Particular solution of the differential equation is a unique solution of the form y = f(x), which satisfies the differential equation. The particular solution of the differential equation is derived by assigning values to the arbitrary constants of the general solution of the differential equation.
Let us learn more about the particular solution of the differential equation, how to find the solution of the differential equation, and the difference between a particular solution and the general solution of the differential equation.
Particular solution of the differential equation is an equation of the form y = f(x), which do not contain any arbitrary constants, and it satisfies the differential equation. The equation or a function of the form y = f(x), having specific values of x which satisfy this equation and are called the solutions of this equation. For a differential equation d2y/dx2 + 2dy/dx + y = 0, the the values of y which satisfy this differential equation is called the solution of the differential equation.
Here y = f(x) representing a line or a curve is the solution of the differential equation that satisfies the differential equation. The solution of the form y = ax2 + bx + c is the general solution of the differential equation, since it contains arbitrary constants a, b, c. Further, if the solution has values assigned to these arbitrary constants, or if the solution is without any arbitrary constants, then the solution is called the particular solution of the differential equation.
The particular solution of the differential equation can be computed from the general solution of the differential equation. The general solution of a differential solution would be of the form y = f(x) which could be any of the parallel line or a curve, and by identifying a point that satisfies one of these lines or curves, we can find the exact equation of the form y = f(x) which is the particular solution of the differential equation.
The following steps help in finding the particular solution of the differential equation.
A particular solution of the differential equation is derived from the general solution of the differential equation. The differential equation has one general solution, and numerous particular solutions, based on the different values of the arbitrary constants of the general solution.
The general solution of the differential represents a family of curves or lines in the coordinate plane, These curves or lines represent a set of parallel lines or curves, and each of these lines or the curves can be identified as the particular solution of the differential equation.
The general solution of the differential equation is of the form y = ax + b, but the particular solution of the differential equation can be y = 3x + 4, y = 5x + 7, y = 2x + 1. These particular solutions of the differential equation have been obtained by assigning different values to the arbitrary constants a, b in the general solution of the differential equation.
Example 1: Find if the equation y = e-2x is a particular solution of a differential equation d2y/dx2 + dy/dx -2y = 0.
Sol:
The given equation of the solution of the differential equation is y = e-2x.
Differentiating this above solution equation on both sides we have the following expression.
dy/dx = -2e-2x
Further, differentiating this with respect to x for the second differentiation, we have:
d2y/dx2 = 4e-2x
Applying this in the differential equation to check if it satisfies the given expression.
The given differential equation is:
d2y/dx2 + dy/dx -2y = 0
4e-2x - 2e-2x - 2e-2x = 0.
Therefore, the equation y = e-2x is a solution of a differential equation d2y/dx2 + dy/dx -2y = 0.
Example 2: Verify if the function y = acosx + bsinx is a particular solution of a differential equation y'' + y = 0?
Sol:
The given function is y = aCosx + bSinx.
Let us take the second derivative of this function.
y' = -aSinx + bCosx
y'' = -aCosx - bSinx
Further we can substitute this second derivative value in the below differential equation.
y'' + y = 0
(-aCosx - bSinx) + (aCosx + bSinx.) = 0
-aCosx - bSinx + aCosx + bSinx. = 0
-aCosx + aCosx -bSinx +bSinx = 0
Therefore, the function y = acosx + bsinx is a solution of a differential equation y'' + y = 0.
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1. What is a particular solution of a differential equation? |
2. How can we find the particular solution of a differential equation? |
3. What is the difference between a particular solution and a general solution of a differential equation? |
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