Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev

Civil Engineering SSC JE (Technical)

Civil Engineering (CE) : Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev

The document Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev is a part of the Civil Engineering (CE) Course Civil Engineering SSC JE (Technical).
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Chapter 4 
SEWAGE AND SEWAGE TREATMENT, QUANTITY AND CHARACTERISTICS OF WASTE WATER
SULLAGE:
This refers to the waste water generated from bathrooms, kitchens, washing place and wash basins etc.
Composition of this waste does not involve higher concentration of organic matter and it is less polluted water as compared to sewerage.

SEWAGE:
It indicates the liquid waste originating from the domestic uses of water. It includes Sullage, discharge  from toilets, urinals,  waste  water  generated  from  commercial establishments, institutions, industrial establishments and also the ground water, storm water that may enter into the sewers. Its decomposition produces large quantities of malodorous gases and it contains numerous pathogenic bacteria, along with concentration of organic matter and suspended solids.

Domestic sewage: Consists of liquid wastes originating from urinals, bathrooms, kitchen sinks, wash basins etc.This sewage is generally extremely foul,because of the presence of human excreta.
Industrial sewage: Liquid wastes originating from industrial processes of various industries like dying, paper making,brewing etc.

Aerobic decomposition: If air or oxygen is available freely to waste water in dissolved form ,then the biodegradable organic matter will undergo aerobic decomposition, caused by aerobic bacteria as well as by facultative bacteria. This bacteria will then utilizes the free oxygen as electron acceptor, thereby oxidizing the organic matter to stable and unobjectionable end products.The stable end products like nitrates,carbon dioxide,sulphates are formed.

-Nitrogenous organic matter on oxidation gives NO3- + NH3  + Energy
-Carbonaceous organic matter on oxidation gives CO2  + H2O + Energy
-Sulphurous organic matter on oxidation gives SO4--  + Energy

Anaerobic decomposition: If free dissolved oxygen is not available to the sewage, then anaerobic  decomposition,  called putrefaction will  occur.  Anaerobic  bacteria  as well  as facultative  bacteria  operating  anaerobically will  then  flourish and  convert  the  complex organic matter into simpler organic compounds of nitrogen, carbon and sulphur.
Nitrogenous organic matter on reduction gives N2 + NH3 + Organics Acids + Energy
Carbonaceous organic matter on reduction gives CO2 + Energy
Sulphurous organic matter on reduction gives H2S + Energy

Aerobic bacteria: Flourish in presence of free dissolved oxygen in wastewater and consume organic matter for their food and thereby oxidizing it to stable end products.
Anaerobic bacteria: Flourish in absence of oxygen
Facultative bacteria: Can operate either as aerobically or as anaerobically.

Characteristics of sewage:
1. Physical characteristics:
a) Turbidity: Sewage is normally turbid,resembling dirty dish water.It is Measured by turbidity rod or turbidity meter.
b) Colour: If the colour is yellowish,grey or light brown,it indicates fresh sewage.However,if the colour is black or dark brown,it indicates stale sewage.
c) Odour: Measured as Thresold odour number (TON), which represents the extent of dilution required to just make the sample free of odour.
d) Temperature: It has an effect on the biological activity of bacteria present in sewage and it also affects the solubility of gases in sewage.The normal temperature of the sewage is generally higher than the temperature of water,because of additional heat added during the utilisation of water.

2. Chemical characteristics: 
a) Total solids, suspended solids, Settleable solids, dissolved solids.
Total solids: Determined by evaporating a known volume of sewage sample and weighing the dry residue left.The mass of the residue divided by the volume of the sample evaporated,will represent the total solids in mg/L.
Suspended solids: Those solids which are retained by a filter of 1 um pores .
Dissolved solids: Total - suspended.
Total Suspended solids= Volatile solids + Fixed solids.
Loss of weight due to burning of suspended solids is called volatile solids and residue is called fixed solids.

b) Settleable solids: Can be determined by Imhoff cone. The capacity of the cone is 1 litre and it is graduated up to about 50ml. Sewage is allowed to stand in this cone for a period of 2 hours and the quantity of solids settled at the bottom of the cone can then directly be read out.

c) Ph  value:  It is an indicator of the alkalinity of the sewage.The lesser is the Ph value,lesser is the alkalinity.It's determination is important because of the fact that efficiency of certain treatment methods depends upon the availability of a suitable Ph value.

d) Chloride content: The Normal chloride content of sewage is 120. Higher values indicate mixing of industrial wastes.
The chloride content can be measured by titrating the waste water with standard silver nitrate solution,using potassium chromate as indicator.

e) Nitrogen content: The presence of Nitrogen in sewage indicates the presence of organic matter and may occur in one or more of the following forms:
1. Free ammonia
2. Organic nitrogen or Albuminioid nitrogen
3. Nitrites
4. Nitrates.
The sum total of free ammonia and organic nitrogen is called as Kjeldahl nitrogen.Free ammonia indicates quantity of nitrogen present in sewage before the decomposition of organic matter is started. The nitrites indicate the presence of partly decomposed organic matter. Nitrates indicate the presence of fully oxidized organic matter. In drinking water nitrates should be less than 45mg/ . Excess of nitrates causes blue baby or methaemoglobinemia disease in children.

f) Presence  of  fats,  oils  and  greases:  It  interferes  with  treatment  process  like filtration so needs to be removed.

g) Sulphides, sulphates & H2S gas: Cause smell and corrosion of concrete sewer lines

h) Dissolved oxygen: (DO): The DO content of sewage is determined by Winkler ’s method. While discharging into streams, DO in sewage must be more than 4ppm to protect fish.If the temperature of the sewage is more,DO content will be less.

i) Chemical oxygen demand: Oxygen required to completely oxidize the organic matter to CO2,H2O and other oxidised species.

j) Total organic carbon: Another important method of expressing organic matter is in terms of its carbon content.Known concentrations of chemical components in waste water will enable us to calculate carbon content present in sewage.

Bio chemical oxygen demand (BOD): The amount of oxygen required to decompose the organic matter present in sewage is called BOD.
The BOD of water during 5 days at 20º C is generally taken as the standard demand and is about 68% of the total demand.
BOD5 : BOD during 5 days at 20º C
BOD5 = D.O consumed by diluted sample ×Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev
=D.O Consumed × dilution factor
Lt = L at t = 0

Lt =  Amount of organic matter Present at time t

L = Ultimate BOD(BODu)

Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev

Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev∝Lt
Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev

Integrating both sides,we get

Loge Lt = – Kt + C

At t = 0, Lt = L C = log L

log Lt = log L – Kt

Loge Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev = - Kt
Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev
Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev

where Kd = K/2.3

BOD at time t = L - Lt = Yt = L – L* 10– Kdt

Yt = L [1 – 10- Kd t ]       KD = De–oxygenation constant


The value of Kd  changes with temperature and this relationship is approximately given by the equation
Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev
Population equivalent :
Industrial wastewaters are generally compared with per capita normal domestic wastewaters,so as to rationally charge the industries for the pollution caused by them.Thus,it indicates the strength of the industrial wastewater for estimating the treatment required at the municipal sewage treatment plant.

Sewage And Sewage Treatment Civil Engineering (CE) Notes | EduRev

Relative stability :
It is the ratio of of oxygen available in effluent to the total oxygen required to satisfy its first stage BOD demand.

S = 100[1-(0.794)t20]
Or S=100[1-(0.630)t37]
where S= The relative stability,t20 and t37 represent the time in days for a sewage sample to decolourise a standard volume of methylene blue solution,when incubated at 20 degree celsius or 37 degree celsius respectively.


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