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Important Logarithms Formulas for JEE and NEET

What are Logarithms?

A logarithm is defined as the power to which a number must be raised to get some other values. It is the most convenient way to express large numbers. A logarithm has various important properties that prove multiplication and division of logarithms can also be written in the form of a logarithm of addition and subtraction.
“The logarithm of a positive real number a with respect to base b, a positive real number not equal to 1[nb 1], is the exponent by which b must be raised to yield a”.
i.e. by= a logba=y 
Where,

  • “a” and “b” are two positive real numbers
  • y is a real number
  • “a” is called argument, which is inside the log
  • “b” is called the base, which is at the bottom of the log.

Important Logarithms Formulas for JEE and NEET

In other words, the logarithm gives the answer to the question “How many times a number is multiplied to get the other number?”. 
For example, how many 3’s are multiplied to get the answer 27?
If we multiply 3 for 3 times, we get the answer 27. 
Therefore, the logarithm is 3.
The logarithm form is written as follows:
Log3 (27) = 3 ….(1)
Therefore, the base 3 logarithm of 27 is 3.
The above logarithm form can also be written as:
3 x 3 x 3 = 27
33 = 27 …..(2)
Thus, the equations (1) and (2) both represent the same meaning.
Below are some of the examples of conversion from exponential forms to logarithms.
Important Logarithms Formulas for JEE and NEET

Logarithm

Let a,b be positive real numbers
So, ax =b can be written as
loga b = x          a 1≠1, a > 0, b > 0
Ex:- 35 = 243   log3 243 = 5

Types of Logarithms

(i) Natural Logarithm: loge N is called natural Logarithm or Naperian Logarithm denoted by (ln N) i.e., when logarithm’s base is “e” then it is called natural logarithm. Ex: loge 7
(ii) Common Logarithm: log10 N is called Brigg’s Logarithm when the base is 10. Ex: log10 100

Logarithm Properties

  • loga 1 = 0, a > 0, a 1
  • loga a = 1,  a > 0, a 1
  • Loga ax = x, x x R, x >0
  • aloga x = x, x x R, x >0
  • loga (m.n) = loga m + loga n, n m, n > 0, a > 0, a 1
  • loga (m/n) = loga m –  loga n, n m, n > 0, a > 0, a 1
  • loga (mn) = n loga m, m m, m > 0, a > 0, a 1
  • loga (1/m)  = –  loga m, m m, n > 0, a > 0, a 1
  • Important Logarithms Formulas for JEE and NEET 
  • loga b = x a, b > 0, a 1 and x R
    (i) log1/a b = – x
    (ii) loga (1/b) = – x
    (iii) log1/a (1/b) = -x
  • logam b = 1/m loga b
  • loga x is a decreasing function, if 0 < a < 1
  • loga x is a increasing function, if a > 1
  • When 0 < a < 1 then
    • loga b loga c, b c
    • loga b c, b ac 
  • When a >1
    • loga b loga c, b c > 0
    • loga b c, b ac  

Characteristics and Mantissa

Characteristic: The integral part of logarithm is known as characteristic.
Mantissa: The decimal part is known as mantissa and is always positive
In log 3274 = 3.5150, the integral part is 3 i.e., characteristic is 3 and the decimal part is .5150 i.e., mantissa is .5150.

Points to Remember About Characteristics

  • The characteristic of common logarithm of positive number less than unity (i.e.,1) is negative.
  • The characteristic of common logarithm of a positive number greater than 1 is positive.
  • If the logarithm to any base a gives the characteristic ‘n’, then the number of possible integral values is given by an+1 −an. For example log10 x = n.abcd, then the number of integral values that x can have given by 10n+1 −10n
  • If the characteristic of log10 x is negative (i.e., − n), then the number of zeros between the decimal and the first significant number after the decimal is (n −1)

Important Conversions

  • For > 1, 1, > 0, b > loga < b
  • For 0 < < 1, 1, > 0, b > loga > b

Solved Examples

Question 1: If log2X + log4X = log0.25√6 and x > 0, then x is:

A. 6-1/6

B. 61/6

C. 3-1/3

D. 61/3

Correct Answer is Option (A).

  • log2x + log4x = log0.25√6
    We can rewrite the equation as:  
    Important Logarithms Formulas for JEE and NEET
     log2x * 3 = 2log0.25√6
     log2x3 = -log46 
    Important Logarithms Formulas for JEE and NEET
    Important Logarithms Formulas for JEE and NEET
     2log2x3 = -log26
  • 2log2x3 + log26 = 0
    log26X6 = 0
  • 6x6 = 1 
    x6 = 1/6
    Important Logarithms Formulas for JEE and NEET
  • The question is "If log2X + log4X = log0.25 √6 and x > 0, then x is"
  • Hence, the answer is "6-1/6".

Question 2: log9 (3log2 (1 + log3 (1 + 2log2x))) = 1/2. Find x. 

A. 4

B. 1/2

C. 1

D. 2

Correct Answer is Option (D).

log9 (3log2 (1 + log3 (1 + 2log2x)) = 1/2

3log2(1 + log3(1 + 2log2x)) = 91/2 = 3
log2(1 + log3(1 + 2log2x) = 1 
1 + log3(1 + 2log2x) = 2 
log3(1 + 2log2x) = 1
1 + 2log2x = 3 
2log2x = 2 
log2x = 1 
x = 2 

The question is "Find x."

Hence, the answer is "2".


Question 3: If 22x+4 – 17 × 2x+1 = –4, then which of the following is true? 

A. x is a positive value

B. x is a negative value

C. x can be either a positive value or a negative value 

D. None of these 

Correct Answer is Option (C).

2x+4 – 17 * 2x+1 = – 4 
=> 2x+1 = y 
22x+2 = y2
22(22x+2) – 17 * 2x+1 = –4 
4y2 – 17y + 4 = 0 
4y2 – 16y – y + y = 0 
4y (y – 4) – 1 (y – 4) = 0 

y = 1/4 or 4

2x+1 = 1/4 or 4

⇒ x + 1 = 2 or – 2
x = 1 or – 3

The question is "which of the following is true?"

Hence, the answer is "x can be either a positive value or a negative value".


Question 4: If log1227 = a, log916 = b, find log8108 

A. Important Logarithms Formulas for JEE and NEET

B. Important Logarithms Formulas for JEE and NEET

C. Important Logarithms Formulas for JEE and NEET

D. Important Logarithms Formulas for JEE and NEET

Correct Answer is Option (D).

log8108 = log8(4 * 27) 
log8108 = log84 + log827 
 log84 = 2/3

Important Logarithms Formulas for JEE and NEET
Important Logarithms Formulas for JEE and NEET
log827 = 2 * log16
log916 = b 
log169 = 1/b

log827 = 2/b

Important Logarithms Formulas for JEE and NEET

The question is "find log8108."

Hence, the answer is Important Logarithms Formulas for JEE and NEET


Question 5: Important Logarithms Formulas for JEE and NEET If a, b are integers such that x = a, and x = b satisfy this inequation, find the maximum possible value of a – b. 

A. 214

B. 216

C. 200

D. 203

Correct Answer is Option (A).

Important Logarithms Formulas for JEE and NEET

log3x = y

Important Logarithms Formulas for JEE and NEET

y ∈ (3, 5)
3 < log3x < 5
27 < x < 243
Therefore max ( a – b) will be when a = 242 and b = 28. Therefore, max(a – b) = 214.

The question is "find the maximum possible value of a – b."

Hence, the answer is "214".


Question 6: log5x = a (This should be read as log X to the base 5 equals a) log20x = b. What is logx10?

A. Important Logarithms Formulas for JEE and NEET
B. (a + b) * 2ab

C. Important Logarithms Formulas for JEE and NEET
D. Important Logarithms Formulas for JEE and NEET

Correct Answer is Option (A).

Given, log5x = a
log20x = b
logx5 = 1/a

logx20 = 1/b
Important Logarithms Formulas for JEE and NEET
Important Logarithms Formulas for JEE and NEET
Important Logarithms Formulas for JEE and NEET
Important Logarithms Formulas for JEE and NEET
Important Logarithms Formulas for JEE and NEET

The question is "What is logx10?"

Hence, the answer is Important Logarithms Formulas for JEE and NEET


Question 7: log3x + logx3 = 17/4. Find x.

A. 34

B. 31/8

C. 31/4

D. 31/3

Correct Answer is Option (C).

log3x + logx3 = 17/4

Let y = log3x
We know that logx3 = Important Logarithms Formulas for JEE and NEET

Hence logx3 = 1/y

Thus the equation can be written asImportant Logarithms Formulas for JEE and NEET

4y2 + 4 = 17y
4y2 + 4 - 17y = 0
Solving the above equation we get y = 4 or 1/4

If y = 4
log3x = 4
Then x = 34
If y = 1/4

log3x = 1/4

Then x = 31/4
The question is "Find x."

Hence, the answer is "34".

Question 8: logxy + logyx2 = 3. Find logxy3. 

A. 4

B. 3

C. 31/2

D. 31/16

Correct Answer is Option (B).

logxy + logyx2 = 3
Let a = logxy 

Important Logarithms Formulas for JEE and NEET

logyx2 = 2logyx
We know that logyx =Important Logarithms Formulas for JEE and NEET

Hence form above logyx = 1/a

Now rewritting the equation logxy + logyx2 = 3 

Using a we get Important Logarithms Formulas for JEE and NEET

i.e., a2 - 3a + 2 = 0
Solving we get a = 2 or 1 
If a = 2, Then logxy = 2 and logyx3 = 3
logxy = 3 * 2 = 6
Or
If a = 1, Then logxy = 1 and logyx3 = 3
logxy = 3 * 1 = 3

The question is "Find logxy3."

Hence, the answer is "3".


Question 9: log2 4 * log4 8 * log8 16 * ……………nth term = 49, what is the value of n? 

A. 49

B. 48

C. 34

D. 24

Correct Answer is Option (B).

First, the nth term of L.H.S need to be defined by observing the pattern :-
It is log(2n) 2.2n 
Given,
log2 4 * log4 8 * log8 16 * ……………log(2n) 2.2n = 49
Whenever solving a logarithm equation, generally one should approach towards making the base same.
Making the base 2:- 

Important Logarithms Formulas for JEE and NEET

log(2n) 2.2n = 49
log(2n) 2 + log(2n) 2n = 49
1 + n = 49
n = 48

The question is "what is the value of n?"

Hence, the answer is "48".


Question 10: If 33 + 6 + 9 + ……… 3x =Important Logarithms Formulas for JEE and NEET what is the value of x? 

A. 3

B. 6

C. 7

D. 11

Correct Answer is Option (D).

First of all, let us define the xth term. 

Important Logarithms Formulas for JEE and NEET

Whenever you encounter a distinctive number such as one given in R.H.S of above equation, always try to find its significance in the context of question. 

In this case L.H.S has 3a, so Important Logarithms Formulas for JEE and NEET must be some form of 3a. 

With little hit and trial, you may find Important Logarithms Formulas for JEE and NEET

33(1 + 2 + 3 + ...X) = 3 -3 * -66
 33 * 3x(x+1)/2 = 33*66 

 Important Logarithms Formulas for JEE and NEET

x(x+1) = 132
Solving this equation for x > 0, we get x = 11.
You should directly be able to see that 132 = 11 * 12 => x= 11
And avoid wasting time solving the complete equation.

The question is "what is the value of x?"

Hence, the answer is "11".

Question 11: x, y, z are 3 integers in a geometric sequence such that y - x is a perfect cube. Given, log36x2 + log6√y + log216y1/2z = 6. Find the value of x + y + z. 

A. 189

B. 190

C. 199

D. 201

Correct Answer is Option (A).

Let us begin with simplifying the equation:-
 log62x2 + log6y1/2 + 3log63y1/2z = 6 

Important Logarithms Formulas for JEE and NEET

log6x + log6y1/2y1/2z = 6
log6xyz = 6
xyz = 66 

Given x,y,z is in G.P. Let x = a, y = ab, z = ab2
⇒ xyz = a3b3 = (ab)3 
(ab)3 = (62)3
Possible values of (a,b) satisfying the equation :-
(1, 36), (2, 18), (3, 12), (4, 9), (9, 4), (12, 3), (18, 2), (36, 1)
Given y-x is a perfect cube
⇒ ab-a is perfect cube
⇒ a(b-1) is perfect cube
Only possible when (a, b) = (9, 4)
∴ x = 9 , y = 36 , z = 144
∴ x + y + z = 9 + 36 + 144 = 189

The question is "Find the value of x + y + z."

Hence, the answer is "189".

Question 1210log(3 - 10logy) = log2(9 - 2y), Solve for y. 

A. 0

B. 3

C. 0 and 3

D. none of these

Correct Answer is Option (D).

Before beginning to simplify the equation, don’t forget that anything inside a log cannot be negative 
10log(3-y) = log2(9 - 2y) (y > 0)…………………………………(1)
3 - y = log2(9 - 2y) (Therefore, 3 - y > 0 =) (y < 3)) ……………………… (2)
23-y = 9 - 2y
2y = t 

Important Logarithms Formulas for JEE and NEET

⇒ 8 = 9t –t2
⇒ t2 - 9t + 8 = 0
⇒ t2 - t - 8t - 8 = 0
⇒ t(t - 1) - 8(t - 1) = 0
⇒ t = 1, 8
Therefore, 2y = 1 and 2y = 8
⇒ y = 0 and y = 3
However, from inequalities (1) and (2), y cannot take either of these value.

The question is "Solve for y."

Hence, the answer is "none of these".

Question 13: 46+12+18+24+…+6x = (0.0625)-84, what is the value of x? 

A. 7

B. 6

C. 9

D. 12

Correct Answer is Option (A).

Take right side expression, 

Important Logarithms Formulas for JEE and NEET

= (4-2)-84
= 4168
Take left side expression 
46+12+18+24+…+6x = 46(1+2+3+4+x)
= 46 * 4(1+2+3+4+…+x)
= 46 * 4x(x+1)/2 (using the formula for sum of natural numbers from 1 to x)
Equating left and right side expresssions, we get 46 * 4x(x+1)/2 = 4168
Or 46 * 4x(x+1)/2 = 46*28

Important Logarithms Formulas for JEE and NEET

or x (x + 1) = 56
Solving for x we get, x = 7

The question is "what is the value of x?"

Hence, the answer is "7".

Logarithm

  • Log(ab) = Log(a) + Log(b)
  • Log(a/b) = Log(a) - Log(b)
  • Log(an) = nLog(a)
  • Important Logarithms Formulas for JEE and NEET
  • Logb b = 1
  • Logb 1 = 0
  • Logb bx = x
  • Ln x means loge x
  • x = blogbx
    Important Logarithms Formulas for JEE and NEET
The document Important Logarithms Formulas for JEE and NEET is a part of the UPSC Course CSAT Preparation.
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FAQs on Important Logarithms Formulas for JEE and NEET

1. What is a logarithm?
Ans. A logarithm is the inverse operation of exponentiation. It is a mathematical function that determines the power to which a given number, called the base, must be raised to obtain a specific value. In other words, logarithms help us solve equations involving exponential functions.
2. What are the types of logarithms?
Ans. There are different types of logarithms, including: - Common logarithm (base 10): It is denoted by log10 or simply log. It helps us find the exponent to which 10 must be raised to obtain a given value. - Natural logarithm (base e): It is denoted by ln. Here, e is a mathematical constant approximately equal to 2.71828. Natural logarithms help us find the exponent to which e must be raised to obtain a given value.
3. What are some properties of logarithms?
Ans. Logarithms have several important properties, including: - Product Rule: log(ab) = log(a) + log(b) - Quotient Rule: log(a/b) = log(a) - log(b) - Power Rule: log(a^n) = n * log(a) - Change of Base Rule: loga(b) = logc(b) / logc(a), where c can be any positive number These properties help simplify logarithmic expressions and solve logarithmic equations.
4. What are characteristics and mantissa in logarithms?
Ans. In logarithms, the characteristic refers to the integer part of the logarithm, while the mantissa refers to the decimal part. For example, in log 1000 = 3, the characteristic is 3 and the mantissa is 0. The characteristic relates to the magnitude of the number being represented, while the mantissa represents the fractional part of the logarithm.
5. Can you provide some important conversions related to logarithms?
Ans. Yes, here are some important conversions related to logarithms: - loga(b) = logc(b) / logc(a), where c can be any positive number - loga(b) = 1 / logb(a) - loga(b * c) = loga(b) + loga(c) - loga(b / c) = loga(b) - loga(c) - loga(b^n) = n * loga(b) These conversions can be used to simplify logarithmic expressions and solve logarithmic equations.
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