➤ First Ionization Energy
➤ Second ionization energy
Many compounds of transition elements are coloured in contrasts to those of s and p block elements.In compound state due to the surrounding groups (ligands), the d-orbitals of transition elements are not degenerate but split into two groups of different energy.
Thus it is possible to promote electrons from one group to another group. This corresponds to fairly small amount of energy difference and so light is absorbed in visible region. Some compounds of transition metals are white, for example ZnSO4 and TiO2. In these compounds it is not possible to promote the electrons within the d-level.
Alloys are homogenous solid solutions of two or more metals obtained by melting the components and then cooling the melt. These are formed by metals whose atomic radii differ by not more than 15% so that the atoms of one metal can easily take up the positions in the crystal lattice of the other. Since transition metals have similar atomic radii, they form alloys very readily.
They show variable oxidation states unlike s and p block elements. The oxidation states changes in units of one, e.g. Fe2+ and Fe+3, Cu+1 and Cu+2.
Scandium can have an oxidation number of (+II) if both s electrons are used for bonding and (+III) when two s and one d electrons are involved. Similarly all the elements show variable oxidation states depending upon the number of electrons available for bonding in their s and d sub-shells.
Many transition metals and their compounds have catalytic properties. For e.g. V2O5, Fe, FeCl3, Ni, Pd etc. This is due to following reasons
The transition elements have an unparalleled tendency to form coordination compounds with the Lewis bases, which are called as ligands.
CO3+ + 6NH3 → [CO(NH3)6]3+
Fe2+ + 6CN– → [Fe(CN)6]4–
s and p block elements form very few complexes. The reason transition elements are so good at forming complex is that they have small, highly charged ions and have vacant low energy orbitals to accept lone pairs of electrons donated by ligands.
Transition elements show variable oxidation states unlike s and p block elements. The oxidation states changes in units of one, e.g. Fe2+ and Fe+3, Cu+1 and Cu+2.
Scandium can have an oxidation number of (+II) if both s electrons are used for bonding and (+III) when two s and one d electrons are involved. Similarly all the elements show variable oxidation states depending upon the number of electrons available for bonding in their s and d sub-shells.
Transition metals have unique property to show variable oxidation state. This property arises from the fact that the energy levels of 3d, 4d and 5d orbitals are very close to those of 4s, 5s and 6s orbitals respectively and, therefore, electrons from both ns and (n-1)d orbitals can be used, infect they are used, for the formation and bonds by transition metals.
➤ Minimum oxidation state: All the transition elements except Cr, Cu, Ag, Au and Hg which have a minimum oxidation state of +1 exhibit a minimum oxidation state of +2.
➤ Maximum oxidation state: Each of the elements in groups III B to VII B can show the maximum oxidation state equal to its group number. For example, Cr in group VIB shows a maximum oxidation state of +6 in Cr2O72– ion.
Most of the elements in VIII group show a maximum oxidation state equal to + 6. However, Ru and Os have a maximum oxidation state equal to +8 which is the highest oxidation state shown by any element.
➤ Relative stability of various oxidation states:
On the basis of behaviour in a magnetic field, substance are classified as paramagnetic, diamagnetic and ferromagnetic. Those substance which are attracted by the applied magnetic field are called paramagnetic where as those which are repelled by the magnetic field are called diamagnetic. Substances which are very strongly attracted by the applied field are called ferromagnetic.
Paramagnetism is a property due to the presence of unpaired electrons. Thus most of the transition metals are paramagnetic. As the number of unpaired electrons increases, the paramagnetic character also increases.
The magnetic moment is calculated from the following formula μ = √n(n+2) BM where n is the number of unpaired electrons and B. M stands for Bohr magneton.
Because of small size of their atoms and strong metallic bonding the density and hardness of transition elements are high.? Except for mercury, which is a liquid at room temperature all other elements are solid metals exhibiting all the characteristics of a metal.
Question 1: K2PtCl6 is a well known compound whereas corresponding Ni compound is not known. State a reason for it.
Solution: This is because Pt4+ is more stable than Ni4+ has the sum of four ionization energies of Pt is less than that of Ni.
Question 2: Why do transition elements show variable oxidation states?
Solution: In the transition elements, the energies of (n-1)d orbitals and ns orbitals are very close. Hence electrons from both can participate in bonding.
Question 3: Explain briefly how +2 state becomes more and more stable in the first half of the first row transition elements with increasing atomic number.
or
Compare the stability of +2 oxidation state of the elements of the first transition series.
Solution: The sum IE1 + IE2 increases. As a result the standard reduction potentials (E0) becomes less and less negative. Hence the tendency to form M2+ ion decreases. The greater stability of +2 state for Mn is due to half-filled d-subshell (d5), that for zinc is due to completely filled d-subshell (d10) and half that for nickel is due to highest negative enthalpy of hydration.
Question 4: Why Zn2+ salts are white while Ni2+ salts are blue?
Solution: Zn2+ has completely filled d-orbitals (3d10) while Ni2+ has incompletely filled d-orbitals (3d8).
Question 5: Why Zn2+ salts are white while Cu2+ salts are blue?
Solution: Reason same as above.
Question 6: Giving reasons indicate which one of the following would be coloured?
Cu+, VO2+, Sc3+, Ni2+ (At. Nos Cu = 29, V = 23, Sc = 21, Ni = 28)
Solution: Ni2+ due to incompletely filled d-orbitals.
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