Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

Class 11 Chemistry 35 Years JEE Mains &Advance Past yr Paper

JEE : Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

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Q.1. The total number of cyclic structural as well as stereo isomers possible for a compound with the molecular formula C5H10 is

Ans. 7

Solution. The seven possible cyclic structural and stereoisomers are

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRevInteger Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRevInteger Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev


Q. 2. The total number of cyclic isomers possible for a hydrocarbon with the molecular formula C4H6 is 5.

Ans. 5

Solution. The number of cyclic isomers for a hydr ocarbon with molecular formula C4H6 is 5.

The structures are

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRevInteger Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev


Q. 3. The maximum number of isomers (including stereoisomers) that are possible on monochlorination of the following compound is

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

Ans. 8

Solution.

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev   Enantiomeric pair = 2
Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev        Two enantiomeric pairs = 4
Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev      = 1
Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev     = 1 

Total = 2 + 4 + 1 + 1 = 8


Q. 4. The total number of contributing structures showing hyperconjugation (involving C-H bonds) for the following carbocation is

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

Ans. 6

Solution.

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

a = 3 Hyperconjugative H's
b = 2 Hyperconjugative H's
c = 1 Hyperconjugative H


Q. 5. The total number(s) of stable conformers with non-zero dipole moment for the following compound is (are)

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

Ans. 3

Solution. 

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

Following three conformers (with μ ≠ 0) are possible

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRevInteger Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev


Q. 6. The total number of stereoisomers that can exist for M is

Ans. 2

Solution. The molecule cannot show geometrical isomerism, so only its mirror image will be the other stereoisomer.

Integer Answer Type Questions: Organic Chemistry - Some Basic Principles & Technique | JEE Advanced Notes | EduRev

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