Impulse of Jets Civil Engineering (CE) Notes | EduRev

Fluid Mechanics

Civil Engineering (CE) : Impulse of Jets Civil Engineering (CE) Notes | EduRev

The document Impulse of Jets Civil Engineering (CE) Notes | EduRev is a part of the Civil Engineering (CE) Course Fluid Mechanics.
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Chapter 14
IMPULSE OF JETS
-Jet Strikes normal to the flat stationary plate

Impulse of Jets Civil Engineering (CE) Notes | EduRev

Force exerted by the jet normal to the plate
Fn = ρaV2
a = area of jet
V = velocity of jet
ρ= density of water

-Jet strikes on a inclined stationary plate

Impulse of Jets Civil Engineering (CE) Notes | EduRev

Force exerted by the jet normal to the plate
  Fn = ρaV2.sinθ
Impulse of Jets Civil Engineering (CE) Notes | EduRev

-Force exerted by jet on moving flat plate normal to jet

Impulse of Jets Civil Engineering (CE) Notes | EduRev

u = plate velocity, v= jet velocity
F= ρa(V – u)2
Work done per second (W) = Fn × u = ρa[V – u]2 × u

-Jet strikes on series of flat plat mounted on the peripehry of wheel

Impulse of Jets Civil Engineering (CE) Notes | EduRev

Fn = ρaV(V – u)
Work done by the jet = Fn × U
W = ρaV(V – u)u
Efficiency of the work done of wheel=Impulse of Jets Civil Engineering (CE) Notes | EduRev
At, u = V/2 ; ηmax = 50%

-Jet striking on a symmetrical stationary curved plate

Impulse of Jets Civil Engineering (CE) Notes | EduRev


Fn = ρaV2 (1 + cosθ)

Force exerted by a jet in its direction of flow on a curved vane is always greater than that exerted on a flat plate.

-Force Exerted By a jet on a Hinged Plate

     Impulse of Jets Civil Engineering (CE) Notes | EduRev
-Force due to jet of water, normal to the plate

    Pn = ρaV2 sin (90º –θ)
-For equilibrium of plate

sinθ=ρav2/W
W= weight of the plate

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