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Practice Exercise 
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Question 1: In the adjoining figure, find x + y + z + w
Solution: Since, the sum of the measures of interior angles of a quadrilateral is 360°.
Also, 115° + 70° + 60° = 245°
∴ 245° +∠ABC = 360°
⇒∠ABC = 360° – 245° = 115°
Now, x = ext. ∠BCD
= 180° – ∠BCD
= 180° – 115° = 65°
Similarly, y = 180° – 70° = 110°
z = 180° – 60° = 120°
w = 180° – 115° = 65°
∴ x + y + z + w = 65° + 110° + 120° + 65°
= 360°
Question 2: In a quadrilateral ABCD, the angles A, B, C and D are in the ratio 1 : 2 : 3 : 4. Find the measure of each angle of the quadrilateral.
Solution: ∵∠A : ∠B : ∠C : ∠D = 1 : 2 : 3 : 4
∴ Let us suppose that
∠A = 1x°, ∠B = 2x°
∠C = 3x°, –D = 4x°
Since, ∠A +∠B + ∠C +∠D = 360°
∴ x + 2x + 3x + 4x = 360°
⇒ 10x = 360°
⇒ x = 360/10 = 36°
∴ Angles are:
∠A = x° = 36°
∠B = 2x° = 2 x 36° = 72°
∠C = 3x° = 3 x 36° = 108°
∠D = 4x° = 4 x 36° = 144°
Thus, the measure of the angle of the quad. are 36°, 72°, 108° and 144°
Question 3: The interior angle of a regular is 108°. Find the number of sides of the polygon.
Solution: Let there are ‘n’ sides of the regular polygon.
∴ Measure of each exterior angle = (360/n)^{o}
Since, the measure of each of the interior angle = 108°
∴ Measure of each exterior angle = 180° – 108° = 72°
⇒ 360/n = 72 ⇒ n = 360/72 = 5
Thus, the required number of sides of the regular polygon is 5.
Alternate Solution
Let there be ‘n’ sides of the regular polygon.
Since the measure of each interior angle is
∴
⇒ (2n4) x 90 = 108 x n
⇒ 180n  360 = 108n
⇒ 180n  108n = 360
⇒ 72n = 360 ⇒ n= (360/72) = 5
Thus, there are 5 sides of the given regular polygon.
Question 4: Two regular polygons are such that the ratio of the measures their interior angles is 4 : 3 and the ratio between their number of sides is 2: 1. Find the number of sides of each polygon.
Solution: Let 2n and n be the number of sides of the regular polygons.
∴ Their interior angles are
Since the ratio of the interior angles is 4 : 3
∴
⇒
⇒
⇒
⇒
⇒ 3(n1) = 4(n2)
⇒ 3n 3 = 4n 8
⇒ 3n  4n = 8 +3
⇒ n = 5 ⇒ n=5
⇒ 2n = 2 x 5 = 10
Thus, the number of sides of the polygons are 10 and 5 respectively.
Question 5: The exterior angle of a regular polygon is onefifth of its interior angle. How many sides has the polygon?
Solution: Let the number of sides be ‘n’.
∴ Exterior angle of polygon = (360/n)^{o}
^{And the interior angle of the polygon = }
since Exterior angle = 1/5 (Interior angle)
⇒
⇒
⇒
⇒ 2n 4 = 20 ⇒ 2n = 20 +4 = 24
⇒ n= 24/2 = 12
Thus, the polygon is having 12 sides.
Question 6: The measures of two adjacent angles of a parallelogram are in the ratio 4: 5. Find the measure of each of the angles of the parallelogram.
Solution: Let ABCD be a parallelogram such that ∠A and ∠B are 4x and 5x respectively.
Since, the adjacent angles are supplementary,
∴ ∠A+ ∠B = 180^{0}
⇒ 4x + 5x = 180^{o}
⇒ 9x+ = 180^{0 . }⇒ x = 180^{o}/9 = 20^{o}
∴ ∠A = 4x = 4 x 20° = 80°
and ∠B = 5x = 5 x 20° = 100°
We know that opposite angles of a parallelogram are equal.
∴ ∠C = ∠A = 80º
And ∠D= ∠B = 100°
Thus, ∠A = 80°, ∠B = 100°, ∠C = 80° and D = 100°
Question 7: In a quadrilateral ABCD, DO and CO are the bisectors of ∠D and ∠C respectively.
Prove that
Solution: In ΔCOD, we have
⇒ ∠COD + ∠1 + ∠2 = 180°
⇒ ∠COD = 180° – [–1 + –2]
⇒
⇒ But ∠A+ ∠B+∠C+∠D = 360^{o}
⇒ ∠C+∠D = 360^{o}  (∠A+∠B)
∴
Thus,
Q 1. If an exterior angle of a regular polygon is 45°, then find the number of its sides.
Ans: 8
Q 2. If an interior angle of a regular polygon is 162°, then find the number of its sides.
Ans: 20
Q 3. Find x in the following figure.
Ans: 70^{o}
Q 4. Find the measure of an interior angle of a regular polygon having 15 sides.
Ans: 156^{o}
Q 5. Find the measure of each of the (i) exterior angle. (ii) interior angle of an octagon.
Ans: (i) 45° (ii) 135°
Q 6. An angle of a parallelogram measures 70°. Find the measure of the remaining three angles.
Ans: 110°, 70°, 110°
Q 7. In the following figure, ABCD is a parallelogram. Find measures of x, y and z.
Ans: x = 80°, y = 100°, z = 80°
Q 8. In the following figure, find the measures of x, y, z and w.
Ans: x = 120°, y = 100°, z = 120°, w = 80°
Q 9. One angle of a quadrilateral is 111° and the remaining three angles are equal. Find three angles.
Ans: 81° each
Q.10. What is the ratio of the interior angles of a pentagon and a decagon?
Note: (i) A pentagon has 5 sides. (ii) A decagon has 10 sides.
Ans: 3: 4
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