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DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics PDF Download

Objective Questions (Level 1)
Single Correct Option

Ques 1: A particle has initial velocity, DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics and a constant force 

DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics acts on it. The path of the particle is 
(a) straight line 
(b) parabolic 
(c) circular 
(d) elliptical
Ans: circular
Sol: 
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Path of the particle is circular.
Option (c) is correct.

Ques 2: Identify the correct statement related to the projectile motion. 
(a) It is uniformly accelerated everywhere 
(b) It is uniformly accelerated everywhere except at the highest position where it is moving with constant velocity 
(c) Acceleration is never perpendicular to velocity 
(d) None of the above
Ans: It is uniformly accelerated everywhere
Sol: Projectile motion is uniformly accelerated everywhere even at the highest point.
Option (a) correct.
Option (b) incorrect.
At the highest point acceleration is perpendicular to velocity.
Option (c) incorrect.

Ques 3: A ball is projected with a velocity 20 ms -1 at an angle to the horizontal. In order to have the maximum range. Its velocity at the highest position must be 
(a) 10 ms-1 
(b) 14 ms-1 
(c) 18 ms-1 
(d) 16 ms-1
Ans: 14 ms-1
Sol: For range to be maximum
θ = 45°
i.e., DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or  DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics  (∴ vx = ux)
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
= 14.14 m/s = 14 m/s (approx)
Option (b) is correct.

Ques 4: Two bodies are thrown with the same initial velocity at angles θ and (90° - 0) respectively with the horizontal, then their maximum heights are in the ratio 
(a) 1 : 1 
(b) sin θ : cos θ 
(c) sin2 θ : cosθ 
(d) cos θ : sin θ
Ans: sin2 θ : cosθ
Sol: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Thus,  DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (c) is correct.

Ques 5: A gun is firing bullets with velocity v0 by rotating through 360° in the horizontal plane. The maximum area covered by the bullets is
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Ans: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Sol: Equation to trajectory is
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics

Ques 6: A body is projected at an angle 60° with the horizontal with kinetic energy K. When the velocity makes an angle 30° with the horizontal, the kinetic energy of the body will be 
(a) K/2 
(b) K/3 
(c) 2K/3 
(d) 3K/4
Ans: K/3
Sol: v cos φ = u cos θ
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or  DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
∴ Option (b) is correct.

Ques 7: The range of a projectile at an angle 0 is equal to half of the maximum range if thrown at the same speed. The angle of projection 0 is given by 
(a) 15° 
(b) 30° 
(c) 60° 
(d) data insufficient
Ans: 15°
Sol: 
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or 2θ = 30°
∴ θ = 15°
Option (a) is correct.

Ques 8: If T1 and T2 are the times of flight for two complementary angles, then the range of projectile R is given by
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Ans: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Sol: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or  DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (d) is correct.

Ques 9: A grass hopper can jump maximum distance 1.6 m. It spends negligible time on ground. How far can it go in 10√2 s. 
(a) 45 m 
(b) 30 m 
(c) 20 m 
(d) 40 m
Ans: 40 m
Sol: Rmax = 1.6 m
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
⇒ u = 4 m/s
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics= 25
∴ Grass hopper would go = 25 x 1.6 m i.e., 40 m.
Option (d) is correct.

Ques 10: Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projection speed = u, angle of projection from horizontal = θ)
(a) u cos θ
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Ans: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Sol: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (b) is correct.

Ques 11: A train is moving on a track at 30 ms-1. A ball is thrown from it perpendicular to the direction of motion at 30 ms-1 at 45° from horizontal. Find the distance of ball from the point of projection on train to the point where it strikes the ground. 
(a) 90 m 
(b) 90 √3 m 
(c) 60 m 
(d) 60 √3 m
Ans: 90 m
Sol: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (b) is correct.

Ques 12: A body is projected at time t = 0 from a certain point on a planet’s surface with a certain velocity at a certain angle with the planet’s surface (assumed horizontal). The horizontal and vertical displacements x and y (in metre) respectively vary with time t in second as, x = (10√3) 7 and y = 10t - t2. The m axim um height attained by the body is 
(a) 200 m 
(b) 100 m 
(c) 50 m 
(d) 25 m
Ans: 25 m
Sol: At maximum height
dy/dt = 0
i.e.,  DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or   10 - 2t = 0
or t = 5 s
∴ Maximum height attained = 10 (5) - 52
= 25 m
Option (d) is correct.

Ques 13: A particle is fired horizontally from an inclined plane of inclination 30° with horizontal with speed 50 ms-1. If g = 10 ms-2, the range measured along the incline is
(a) 500 m
(b) DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
(c) DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
(d) DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Ans: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Sol: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
As α = 0 (according to question)
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (b) is correct.

Ques 14: Two stones are projected with the same speed but making different angles with the horizontal. Their horizontal ranges are equal. The angle of projection of one is π/3 and the maximum height reached by it is 102 m. Then the maximum height reached by the other in metres is
(a) 336 
(b) 224 
(c) 56 
(d) 34 
Ans: 34
Sol: First particle:
Hmax = 102 m
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Second particle:
Range of the second particle will be equal to that of particle
if, DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
sin 2φ = sin 3α
2φ = π - 2α
or  DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
∴ Maximum height attained by second particle
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (d) is correct.

Ques 15: A ball is projected upwards from the top of a tower with a velocity 50 ms-1 making an angle 30° with the horizontal. The height of tower is 70 m. After how many seconds from the instant of throwing, will the ball reach the ground, (g = 10 ms-2
(a) 2 s 
(b) 5 s 
(c) 7 s 
(d) 9 s
Ans: 7 s
Sol: DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
or 5t2 - 25t - 70 = 0
or t2 - 5t - 14 = 0
(t - 7) (t + 2) = 0
t = 7 s
(- 2 s not possible)
Option (c) is correct.

Ques 16: A fixed mortar fires a bomb at an angle of 53° above the horizontal with a muzzle velocity of 80 ms-1. A tank is advancing directly towards the mortar on level ground at a constant speed of 5m/s. The initial separation (at the instant mortar is fired) between the mortar and tank, so that the tank would be hit is [Take g = 10 ms-2
(a) 662.4 m 
(b) 526.3 m 
(c) 486.6 m 
(d) None of these
Sol: Initial separation
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics
Option (d) is correct.

The document DC Pandey Solutions (JEE Main): Projectile Motion- 3 | DC Pandey Solutions for JEE Physics is a part of the JEE Course DC Pandey Solutions for JEE Physics.
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FAQs on DC Pandey Solutions (JEE Main): Projectile Motion- 3 - DC Pandey Solutions for JEE Physics

1. What is projectile motion?
Ans. Projectile motion refers to the motion of an object that is launched into the air and moves along a curved path under the influence of gravity alone. It is characterized by the object's initial velocity, angle of projection, and the acceleration due to gravity.
2. How is the trajectory of a projectile determined?
Ans. The trajectory of a projectile is determined by its initial velocity and angle of projection. By analyzing the horizontal and vertical components of the initial velocity, one can calculate the time of flight, maximum height reached, and range of the projectile.
3. What are the equations of motion for projectile motion?
Ans. The equations of motion for projectile motion are: - Horizontal motion: x = v₀x * t, where x is the horizontal displacement, v₀x is the horizontal component of the initial velocity, and t is the time. - Vertical motion: y = v₀y * t - 1/2 * g * t², where y is the vertical displacement, v₀y is the vertical component of the initial velocity, g is the acceleration due to gravity, and t is the time.
4. How does the angle of projection affect the range of a projectile?
Ans. The range of a projectile is maximized when it is launched at an angle of 45 degrees with respect to the horizontal. Any angle greater or lesser than 45 degrees will result in a shorter range. This is because the horizontal component of the initial velocity is highest at 45 degrees.
5. How does the initial velocity affect the maximum height reached by a projectile?
Ans. The maximum height reached by a projectile is directly proportional to the square of the initial velocity. This means that doubling the initial velocity will result in a four-fold increase in the maximum height.
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