Class 5 Maths - Mapping your Way - CBSE Worksheets Solutions - 1

Q1: Multiple Choice Questions:

(a) 250 km
(b) 450 km
(c) 350 km
(d) 150 km

Ans:  To calculate the distance between Jaunpur and Chapra, we followed these steps:

• Grid Measurement: The map is divided into 1 cm grid squares, and the scale tells us that each 1 cm on the map equals 50 kilometers on the ground.
• Estimate the Distance: By counting the number of grid squares between Jaunpur and Chapra, the distance is estimated to be around 5 cm.
• Convert to Real Distance: Since each centimeter on the map represents 50 kilometers, we multiply the 5 cm by 50 kilometers:

                           5 cm × 50 km/cm = 250 km

Therefore, the approximate distance between Jaunpur and Chapra is 250 km.

(ii) There is a pentagon drawn on a 1 cm square grid. If Mohan is asked to draw the same picture on a 2cm grid. The side of the square is made two times bigger. Does the area of square grids also become two times bigger?

(a) Yes, becomes two times bigger

(b) No, it becomes 4 times bigger 

(c) No, it becomes three times bigger

(d) No, it remains the same

Ans: The area of a square is calculated using the formula: Area = side × side.

1. Original Grid (1 cm):

   • Area = $1\hspace{0.17em}cm\times 1\hspace{0.17em}cm=1\hspace{0.17em}square cm1\; \backslash ,\; \backslash text\{cm\}\; \backslash times\; 1\; \backslash ,\; \backslash text\{cm\}\; =\; 1\; \backslash ,\; \backslash text\{square\; cm\}$1cm×1cm=1 square cm

2. New Grid (2 cm):

   • Area = $2\hspace{0.17em}cm\times 2\hspace{0.17em}cm=4\hspace{0.17em}square cm2\; \backslash ,\; \backslash text\{cm\}\; \backslash times\; 2\; \backslash ,\; \backslash text\{cm\}\; =\; 4\; \backslash ,\; \backslash text\{square\; cm\}$ cm

When the side of the square becomes two times bigger, the area becomes four times bigger, not two times. Therefore, the correct answer is  B. No, it becomes 4 times bigger.

c) If the tiger wants to catch the deer, in which direction he should be making the jump?

(a) North

(b) South

(c) East

(d) West

Ans: Based on the image and the compass directions provided, the tiger is positioned to the north of the deer. If the tiger wants to catch the deer, it should jump south.

So, Option b is correct.

Q2: Find the perimeter.

(i)

Ans:  Perimeter = 76 cm

The perimeter is the total distance around the figure. To find it, we add the lengths of all the outer sides.

The figure has the following sides:

• 17 cm (top horizontal side)
• 8 cm (left vertical side)
• The missing vertical side, can be calculated by subtracting (21 - 12) = 9 cm
• 12 cm (left bottom vertical side)
• 21 cm (right vertical side)
• The missing horizontal side at the bottom, which can be calculated by subtracting the 8 cm from the total 17 cm: $17-8=\; 9\; cm$

Now, we can add up all the sides:

$Perimeter=17+8+\mathrm{9\; +\; 12}+21+9=\; 76\; cm\mathrm{<br\; style="word-break:\; break-word;\; line-height:\; 1.8;\; font-family:\; Lato,\; sans-serif;\; font-size:\; 20px;\; letter-spacing:\; inherit;\; color:\; black;">}\hspace{0.17em}cm\backslash text\{Perimeter\}\; =\; 17\; +\; 8\; +\; 12\; +\; 21\; +\; 9\; =\; 67\; \backslash ,\; \backslash text\{cm$

(ii)
Ans: Perimeter = 66 cm

The perimeter is the total distance around the figure. We need to add up the lengths of all the outer sides.

The sides are as follows:

• 5 cm (top horizontal side)
• Top vertical line will be 16 cm - 8 cm = 8 cm
• 8 cm (right horizontal side)
• 16 cm (bottom horizontal side)
• 17 cm (left vertical side)
• The missing vertical side, which can be calculated as $17-5=\; 12\; cm$

Now, let's sum these values to find the perimeter:

$Perimeter=5+8+\; 8\; +16+17+12=\mathrm{66\; cm}\hspace{0.17em}cm\backslash text\{Perimeter\}\; =\; 5\; +\; 8\; +\; 16\; +\; 17\; +\; 12\; =\; 58\; \backslash ,\; \backslash text\{cm$

(iii)
Ans: Perimeter = 42 cm

To find the perimeter, we need to sum up the lengths of all the outer sides of the figure.

The sides are:

• 11 cm (top horizontal side)
• 10 cm (right vertical side)
• 4 cm (bottom left vertical side)
• 3 cm (left horizontal side)
• The missing horizontal side, which is $11-3=\mathrm{8\; cm}$
• $\mathrm{The\; missing\; left\; vertical\; side\; is\; calculated\; as 10\; cm\; -}$ 4 cm = 6 cm

Now, let's add all the sides together to get the perimeter:

$Perimeter=11+10+4+8+3+\; 6\; =\mathrm{42\; cm}\hspace{0.17em}cm\backslash text\{Perimeter\}\; =\; 11\; +\; 10\; +\; 4\; +\; 8\; +\; 3\; =\; 36\; \backslash ,\; \backslash text\{cm$

(iv)
Ans: Perimeter  = 82 cm

To find the perimeter, we sum up the lengths of all the outer sides.

The sides are:

22 cm (left vertical side)

13 cm (right vertical side)

10 cm (top horizontal side)

19 cm (bottom horizontal side)

The missing horizontal side is $19-10=\mathrm{9\; cm<br\; style="font-family:\; Lato,\; sans-serif;\; letter-spacing:\; inherit;\; word-break:\; break-word;\; line-height:\; 1.8;\; font-size:\; 20px;\; color:\; black;">}$

The missing right vertical side, which is 22 - 13 = 9 cm

Now, let's add up all the side lengths to find the perimeter:

$Perimeter=22+13+10+19+\mathrm{9\; +\; 9 }=\mathrm{82\; cm}\hspace{0.17em}cm\backslash text\{Perimeter\}\; =\; 22\; +\; 13\; +\; 10\; +\; 19\; +\; 9\; =\; 73\; \backslash ,\; \backslash text\{cm$

(v)
Ans: Perimeter = 117 cm

The perimeter is the sum of all the side lengths of the triangle.

From the image, the sides of the triangle are: 

49 cm
39 cm
29 cm

Now, let's add these side lengths to find the perimeter:

$Perimeter=49+39+29=\mathrm{117\; cm}$
$\backslash text\{Area\}\; =\; \backslash frac\{1\}\{2\}\; \backslash times\; 50.6\; \backslash times\; 27\; =\; 683.1\; \backslash ,\; \backslash text\{cm\}^$

(i) 

Ans:   1. The Dog is located south of the Horse.

              2. The Cat is located southeast of the Horse.

              3. The Cow is located north of the Cat.

              4. The Horse is located northwest of the Cat.

              5. The Dog is located west of the Cat.

              6. The Cow is located northeast of the Horse.

              7. The Dog is located southwest of the Cow.

              8. The Cat is located south of the Cow.

(ii) Find out the scale used to draw the map using the distance information given.
Places - From Bengaluru to Lucknow
Actual distance - 1855 Km 
Distance on map - 5.3 cm
Ans: Actual distance =1855 km
Distance on map =5.3 cm
1 cm = 1855 km / 5.3 
= 1855km / 1 x 10/53 
= 18550 km/53 
∴ 1 cm = 350 km

(iii) Height of a building is 9 m and this building is represented by 9 cm on a map. What is the scale used for the map?
Ans: Given: The height of the building is 9m.
9m is represented by 9cm on the map.
We know that 1m = 100cm
therefore,
9m : 9cm ⇒ 900cm : 9cm
Scale used ⇒ 100:1

(iv) If actual distance between two places A and B is 110 km and it is represented on a map by 25 mm. Then the scale used is _____.
Ans: We know that
Scale of map = Size drawn on map / Actual size  = 25mm / 110km
25mm / 110000000mm
1/440000
So, If actual distance between two places A and B is 110 km and it is represented on a map by 25 mm. Then the scale used is 1 : 4400000

Q4: Look at the given map of INDIA and answer the questions that follow.

(i) Which State is surrounded by four other states?
Ans: Haryana. It is surrounded by Punjab, Himachal Pradesh, Uttarakhand, and Uttar Pradesh.

(ii) Which state has the largest area?
Ans: Rajasthan. It is the largest state in India by area.

(iii) Which are the places along the sea coast of South India?
Ans:

• Chennai (Tamil Nadu)
• Thiruvananthapuram (Kerala)
• Bangalore (Karnataka)
• Panaji (Goa)

(v) Mark those states which have the sea on one side.
Ans:

• Gujarat
• Maharashtra
• Karnataka
• Kerala
• Tamil Nadu
• Andhra Pradesh
• Odisha
• West Bengal
• Goa

(vi) Name one state which does not have the sea on any side.
Ans: Madhya Pradesh. It is a landlocked state with no coastline.

(vii) Name 4 Eastern states of India.
Ans:

• West Bengal
• Odisha
• Bihar
• Jharkhand

(viii) Name 4 South Indian states.
Ans:

• Tamil Nadu
• Kerala
• Karnataka
• Andhra Pradesh

(ix) Which is the capital of Tamil Nadu?
Ans: Chennai. It is the capital city of Tamil Nadu.

(x) Sai is going from Tamil Nadu to Punjab. Name the states which fall in between his route.
Ans: The states from South to North are:

• Tamil Nadu
• Karnataka
• Maharashtra
• Madhya Pradesh
• Uttar Pradesh
• Haryana
• Punjab

(xi) Harsha is travelling from Delhi to Mumbai (Maharashtra). Name the states which fall in between her route.
Ans: The states from North to West are:

• Delhi
• Haryana
• Rajasthan
• Gujarat
• Maharashtra