Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE) PDF Download

Chapter 14
IMPULSE OF JETS
-Jet Strikes normal to the flat stationary plate

Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)

Force exerted by the jet normal to the plate
Fn = ρaV2
a = area of jet
V = velocity of jet
ρ= density of water

-Jet strikes on a inclined stationary plate

Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)

Force exerted by the jet normal to the plate
  Fn = ρaV2.sinθ
Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)

-Force exerted by jet on moving flat plate normal to jet

Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)

u = plate velocity, v= jet velocity
F= ρa(V – u)2
Work done per second (W) = Fn × u = ρa[V – u]2 × u

-Jet strikes on series of flat plat mounted on the peripehry of wheel

Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)

Fn = ρaV(V – u)
Work done by the jet = Fn × U
W = ρaV(V – u)u
Efficiency of the work done of wheel=Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)
At, u = V/2 ; ηmax = 50%

-Jet striking on a symmetrical stationary curved plate

Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)


Fn = ρaV2 (1 + cosθ)

Force exerted by a jet in its direction of flow on a curved vane is always greater than that exerted on a flat plate.

-Force Exerted By a jet on a Hinged Plate

     Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE)
-Force due to jet of water, normal to the plate

    Pn = ρaV2 sin (90º –θ)
-For equilibrium of plate

sinθ=ρav2/W
W= weight of the plate

The document Impulse of Jets | Civil Engineering SSC JE (Technical) - Civil Engineering (CE) is a part of the Civil Engineering (CE) Course Civil Engineering SSC JE (Technical).
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FAQs on Impulse of Jets - Civil Engineering SSC JE (Technical) - Civil Engineering (CE)

1. What is the impulse of a jet?
Ans. The impulse of a jet refers to the change in momentum of an object due to the force exerted by the jet. It is equal to the force multiplied by the time interval over which it acts.
2. How is the impulse of a jet calculated?
Ans. The impulse of a jet can be calculated using the formula: Impulse = Force × Time. The force is the strength of the jet, and the time is the duration over which the force is applied.
3. What factors affect the impulse of a jet?
Ans. Several factors can affect the impulse of a jet, including the force exerted by the jet, the duration of the force application, and the mass of the object on which the jet is acting. These factors determine the change in momentum and hence the impulse.
4. What are some practical applications of the impulse of jets?
Ans. The impulse of jets has various practical applications. It is utilized in the propulsion systems of aircraft, where the impulse generated by jet engines enables forward motion. It is also used in water propulsion systems, such as waterjet propulsion for boats and ships.
5. How does the impulse of jets relate to Newton's third law of motion?
Ans. The impulse of jets follows Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. When a jet exerts a force on an object, the object exerts an equal and opposite force on the jet. This exchange of forces results in a change in momentum and the impulse of the jet.
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