Class 8 Exam  >  Class 8 Notes  >  Mathematics Class 8 ICSE  >  Chapter Notes: Volume and Capacity

Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE PDF Download

Introduction

This chapter introduces the concepts of volume, capacity, and surface area for three-dimensional shapes like cuboids, cubes, and cylinders. Volume refers to the space occupied by a solid, capacity is the internal volume of a container, and surface area is the total area of all faces of a solid. The following notes provide a clear, step-by-step explanation of each concept, accompanied by examples and practical applications that illustrate the calculations.
Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE

Key Points

  • Volume is the measure of how much space an object occupies. It is usually measured in cubic units, such as cubic meters (m³), cubic centimeters (cm³), or liters (L). The formula to calculate the volume of a cuboid is:
    Volume of a Cuboid = Length × Breadth × Height
  • Capacity refers to the maximum amount of space that a container can hold. It is often measured in litres or gallons. For example, a water tank with a capacity of 1000 litres can hold 1000 litres of water. The capacity of a cuboid can be calculated using the same formula as volume, since it refers to the space inside the container.
  • Surface area is the total area of all the surfaces of a three-dimensional object. It is measured in square units, such as square meters (m²) or square centimetres (cm²). The formula to calculate the surface area of a cuboid is:
    Surface Area of a Cuboid = 2 × (Length × Breadth + Length × Height + Breadth × Height)

Units of measurement:

  • Length: metre (m), centimetre (cm), millimetre (mm).
  • Volume: cubic metre (m³), cubic centimetre (cm³), cubic millimetre (mm³).
  • Surface area: square metre (m²), square centimetre (cm²), square millimetre (mm²).

Conversion between units:

  • 1 m³ = 1,000,000 cm³ (100 × 100 × 100 cm³).
  • 1 cm³ = 1/1,000,000 m³.
  • 1 cm³ = 1,000 mm³ (10 × 10 × 10 mm³).
  • 1 mm³ = 1/1,000 cm³.

Volume of liquids or gases is measured in litres:

  • 1 m³ = 1,000 litres.
  • 1 litre = 1,000 cm³ (also called millilitres or c.c.).

Example: Understand that if a container has a capacity of 1 litre, its internal volume is 1,000 cm³.

Cuboid (A Rectangular Solid)

Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE

A cuboid is a solid shape with six rectangular faces.

Key measurements

  • Volume: The volume of a cuboid is calculated by multiplying its length, breadth, and height. The formula is: Volume = Length × Breadth × Height (l × b × h).
  • Total Surface Area: The total surface area of a cuboid is found by using the formula: Total Surface Area = 2(l × b + b × h + h × l).

Area of Faces

  • Area of Top and Bottom Faces: The area of the top and bottom faces is calculated as 2(l × b).
  • Area of Front and Back Faces: The area of the front and back faces is calculated as 2(b × h).
  • Area of Left and Right Faces: The area of the left and right faces is calculated as 2(h × l).

Steps to calculate Volume

Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE

  • To calculate the volume of a cuboid, measure the length, breadth, and height in the same unit.
  • Multiply these three dimensions together: Volume = Length × Breadth × Height.
  • Express the result in cubic units, such as cm³ or m³.

Steps to Calculate the Total Surface Area

  • Measure the length, breadth, and height of the cuboid in the same unit.
  • Calculate the following products: Length × Breadth, Breadth × Height, and Height × Length.
  • Add these three products together and multiply the sum by 2. 
    Total Surface Area = 2 × (Length × Breadth + Breadth × Height + Height × Length).
  • Express the result in square units, such as cm² or m².

Example: A cuboid has length, breadth, and height in the ratio 6:5:4, with a volume of 15,000 cm³.

Steps to find dimensions:

  • Let length = 6x cm, breadth = 5x cm, height = 4x cm.
  • Volume = 6x × 5x × 4x = 15,000 cm³.
  • Simplify: 120x³ = 15,000 → x³ = 15,000/120 = 125.
  • Find x: x = ∛125 = 5.
  • Dimensions: length = 6 × 5 = 30 cm, breadth = 5 × 5 = 25 cm, height = 4 × 5 = 20 cm.

Steps to find surface area:

  • Use formula: 2(l × b + b × h + h × l).
  • Substitute: 2(30 × 25 + 25 × 20 + 20 × 30) = 2(750 + 500 + 600) = 2 × 1850 = 3,700 cm².

Cube

Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE

A cube is a special kind of cuboid where all the faces are squares, meaning the length, breadth, and height are all the same. Let's say the edge of the cube is a.

  • Volume = a × a × a = a³ ( edge³ ).
  • Total surface area = 6 × (edge)² = 6a² (since each face is a square).

Steps to calculate Volume

  • Measure the edge length ( a ).
  • Calculate the volume by finding a³.
  • Express the result in cubic units.

Steps to calculate the Total Surface Area

  • Measure the edge length (a).
  • Calculate a² for one face.
  • Multiply by 6 (since a cube has 6 faces).
  • Express the result in square units.

Example:

  • A cube has a total surface area of 294 cm². Find its volume.
  • Steps:
    1. Total surface area = 6a² = 294 cm².
    2. Find a²: a² = 294/6 = 49.
    3. Find a: a = √49 = 7 cm.
    4. Volume = a³ = 7³ = 343 cm³.

Application

Application 1: For a Room

  • A room has four walls: two along its length and two along its width.
  • Area calculations:
    1. Area of each wall along length = length × height (l × h).
    2. Area of each wall along width = breadth × height (b × h).
    3. Total area of four walls = 2(l × h) + 2(b × h) = 2(l + b) × h.
    4. This includes the area of doors and windows.
    5. Area of roof = area of floor = length × breadth (l × b).
  • Steps to calculate the area to be whitewashed:
    1. Calculate the area of four walls: 2(l + b) × h.
    2. Calculate the area of the roof: l × b.
    3. Subtract the area of doors and windows if they are not to be whitewashed.
    4. Add the remaining areas to get the total area to be whitewashed.

Example: A room has internal dimensions 6 m (length), 5.2 m (breadth), 4.5 m (height), with two doors (1.2 m × 2 m) and three windows (1 m × 0.8 m). Find the area to be whitewashed and cost at ₹6 per m².
Steps:

  • Area of four walls = 2(6 + 5.2) × 4.5 = 2 × 11.2 × 4.5 = 100.8 m².
  • Area of roof = 6 × 5.2 = 31.2 m².
  • Area of two doors = 2 × (1.2 × 2) = 4.8 m².
  • Area of three windows = 3 × (1 × 0.8) = 2.4 m².
  • Total area to whitewash = (100.8 + 31.2) - (4.8 + 2.4) = 124.8 m².
  • Cost = 124.8 × 6 = ₹748.80.

Application 2: For a Box

Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE

  • Space occupied = external volume.
  • Capacity = internal volume.
  • Volume of material = external volume - internal volume.
  • For a closed box with external dimensions l, b, h and wall thickness t:
    1. Internal length = l - 2t.
    2. Internal breadth = b - 2t.
    3. Internal height = h - 2t.
  • If internal dimensions are l, b, h, and thickness is t:
    1. External length = l + 2t.
    2. External breadth = b + 2t.
    3. External height = h + 2t.
  • Steps to calculate capacity:
    1. Find internal dimensions by subtracting twice the thickness from external dimensions.
    2. Calculate the internal volume: length × breadth × height
  • Steps to calculate the volume of material:
    1. Calculate external volume: l × b × h.
    2. Calculate internal volume: (l - 2t) × (b - 2t) × (h - 2t).
    3. Subtract internal volume from external volume.

Example: A closed wooden box has external dimensions 30 cm, 18 cm, 20 cm, with walls 1.5 cm thick. Find capacity, volume of wood, and weight if 1 cm³ of wood weighs 0.8 g.
Steps:

  • External volume = 30 × 18 × 20 = 10,800 cm³.
  • Internal dimensions: length = 30 - 2 × 1.5 = 27 cm, breadth = 18 - 2 × 1.5 = 15 cm, height = 20 - 2 × 1.5 = 17 cm.
  • Capacity (internal volume) = 27 × 15 × 17 = 6,885 cm³.
  • Volume of wood = 10,800 - 6,885 = 3,915 cm³.
  • Weight = 3,915 × 0.8 = 3,132 g = 3.132 kg.

Cylinder

Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE

A cylinder is a solid with a uniform circular cross-section. Let the radius of the base = r cm, height = h cm.

Key measurements

  • Area of cross-section = πr².
  • Perimeter of cross-section = 2πr.
  • Curved surface area = perimeter × height = 2πrh.
  • Total surface area = curved surface area + 2 × area of cross-section = 2πrh + 2πr² = 2πr(h + r).
  • Volume = area of cross-section × height = πr²h.
  • Use π = 22/7 unless specified otherwise.

Steps to calculate Curved Surface Area

  • Measure radius (r) and height (h).
  • Calculate 2πrh.
  • Express in square units.

Steps to calculate the Total Surface Area

  • Calculate curved surface area: 2πrh.
  • Calculate the area of two bases: 2 × πr².
  • Add both: 2πr(h + r).
  • Express in square units.

Steps to calculate Volume

  • Measure radius (r) and height (h).
  • Calculate πr²h.
  • Express in cubic units.

Example:

  • A cylinder has a curved surface area of 17,600 cm² and a base circumference of 220 cm. Find height and volume.
  • Steps:
    • Curved surface area = 2πrh = 17,600 cm², circumference = 2πr = 220 cm.
    • Find height: h = 17,600 / 220 = 80 cm.
    • Find radius: 2πr = 220 → 2 × 22/7 × r = 220 → r = (220 × 7) / (2 × 22) = 35 cm.
    • Volume = πr²h = 22/7 × 35 × 35 × 80 = 308,000 cm³.
The document Volume and Capacity Chapter Notes | Mathematics Class 8 ICSE is a part of the Class 8 Course Mathematics Class 8 ICSE.
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FAQs on Volume and Capacity Chapter Notes - Mathematics Class 8 ICSE

1. What is the difference between a cuboid and a cube?
Ans. A cuboid is a three-dimensional shape with six rectangular faces, while a cube is a special type of cuboid where all six faces are squares and have equal dimensions. In simpler terms, all sides of a cube are the same length, whereas a cuboid can have different lengths, widths, and heights.
2. How do you calculate the volume of a cuboid?
Ans. The volume of a cuboid can be calculated using the formula: Volume = Length × Width × Height. This formula multiplies the three dimensions of the cuboid to find out how much space it occupies.
3. What is the volume formula for a cube?
Ans. The volume of a cube is calculated using the formula: Volume = Side × Side × Side (or Volume = Side³). Since all sides of a cube are equal, you can simply multiply the length of one side by itself two more times to find the total volume.
4. In what real-life situations do we encounter cylinders, and how do we calculate their volume?
Ans. Cylinders are commonly found in everyday objects like cans, pipes, and tubes. The volume of a cylinder can be calculated using the formula: Volume = π × Radius² × Height. This formula helps determine the amount of space inside the cylinder based on its radius and height.
5. How can we apply the concepts of volume and capacity in daily life?
Ans. Understanding volume and capacity is essential for various real-life applications, such as cooking (measuring ingredients), packaging (determining how much a container can hold), and construction (calculating the space needed for materials). It helps in making informed decisions in practical tasks.
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