. Taking force, length and time as fundamental quantity a) Density = ] T FL [ T L F ] L [ ] LT / F [ Volume leration) force/acce ( V m 2 4 2 4 2 2 ? ? ? ? ? ? ? b) Pressure = F/A = F/L 2 = [FL –2 ] c) Momentum = mv (Force / acceleration) × Velocity = [F / LT –2 ] × [LT –1 ] = [FT] d) Energy = 2 2 ) velocity ( on accelerati Force mv 2 1 ? ? = ] FL [ ] T L [ ] LT F ] LT [ LT F 2 2 2 2 1 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 8. g = 2 sec metre 10 = 36 ? 10 5 cm/min 2 9. The average speed of a snail is 0.02 mile/hr Converting to S.I. units, 0.02 1.6 1000 3600 ? ? m/sec [1 mile = 1.6 km = 1600 m] = 0.0089 ms –1 The average speed of leopard = 70 miles/hr In SI units = 70 miles/hour = 70 1.6 1000 3600 ? ? = 31 m/s Page 2 1.1 SOLUTIONS TO CONCEPTS CHAPTER – 1 1. a) Linear momentum : mv = [MLT –1 ] b) Frequency : T 1 = [M 0 L 0 T –1 ] c) Pressure : ] L [ ] MLT [ Area Force 2 2 ? ? = [ML –1 T –2 ] 2. a) Angular speed ? = ?/t = [M 0 L 0 T –1 ] b) Angular acceleration ? = ? ? ? ? T T L M t 2 0 0 [M 0 L 0 T –2 ] c) Torque ? = F r = [MLT –2 ] [L] = [ML 2 T –2 ] d) Moment of inertia = Mr 2 = [M] [L 2 ] = [ML 2 T 0 ] 3. a) Electric field E = F/q = ] I MLT [ ] IT [ MLT 1 3 2 ? ? ? ? b) Magnetic field B = ] I MT [ ] LT ][ IT [ MLT qv F 1 2 1 2 ? ? ? ? ? ? c) Magnetic permeability ? 0 = ] I MLT [ ] I [ ] L [ ] I MT I a 2 B 2 2 1 2 ? ? ? ? ? ? ? ? ? 4. a) Electric dipole moment P = qI = [IT] × [L] = [LTI] b) Magnetic dipole moment M = IA = [I] [L 2 ] [L 2 I] 5. E = h ? where E = energy and ? = frequency. h = ] T ML [ ] T [ ] T ML [ E 1 2 1 2 2 ? ? ? ? ? 6. a) Specific heat capacity = C = ] K T L [ ] K ][ M [ ] T ML [ T m Q 1 2 2 2 2 ? ? ? ? ? ? b) Coefficient of linear expansion = ? = ] K [ ] R ][ L [ ] L [ T L L L 1 0 2 1 ? ? ? ? ? c) Gas constant = R = ] ) mol ( K T ML [ ] K )][ mol [( ] L ][ T ML [ nT PV 1 1 2 2 3 2 1 ? ? ? ? ? ? ? ? 7. Taking force, length and time as fundamental quantity a) Density = ] T FL [ T L F ] L [ ] LT / F [ Volume leration) force/acce ( V m 2 4 2 4 2 2 ? ? ? ? ? ? ? b) Pressure = F/A = F/L 2 = [FL –2 ] c) Momentum = mv (Force / acceleration) × Velocity = [F / LT –2 ] × [LT –1 ] = [FT] d) Energy = 2 2 ) velocity ( on accelerati Force mv 2 1 ? ? = ] FL [ ] T L [ ] LT F ] LT [ LT F 2 2 2 2 1 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 8. g = 2 sec metre 10 = 36 ? 10 5 cm/min 2 9. The average speed of a snail is 0.02 mile/hr Converting to S.I. units, 0.02 1.6 1000 3600 ? ? m/sec [1 mile = 1.6 km = 1600 m] = 0.0089 ms –1 The average speed of leopard = 70 miles/hr In SI units = 70 miles/hour = 70 1.6 1000 3600 ? ? = 31 m/s Chapter-I 1.2 10. Height h = 75 cm, Density of mercury = 13600 kg/m 3 , g = 9.8 ms –2 then Pressure = hfg = 10 ? 10 4 N/m 2 (approximately) In C.G.S. Units, P = 10 × 10 5 dyne/cm 2 11. In S.I. unit 100 watt = 100 Joule/sec In C.G.S. Unit = 10 9 erg/sec 12. 1 micro century = 10 4 × 100 years = 10 –4 ? 365 ? 24 ? 60 min So, 100 min = 10 5 / 52560 = 1.9 microcentury 13. Surface tension of water = 72 dyne/cm In S.I. Unit, 72 dyne/cm = 0.072 N/m 14. K = kI a ? b where k = Kinetic energy of rotating body and k = dimensionless constant Dimensions of left side are, K = [ML 2 T –2 ] Dimensions of right side are, I a = [ML 2 ] a , ? b = [T –1 ] b According to principle of homogeneity of dimension, [ML 2 T –2 ] = [ML 2 T –2 ] [T –1 ] b Equating the dimension of both sides, 2 = 2a and –2 = –b ? a = 1 and b = 2 ? 15. Let energy E ? M a C b where M = Mass, C = speed of light ? E = KM a C b (K = proportionality constant) Dimension of left side E = [ML 2 T –2 ] Dimension of right side M a = [M] a , [C] b = [LT –1 ] b ?[ML 2 T –2 ] = [M] a [LT –1 ] b ? a = 1; b = 2 So, the relation is E = KMC 2 16. Dimensional formulae of R = [ML 2 T –3 I –2 ] Dimensional formulae of V = [ML 2 T 3 I –1 ] Dimensional formulae of I = [I] ?[ML 2 T 3 I –1 ] = [ML 2 T –3 I –2 ] [I] ? V = IR 17. Frequency f = KL a F b M c M = Mass/unit length, L = length, F = tension (force) Dimension of f = [T –1 ] Dimension of right side, L a = [L a ], F b = [MLT –2 ] b , M c = [ML –1 ] c ?[T –1 ] = K[L] a [MLT –2 ] b [ML –1 ] c M 0 L 0 T –1 = KM b+c L a+b–c T –2b Equating the dimensions of both sides, ? b + c = 0 …(1) –c + a + b = 0 …(2) –2b = –1 …(3) Solving the equations we get, a = –1, b = 1/2 and c = –1/2 ? So, frequency f = KL –1 F 1/2 M –1/2 = M F L K M F L K 2 / 1 2 / 1 ? ? ? Page 3 1.1 SOLUTIONS TO CONCEPTS CHAPTER – 1 1. a) Linear momentum : mv = [MLT –1 ] b) Frequency : T 1 = [M 0 L 0 T –1 ] c) Pressure : ] L [ ] MLT [ Area Force 2 2 ? ? = [ML –1 T –2 ] 2. a) Angular speed ? = ?/t = [M 0 L 0 T –1 ] b) Angular acceleration ? = ? ? ? ? T T L M t 2 0 0 [M 0 L 0 T –2 ] c) Torque ? = F r = [MLT –2 ] [L] = [ML 2 T –2 ] d) Moment of inertia = Mr 2 = [M] [L 2 ] = [ML 2 T 0 ] 3. a) Electric field E = F/q = ] I MLT [ ] IT [ MLT 1 3 2 ? ? ? ? b) Magnetic field B = ] I MT [ ] LT ][ IT [ MLT qv F 1 2 1 2 ? ? ? ? ? ? c) Magnetic permeability ? 0 = ] I MLT [ ] I [ ] L [ ] I MT I a 2 B 2 2 1 2 ? ? ? ? ? ? ? ? ? 4. a) Electric dipole moment P = qI = [IT] × [L] = [LTI] b) Magnetic dipole moment M = IA = [I] [L 2 ] [L 2 I] 5. E = h ? where E = energy and ? = frequency. h = ] T ML [ ] T [ ] T ML [ E 1 2 1 2 2 ? ? ? ? ? 6. a) Specific heat capacity = C = ] K T L [ ] K ][ M [ ] T ML [ T m Q 1 2 2 2 2 ? ? ? ? ? ? b) Coefficient of linear expansion = ? = ] K [ ] R ][ L [ ] L [ T L L L 1 0 2 1 ? ? ? ? ? c) Gas constant = R = ] ) mol ( K T ML [ ] K )][ mol [( ] L ][ T ML [ nT PV 1 1 2 2 3 2 1 ? ? ? ? ? ? ? ? 7. Taking force, length and time as fundamental quantity a) Density = ] T FL [ T L F ] L [ ] LT / F [ Volume leration) force/acce ( V m 2 4 2 4 2 2 ? ? ? ? ? ? ? b) Pressure = F/A = F/L 2 = [FL –2 ] c) Momentum = mv (Force / acceleration) × Velocity = [F / LT –2 ] × [LT –1 ] = [FT] d) Energy = 2 2 ) velocity ( on accelerati Force mv 2 1 ? ? = ] FL [ ] T L [ ] LT F ] LT [ LT F 2 2 2 2 1 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 8. g = 2 sec metre 10 = 36 ? 10 5 cm/min 2 9. The average speed of a snail is 0.02 mile/hr Converting to S.I. units, 0.02 1.6 1000 3600 ? ? m/sec [1 mile = 1.6 km = 1600 m] = 0.0089 ms –1 The average speed of leopard = 70 miles/hr In SI units = 70 miles/hour = 70 1.6 1000 3600 ? ? = 31 m/s Chapter-I 1.2 10. Height h = 75 cm, Density of mercury = 13600 kg/m 3 , g = 9.8 ms –2 then Pressure = hfg = 10 ? 10 4 N/m 2 (approximately) In C.G.S. Units, P = 10 × 10 5 dyne/cm 2 11. In S.I. unit 100 watt = 100 Joule/sec In C.G.S. Unit = 10 9 erg/sec 12. 1 micro century = 10 4 × 100 years = 10 –4 ? 365 ? 24 ? 60 min So, 100 min = 10 5 / 52560 = 1.9 microcentury 13. Surface tension of water = 72 dyne/cm In S.I. Unit, 72 dyne/cm = 0.072 N/m 14. K = kI a ? b where k = Kinetic energy of rotating body and k = dimensionless constant Dimensions of left side are, K = [ML 2 T –2 ] Dimensions of right side are, I a = [ML 2 ] a , ? b = [T –1 ] b According to principle of homogeneity of dimension, [ML 2 T –2 ] = [ML 2 T –2 ] [T –1 ] b Equating the dimension of both sides, 2 = 2a and –2 = –b ? a = 1 and b = 2 ? 15. Let energy E ? M a C b where M = Mass, C = speed of light ? E = KM a C b (K = proportionality constant) Dimension of left side E = [ML 2 T –2 ] Dimension of right side M a = [M] a , [C] b = [LT –1 ] b ?[ML 2 T –2 ] = [M] a [LT –1 ] b ? a = 1; b = 2 So, the relation is E = KMC 2 16. Dimensional formulae of R = [ML 2 T –3 I –2 ] Dimensional formulae of V = [ML 2 T 3 I –1 ] Dimensional formulae of I = [I] ?[ML 2 T 3 I –1 ] = [ML 2 T –3 I –2 ] [I] ? V = IR 17. Frequency f = KL a F b M c M = Mass/unit length, L = length, F = tension (force) Dimension of f = [T –1 ] Dimension of right side, L a = [L a ], F b = [MLT –2 ] b , M c = [ML –1 ] c ?[T –1 ] = K[L] a [MLT –2 ] b [ML –1 ] c M 0 L 0 T –1 = KM b+c L a+b–c T –2b Equating the dimensions of both sides, ? b + c = 0 …(1) –c + a + b = 0 …(2) –2b = –1 …(3) Solving the equations we get, a = –1, b = 1/2 and c = –1/2 ? So, frequency f = KL –1 F 1/2 M –1/2 = M F L K M F L K 2 / 1 2 / 1 ? ? ? Chapter-I 1.3 18. a) h = rg SCos 2 ? ? LHS = [L] Surface tension = S = F/I = 2 2 MLT [MT ] L ? ? ? Density = ? = M/V = [ML –3 T 0 ] Radius = r = [L], g = [LT –2 ] RHS = 2 0 1 0 3 0 2 2Scos [MT ] [M L T ] [L] rg [ML T ][L][LT ] ? ? ? ? ? ? ? ? ? LHS = RHS So, the relation is correct b) v = ? p where v = velocity LHS = Dimension of v = [LT –1 ] Dimension of p = F/A = [ML –1 T –2 ] Dimension of ? = m/V = [ML –3 ] RHS = 1 2 2 2 1/ 2 3 p [ML T ] [L T ] [ML ] ? ? ? ? ? ? ? = 1 [LT ] ? So, the relation is correct. c) V = ( ?pr 4 t) / (8 ?l) ? LHS = Dimension of V = [L 3 ] Dimension of p = [ML –1 T –2 ], r 4 = [L 4 ], t = [T] Coefficient of viscosity = [ML –1 T –1 ] RHS = 4 1 2 4 1 1 pr t [ML T ][L ][T] 8 l [ML T ][L] ? ? ? ? ? ? ? So, the relation is correct. d) v = ) I / mgl ( 2 1 ? LHS = dimension of v = [T –1 ] RHS = ) I / mgl ( = 2 2 [M][LT ][L] [ML ] ? = [T –1 ] LHS = RHS So, the relation is correct. 19. Dimension of the left side = 2 2 2 2 dx L (a x ) (L L ) ? ? ? ? ? = [L 0 ] Dimension of the right side = ? ? ? ? ? ? ? x a sin a 1 1 = [L –1 ] So, the dimension of ? ? ) x a ( dx 2 2 ? ? ? ? ? ? ? ? x a sin a 1 1 So, the equation is dimensionally incorrect. Page 4 1.1 SOLUTIONS TO CONCEPTS CHAPTER – 1 1. a) Linear momentum : mv = [MLT –1 ] b) Frequency : T 1 = [M 0 L 0 T –1 ] c) Pressure : ] L [ ] MLT [ Area Force 2 2 ? ? = [ML –1 T –2 ] 2. a) Angular speed ? = ?/t = [M 0 L 0 T –1 ] b) Angular acceleration ? = ? ? ? ? T T L M t 2 0 0 [M 0 L 0 T –2 ] c) Torque ? = F r = [MLT –2 ] [L] = [ML 2 T –2 ] d) Moment of inertia = Mr 2 = [M] [L 2 ] = [ML 2 T 0 ] 3. a) Electric field E = F/q = ] I MLT [ ] IT [ MLT 1 3 2 ? ? ? ? b) Magnetic field B = ] I MT [ ] LT ][ IT [ MLT qv F 1 2 1 2 ? ? ? ? ? ? c) Magnetic permeability ? 0 = ] I MLT [ ] I [ ] L [ ] I MT I a 2 B 2 2 1 2 ? ? ? ? ? ? ? ? ? 4. a) Electric dipole moment P = qI = [IT] × [L] = [LTI] b) Magnetic dipole moment M = IA = [I] [L 2 ] [L 2 I] 5. E = h ? where E = energy and ? = frequency. h = ] T ML [ ] T [ ] T ML [ E 1 2 1 2 2 ? ? ? ? ? 6. a) Specific heat capacity = C = ] K T L [ ] K ][ M [ ] T ML [ T m Q 1 2 2 2 2 ? ? ? ? ? ? b) Coefficient of linear expansion = ? = ] K [ ] R ][ L [ ] L [ T L L L 1 0 2 1 ? ? ? ? ? c) Gas constant = R = ] ) mol ( K T ML [ ] K )][ mol [( ] L ][ T ML [ nT PV 1 1 2 2 3 2 1 ? ? ? ? ? ? ? ? 7. Taking force, length and time as fundamental quantity a) Density = ] T FL [ T L F ] L [ ] LT / F [ Volume leration) force/acce ( V m 2 4 2 4 2 2 ? ? ? ? ? ? ? b) Pressure = F/A = F/L 2 = [FL –2 ] c) Momentum = mv (Force / acceleration) × Velocity = [F / LT –2 ] × [LT –1 ] = [FT] d) Energy = 2 2 ) velocity ( on accelerati Force mv 2 1 ? ? = ] FL [ ] T L [ ] LT F ] LT [ LT F 2 2 2 2 1 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 8. g = 2 sec metre 10 = 36 ? 10 5 cm/min 2 9. The average speed of a snail is 0.02 mile/hr Converting to S.I. units, 0.02 1.6 1000 3600 ? ? m/sec [1 mile = 1.6 km = 1600 m] = 0.0089 ms –1 The average speed of leopard = 70 miles/hr In SI units = 70 miles/hour = 70 1.6 1000 3600 ? ? = 31 m/s Chapter-I 1.2 10. Height h = 75 cm, Density of mercury = 13600 kg/m 3 , g = 9.8 ms –2 then Pressure = hfg = 10 ? 10 4 N/m 2 (approximately) In C.G.S. Units, P = 10 × 10 5 dyne/cm 2 11. In S.I. unit 100 watt = 100 Joule/sec In C.G.S. Unit = 10 9 erg/sec 12. 1 micro century = 10 4 × 100 years = 10 –4 ? 365 ? 24 ? 60 min So, 100 min = 10 5 / 52560 = 1.9 microcentury 13. Surface tension of water = 72 dyne/cm In S.I. Unit, 72 dyne/cm = 0.072 N/m 14. K = kI a ? b where k = Kinetic energy of rotating body and k = dimensionless constant Dimensions of left side are, K = [ML 2 T –2 ] Dimensions of right side are, I a = [ML 2 ] a , ? b = [T –1 ] b According to principle of homogeneity of dimension, [ML 2 T –2 ] = [ML 2 T –2 ] [T –1 ] b Equating the dimension of both sides, 2 = 2a and –2 = –b ? a = 1 and b = 2 ? 15. Let energy E ? M a C b where M = Mass, C = speed of light ? E = KM a C b (K = proportionality constant) Dimension of left side E = [ML 2 T –2 ] Dimension of right side M a = [M] a , [C] b = [LT –1 ] b ?[ML 2 T –2 ] = [M] a [LT –1 ] b ? a = 1; b = 2 So, the relation is E = KMC 2 16. Dimensional formulae of R = [ML 2 T –3 I –2 ] Dimensional formulae of V = [ML 2 T 3 I –1 ] Dimensional formulae of I = [I] ?[ML 2 T 3 I –1 ] = [ML 2 T –3 I –2 ] [I] ? V = IR 17. Frequency f = KL a F b M c M = Mass/unit length, L = length, F = tension (force) Dimension of f = [T –1 ] Dimension of right side, L a = [L a ], F b = [MLT –2 ] b , M c = [ML –1 ] c ?[T –1 ] = K[L] a [MLT –2 ] b [ML –1 ] c M 0 L 0 T –1 = KM b+c L a+b–c T –2b Equating the dimensions of both sides, ? b + c = 0 …(1) –c + a + b = 0 …(2) –2b = –1 …(3) Solving the equations we get, a = –1, b = 1/2 and c = –1/2 ? So, frequency f = KL –1 F 1/2 M –1/2 = M F L K M F L K 2 / 1 2 / 1 ? ? ? Chapter-I 1.3 18. a) h = rg SCos 2 ? ? LHS = [L] Surface tension = S = F/I = 2 2 MLT [MT ] L ? ? ? Density = ? = M/V = [ML –3 T 0 ] Radius = r = [L], g = [LT –2 ] RHS = 2 0 1 0 3 0 2 2Scos [MT ] [M L T ] [L] rg [ML T ][L][LT ] ? ? ? ? ? ? ? ? ? LHS = RHS So, the relation is correct b) v = ? p where v = velocity LHS = Dimension of v = [LT –1 ] Dimension of p = F/A = [ML –1 T –2 ] Dimension of ? = m/V = [ML –3 ] RHS = 1 2 2 2 1/ 2 3 p [ML T ] [L T ] [ML ] ? ? ? ? ? ? ? = 1 [LT ] ? So, the relation is correct. c) V = ( ?pr 4 t) / (8 ?l) ? LHS = Dimension of V = [L 3 ] Dimension of p = [ML –1 T –2 ], r 4 = [L 4 ], t = [T] Coefficient of viscosity = [ML –1 T –1 ] RHS = 4 1 2 4 1 1 pr t [ML T ][L ][T] 8 l [ML T ][L] ? ? ? ? ? ? ? So, the relation is correct. d) v = ) I / mgl ( 2 1 ? LHS = dimension of v = [T –1 ] RHS = ) I / mgl ( = 2 2 [M][LT ][L] [ML ] ? = [T –1 ] LHS = RHS So, the relation is correct. 19. Dimension of the left side = 2 2 2 2 dx L (a x ) (L L ) ? ? ? ? ? = [L 0 ] Dimension of the right side = ? ? ? ? ? ? ? x a sin a 1 1 = [L –1 ] So, the dimension of ? ? ) x a ( dx 2 2 ? ? ? ? ? ? ? ? x a sin a 1 1 So, the equation is dimensionally incorrect. Chapter-I 1.4 20. Important Dimensions and Units : Physical quantity Dimension SI unit Force (F) ] T L M [ 2 1 1 ? newton Work (W) ] T L M [ 2 2 1 ? joule Power (P) ] T L M [ 3 2 1 ? watt Gravitational constant (G) ] T L M [ 2 3 1 ? ? N-m 2 /kg 2 Angular velocity ( ?) ? ] T [ 1 ? radian/s Angular momentum (L) ] T L M [ 1 2 1 ? kg-m 2 /s Moment of inertia (I) ] L M [ 2 1 kg-m 2 Torque ( ?) ? ] T L M [ 2 2 1 ? N-m Young’s modulus (Y) ] T L M [ 2 1 1 ? ? N/m 2 Surface Tension (S) ] T M [ 2 1 ? N/m Coefficient of viscosity ( ?) ? ] T L M [ 1 1 1 ? ? N-s/m 2 Pressure (p) ] T L M [ 2 1 1 ? ? N/m 2 (Pascal) Intensity of wave (I) ] T M [ 3 1 ? watt/m 2 Specific heat capacity (c) ] K T L [ 1 2 2 ? ? J/kg-K Stefan’s constant ( ?) ? ] K T M [ 4 3 1 ? ? watt/m 2 -k 4 Thermal conductivity (k) ] K T L M [ 1 3 1 1 ? ? watt/m-K Current density (j) ] L I [ 2 1 ? ampere/m 2 Electrical conductivity ( ?) ? ] L M T I [ 3 1 3 2 ? ? ? –1 m –1 ? Electric dipole moment (p) ] T I L [ 1 1 1 C-m Electric field (E) ] T I L M [ 3 1 1 1 ? ? V/m Electrical potential (V) ] T I L M [ 3 1 2 1 ? ? volt Electric flux ( ?) ? ] L I T M [ 3 1 3 1 ? ? volt/m Capacitance (C) ] L M T I [ 2 1 4 2 ? ? farad (F) Permittivity ( ?) ? ] L M T I [ 3 1 4 2 ? ? C 2 /N-m 2 Permeability ( ?) ? ] T I L M [ 3 2 1 1 ? ? Newton/A 2 Magnetic dipole moment (M) ] L I [ 2 1 N-m/T Magnetic flux ( ?) ? ] T I L M [ 2 1 2 1 ? ? Weber (Wb) Magnetic field (B) ] T I M [ 2 1 1 ? ? tesla Inductance (L) ] T I L M [ 2 2 2 1 ? ? henry Resistance (R) ] T I L M [ 3 2 2 1 ? ? ohm ( ?) ? * * * *Read More

Offer running on EduRev: __Apply code STAYHOME200__ to get INR 200 off on our premium plan EduRev Infinity!

129 videos|226 docs|151 tests

- Chapter 2 : Physics and Mathematics - HC Verma Solution, Physics
- Chapter 3 : Rest and Motion Kinematics - HC Verma Solution, Physics
- Chapter 4: The Forces - HC Verma Solution, Physics
- Chapter 5 : Newton's Laws of Motion - HC Verma Solution, Physics
- Chapter 6 : Friction - HC Verma Solution, Physics
- Chapter 7 : Circular Motion - HC Verma Solution, Physics