Class 12 Exam > Class 12 Videos > Current voltage for Inductive circuit - Alternating Current
Current voltage for Inductive circuit - Alternating Current Video Lecture - Class 12
FAQs on Current voltage for Inductive circuit - Alternating Current Video Lecture - Class 12
| 1. What is the current voltage for an inductive circuit in an alternating current? |  |
| 2. How does the inductance of a circuit affect the voltage in an inductive circuit? | |
Ans. The inductance of a circuit affects the voltage in an inductive circuit by causing a phase difference between the current and voltage waveforms. The voltage lags behind the current in an inductive circuit, and the amount of lag depends on the inductance. Higher inductance results in a greater lag between the voltage and current.
| 3. What happens to the voltage in an inductive circuit when the frequency of the alternating current increases? | |
Ans. When the frequency of the alternating current in an inductive circuit increases, the voltage also increases. This is because the rate of change of current, di/dt, becomes larger at higher frequencies, resulting in a larger induced voltage according to the equation V = Ldi/dt.
| 4. How does the voltage in an inductive circuit change when the inductance is increased? | |
Ans. Increasing the inductance in an inductive circuit causes the voltage to increase. This is because a higher inductance leads to a greater opposition to changes in current, resulting in a larger induced voltage. Therefore, an increase in inductance leads to a higher voltage in the circuit.
| 5. Can the voltage in an inductive circuit be greater than the applied voltage? | |
Ans. Yes, the voltage in an inductive circuit can be greater than the applied voltage. This is because of the phenomenon of self-induction, where a changing current in an inductor induces an opposing voltage. Depending on the circuit configuration and conditions, the induced voltage can be higher than the applied voltage, resulting in a higher voltage in the circuit.
Text Transcript from Video
hello friends this video on alternating
currents part 9 is brought to you by
exam feel calm no more fear from exam
means make sure that you have watched
all the videos turn part 8 before going
ahead with part 9 so now we will
represent the relationship between
voltage and current with the help of
graph so what was the expression for
voltage that was the applied voltage it
was equal to VM sine Omega T and what
was the expression for current which we
obtain it was I M sine Omega t minus Phi
by 2 right so what does these two
expression tell us about the map about
the phase between voltage and current it
sees that they are out of phase by PI by
2 and current sensitives Omega t minus
PI by 2 that means current will lag
behind voltage that means if voltage is
this graph what will be the graph of
current current will lag behind because
it is Omega t minus PI by 2 that means
the point where your voltage reaches
maximum current will reach maximum after
PI by 2 let us suppose voltage reached
Omega reached this value at this time
right at Omega T 1 now current will
reach maximum at this time that is PI so
that means after how much time current
reached maximum this is PI by 2 this
difference is PI by 2 right so that
means it is something like this there
are two friends V and I voltage and
currents are two friends when we are
talking about resistive circuits both
are running at the same speed that means
both on reaching the same point at the
same time when I am talking about an
inductive circuit current is lagging
behind voltage by PI by 2 let us suppose
that voltage and current have
participated in the race right so in the
race they will start from school they
will go to a
people from the temple they will go to a
multiplex and from there they will go to
some other place their playground right
so when both of them are in the same
phase both of them will reach each of
these places at the same time they will
both reach the temple at the same time
then again they will run and they will
reach the multiplex at the same time and
again they will run and reach the
playground at the same time so that is
how the scenario is in case of a
resistive circuit but when we talk about
an inductive circuit it is like this
that voltage reached the temple before
then current after that voltage went
forward and the current reached the
temple after 5x2 of the voltage that
means after let us say PI by 2 instead
of PI by 2 in that scenario if I
consider time after 10 seconds of
voltage so that means that 10 seconds
represents the difference between
voltage and current similarly here when
we are talking about phase this PI by 2
represents the phase difference between
voltage and current and since it is
minus PI by 2 that means current is
lagging behind so the plot would be
somewhat like this this is voltage so
for current also you will plot the same
sine curve just that it will reach its
values pi it will you have to start
plotting the curve PI by 2 times after
voltage to make things simpler you can
also plot it like this length and
suppose first you plot your voltage so
this is your voltage now this is 0 this
is PI by 2 this is PI and this is 2 pi
right this is how it is plotted this is
your voltage now you have to plot
current you know that current lags
behind voltage that meant current will
be after voltage so current will start
after voltage after how much time after
PI by B so you can start plotting a sine
curve from here so if you look at these
two figures they represent the same
thing in the sense that they have joined
it from here right
so since current is lagging
behind so you have to start plotting the
curve for current five by two times
after voltage clear so what did we
observe in case of inductive circuit
voltage and current are out of phase by
PI by two current lags voltage by five
by two average current over a complete
cycle is zero average voltage over a
complete cycle is zero that is quite
obvious because over a complete cycle
again the same scenario the positives
and negatives will cancel out so the
average current will come out to be zero
over any complete cycle thank you please
visit exam vo comm to watch free
educational videos try free online tests
get the best quality study materials
study from the best tutors and mentors
and much more thank you once again
currents part 9 is brought to you by
exam feel calm no more fear from exam
means make sure that you have watched
all the videos turn part 8 before going
ahead with part 9 so now we will
represent the relationship between
voltage and current with the help of
graph so what was the expression for
voltage that was the applied voltage it
was equal to VM sine Omega T and what
was the expression for current which we
obtain it was I M sine Omega t minus Phi
by 2 right so what does these two
expression tell us about the map about
the phase between voltage and current it
sees that they are out of phase by PI by
2 and current sensitives Omega t minus
PI by 2 that means current will lag
behind voltage that means if voltage is
this graph what will be the graph of
current current will lag behind because
it is Omega t minus PI by 2 that means
the point where your voltage reaches
maximum current will reach maximum after
PI by 2 let us suppose voltage reached
Omega reached this value at this time
right at Omega T 1 now current will
reach maximum at this time that is PI so
that means after how much time current
reached maximum this is PI by 2 this
difference is PI by 2 right so that
means it is something like this there
are two friends V and I voltage and
currents are two friends when we are
talking about resistive circuits both
are running at the same speed that means
both on reaching the same point at the
same time when I am talking about an
inductive circuit current is lagging
behind voltage by PI by 2 let us suppose
that voltage and current have
participated in the race right so in the
race they will start from school they
will go to a
people from the temple they will go to a
multiplex and from there they will go to
some other place their playground right
so when both of them are in the same
phase both of them will reach each of
these places at the same time they will
both reach the temple at the same time
then again they will run and they will
reach the multiplex at the same time and
again they will run and reach the
playground at the same time so that is
how the scenario is in case of a
resistive circuit but when we talk about
an inductive circuit it is like this
that voltage reached the temple before
then current after that voltage went
forward and the current reached the
temple after 5x2 of the voltage that
means after let us say PI by 2 instead
of PI by 2 in that scenario if I
consider time after 10 seconds of
voltage so that means that 10 seconds
represents the difference between
voltage and current similarly here when
we are talking about phase this PI by 2
represents the phase difference between
voltage and current and since it is
minus PI by 2 that means current is
lagging behind so the plot would be
somewhat like this this is voltage so
for current also you will plot the same
sine curve just that it will reach its
values pi it will you have to start
plotting the curve PI by 2 times after
voltage to make things simpler you can
also plot it like this length and
suppose first you plot your voltage so
this is your voltage now this is 0 this
is PI by 2 this is PI and this is 2 pi
right this is how it is plotted this is
your voltage now you have to plot
current you know that current lags
behind voltage that meant current will
be after voltage so current will start
after voltage after how much time after
PI by B so you can start plotting a sine
curve from here so if you look at these
two figures they represent the same
thing in the sense that they have joined
it from here right
so since current is lagging
behind so you have to start plotting the
curve for current five by two times
after voltage clear so what did we
observe in case of inductive circuit
voltage and current are out of phase by
PI by two current lags voltage by five
by two average current over a complete
cycle is zero average voltage over a
complete cycle is zero that is quite
obvious because over a complete cycle
again the same scenario the positives
and negatives will cancel out so the
average current will come out to be zero
over any complete cycle thank you please
visit exam vo comm to watch free
educational videos try free online tests
get the best quality study materials
study from the best tutors and mentors
and much more thank you once again
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Mar 23, 2025
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