Q1: What is the base of the exponent 69?
(a) 6
(b) 2
(c) 9
(d) None
Ans: (a)
The base of the exponent 69 is 6
Q2: Find the missing number
(a) 2
(b) −5
(c) 1
(d) None
Ans: (b)
The missing number should be −5
So the answer will be 75 =
Q3: Find the value of (52)2
(a) 125
(b) 625
(c) 25
(d) 0
Ans: (b)
The solution will be
(52)2=54
(52)2=5×5×5×5
(52)2= 625
Q4: Find the value of x, when 2x=44
(a) x=6
(b) x=2
(c) x=8
(d) x=−5
Ans: (c)
The solution will be
2x=44
2x=(22)4
2x=28
2x=28
x=8
So the answer will be x=8
Q5: Find the value of (211+62−51)0= ?
(a) 0
(b) −1
(c) 1
(d) None
Ans: (c)
The solution will be
(211+62−51)0=(anything)0
(211+62−51)0=1
So the solution will be
(211+62−51)0=1
Q6: Express 512 as a power of 2.
(a) 27
(b) 28
(c) 29
(d) 210
Ans: (c)
Since 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29.
Hence, option (c) is correct.
Q7: Which is the correct expression for 625?
(a) 53
(b) 45
(c) 54
(d) None of these
Ans: (c)
We have 625 = 5 × 5× 5 × 5 = 54.
Q8: From 27, 42, 32 and 63, which is greater than others?
(a) 27
(b) 32
(c) 43
(d) 63
Ans: (d)
Since we have
27 = 2 × 2 × 2 × 2 × 2 × 2 × 2 = 128
32 = 3 × 3 = 9
42 = 4 × 4 = 16
63 = 6 × 6 × 6 = 216
In this, 63 is greater.
Q1: (100+120)(160+120)=82
Ans: False
(Anything)0 =1 therefore, LHS= 1
RHS= 82 = 64
hence false
Q2: (34)2=38
Ans: True
LHS= (34)2 = (3)8
RHS= (3)8
Q3: (52)3=100000
Ans: False
LHS= (52)3= (5)6 = 1000000 Hence false
Q1: Follow the pattern and complete
Ans: The pattern for the solution is square root of the numbers which continue as
1234321=11112
123454321=111112
Q2: If 2x × 5x=1000 then x=?
Ans: For solving we will just factorise
2x ×5x=1000
2x × 5x = 5 × 5 × 5 × 2 × 2 × 2
2x × 5x = 23 × 53
x = 3
Q3: Find 33 + 43 + 53 and give the answers in cube
Ans: Solve the expression
33+43+53=27+64+125
33+43+53=216
33+43+53=6×6×6
33+43+53=63
Q4: Find the missing number x in 52+x2=132
Ans: Solve the expression
52+x2=132
25+x2=169
x2=144
x=√144
x=12
Q5: Simplify in exponent form (34× 32)÷ 3−4
Ans: Solving the expression
Q6: Expand
(a) 1526.26
(b) 8379
Using exponents
Ans: Solve in exponential form
(a) 1526.26=1×103+5×102+2×101+6×100 +2×10−1 + 6×10−2
(b) 8379=8×103+3×102+7×101+9×100
Q7: Express the following number as a product of powers of prime factors.
(a) 1225
(b) 3600
Ans: Solve in exponential form
(a) 1225=5×5×7×7
1225=52×72
(b) 3600=2×2×2×2×3×3×5×5
3600=24×32×52
Q8: Express the following large no’s in its scientific notation.
(a) 650200000000
(b) 301000000
Ans: Solve in exponential form
(a)650200000000=6.502×1011
(b)301000000=3.01×108
Q9: Express the following in expanded form
(a) 1.682 × 105
(b) 0.86 × 104
Ans: Solve in exponential form
(a) 168200
(b) 8600
Q10: Prove that
Ans: Solve the left hand side and equate with the right
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1. What are exponents and powers? |
2. How do you simplify expressions with exponents? |
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