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Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE PDF Download

Q.1. Based on VSEPR theory, the number of 90 degree F–Br–F angles in BrF5 is (2010)

Ans. (0)

Sol. According to VSEPR theory, number of electron pairs around central atom (Br) are 6.

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE(Five are bond pairs and one is lone pair ) Its geometry is octahedral but due to lone pair –bond pair repulsion, the four fluorine atoms at corner are forced towards the upper fluorine atom thus reducing F–Br–F angle from 90° to 84.8°.

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

 

Q.2. The total number of lone-pairs of electrons in melamine is (JEE Adv. 2013)

Ans. (6)

Sol.  Structure of melamine is as follows :

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Total no. of lone pairs of electron is ‘6’.

 

Q.3. A list of species having the formula XZ4 is given below.
 XeF4, SF4, SiF4, BF4, BrF4, [Cu(NH3)4]2+, [FeCl4]2–, [CoCl4]2– and [PtCl4]2–.
 Defining shape on the basis of the location of X and Z atoms, the total number of species having a square planar shape is (JEE Adv. 2014)

Ans.  (4)

Sol.

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                         Square planar (sp3d2)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                        See-saw (sp3d)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                      Tetrahedral (sp3)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                        Tetrahedral (sp3)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                     Square planar (sp3d2)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE          Square planar (dsp2)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                     Tetrahedral (sp3)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                      Tetrahedral (sp3)

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE                      Square planar (dsp2)

 

4. Among the triatomic molecules/ions, BeCl2, N3, N2O, NO2+, O3, SCl2, ICl2– , I3– and XeF2, the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is [Atomic number : S = 16, Cl = 17, I = 53 and Xe = 54] (JEE Adv. 2015)

Ans.  (4) 

Sol.

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Chemical Bonding & Molecular Structure | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Only BeCl2, N3, N2O and NO2 are linear with sp-hybridisation.

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FAQs on Integer Answer Type Questions: Chemical Bonding & Molecular Structure - JEE Advanced - 35 Years Chapter wise Previous Year Solved Papers for JEE

1. What is a chemical bond?
Ans. A chemical bond is a force of attraction between two atoms that holds them together in a molecule or compound. It is formed when atoms share or transfer electrons to achieve a stable electron configuration.
2. What are the different types of chemical bonds?
Ans. There are three main types of chemical bonds: ionic bonds, covalent bonds, and metallic bonds. Ionic bonds involve the transfer of electrons between atoms, covalent bonds involve the sharing of electrons, and metallic bonds occur between metal atoms and involve the delocalization of electrons.
3. How does the octet rule apply to chemical bonding?
Ans. The octet rule states that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration with eight valence electrons. This rule helps explain the formation of chemical bonds, as atoms will interact with each other to achieve a full outer electron shell.
4. What is the difference between polar and nonpolar covalent bonds?
Ans. In a polar covalent bond, the electrons are shared unequally between the atoms, resulting in a separation of charge and the formation of a dipole. In a nonpolar covalent bond, the electrons are shared equally between the atoms, resulting in no separation of charge and no dipole formation.
5. How do intermolecular forces affect the properties of substances?
Ans. Intermolecular forces are the forces of attraction between molecules. These forces determine properties such as boiling point, melting point, and solubility. Strong intermolecular forces result in higher boiling and melting points, while weak intermolecular forces result in lower boiling and melting points. Additionally, intermolecular forces play a crucial role in determining whether substances are soluble in a particular solvent.
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