Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

I. E. Irodov Solutions for Physics Class 11 & Class 12

JEE : Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

The document Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev is a part of the JEE Course I. E. Irodov Solutions for Physics Class 11 & Class 12.
All you need of JEE at this link: JEE

Q.81. A conductor in the shape of a square frame with side a suspended by an elastic thread is located in a uniform horizontal magnetic field with induction B. In equilibrium the plane of the frame is parallel to the vector B (Fig. 4.25). Having been displaced from the equilibrium position, the frame performs small oscillations about a vertical axis passing through its centre. The moment of inertia of the frame relative to that axis is equal to I, its electric resistance is R. Neglecting the inductance of the frame, find the time interval after which the amplitude of the frame's deviation angle decreases e-fold.

Ans. If φ = angle of deviation of the frame from its normal position, then an e.m.f.
Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

is induced in the frame in the displaced position and a current Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev flows in it. A couple

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

then acts on the frame in addition to any elastic restoring couple c φ. We write the equation of the frame as

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 Thus Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev where β is defined in the book.

Amplitude of oscillation die out according to Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev so time required for the oscillations to decrease toIrodov Solutions: Mechanical Oscillations- 7 Notes | EduRev of its value is 

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.82. A bar of mass m = 0.50 kg lying on a horizontal plane with a friction coefficient k = 0.10 is attached to the wall by means of a horizontal non-deformed spring. The stiffness of the spring is equal to x = 2.45 N/cm, its mass is negligible. The bar was displaced so that the spring was stretched by x0 = 3.0 cm, and then released. Find:
 (a) the period of oscillation of the bar;
 (b) the total number of oscillations that the bar performs until it stops completely.

Ans. We shall denote the stiffness constant by k . Suppose the spring is stretched by x0 . The bar in then subject to two horizontal forces (1) restorin g force - k x and (2) friction kmg opposing motion. If  
Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 the bar will come back.

(If x0 ≤ Δ , the bar will stay put) The equation of the bar when it is moving to the left is

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

This equation has the solution

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

where we have used Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev This solution is only valid till the bar comes to rest. This happens at

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

and at that time  Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev  the tendency of the rod will now be to move to the right . (if Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev the rod will stay put now) Now the equation for rightward motion becomes'*

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

(the friction force has reversed ).

We notice that the rod will move to the right only if

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

In this case the solution is

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

The rod will next come to rest at

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

and at that instant Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev. How ever the rod will stay put unless x0 > 5Δ. Thus

(a) time period of one full oscillation   Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

(b) There is no oscillation if 0 < x0 < Δ     

One half oscillation if Δ < x0 < 3Δ

2 half oscillation if 3Δ < x0< 5Δ etc.
We can say that the number of full oscillations is one half of the integer n

whereIrodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

where [ x ] = smallest non-negative integer greater than x.

 

Q.83. A ball of mass m can perform undamped harmonic oscillations about the point x = 0 with natural frequency ωo. At the moment t = 0, when the ball was in equilibrium, a force Fx = F cos ωt coinciding with the x axis was applied to it. Find the law of forced oscillation x (t) for that ball. 

Ans. The equation of motion of the ball is

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev.

This equation has the solution

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

where A and a are arbitrary and B is obtained by substitution in the above equation

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.84. A particle of mass m can perform undamped harmonic oscillations due to an electric force with coefficient k. When the particle was in equilibrium, a permanent force F was applied to it for δ seconds. Find the oscillation amplitude that the particle acquired after the action of the force ceased. Draw the approximate plot x (t) of oscillations. Investigate possible cases.

Ans. We have to look for solutions of the equation

 Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

The solution of this equation will be sought in the form

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 A and α will be determined from the boundary condition at t = 0.

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Thus Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.85. A ball of mass m, when suspended by a spring stretches the latter by Δl. Due to external vertical force varying according to a harmonic law with amplitude F0  the ball performs forced oscillations. The logarithmic damping decrement is equal to λ. Neglecting the mass of the spring, find the angular frequency of the external force at which the displacement amplitude of the ball is maximum. What is the magnitude of that amplitude? 

Ans. Foi the spring Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 where k is its stifiiess coefficient. Thus

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

The equation of motion of the ball is

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

To find the solution of the above equation we look for the solution of the auxiliary equation

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Clearly we can take Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev Now we look for a particular integral for z of the form

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Thus, substitution gives A and we get

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

so taking the real part

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

The amplitude of this oscillation is maximum when the denominator is minimum. Tthis happens when

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.86. The forced harmonic oscillations have equal displacement amplitudes at frequencies ω1 = 400 s-1  and ω= 600s-1 . Find the resonance frequency at which the displacement amplitude is maximum. 

Ans.

 Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Q.87. The velocity amplitude of a particle is equal to half the maximum value at the frequencies ω1  and ω2 of external harmonic force. Find:
 (a) the frequency corresponding to the velocity resonance;
 (b) the damping coefficient β and the damped oscillation frequency co of the particle. 

Ans.

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Thus the velocity amplitude is

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

This is maximum whenIrodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

and then Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 where we have rejected a solution with - ve sign before there dical. Writing

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRevand damped oscillation frequency

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.88. A certain resonance curve describes a mechanical oscillating system with logarithmic damping decrement λ = 1.60. For this curve find the ratio of the maximum displacement amplitude to the displacement amplitude at a very low frequency. 

Ans. In general for displacement amplitude

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

HenceIrodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.89. Due to the external vertical force Fx  = F cos ωt a body suspended by a spring performs forced steady-state oscillations according to the law x = a cos (ωt — φ). Find the work performed by the force F during one oscillation period. 

Ans. The work done in one cycle is

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.90. A ball of mass m = 50 g is suspended by a weightless spring with stiffness x = 20.0 N/m. Due to external vertical harmonic force with frequency ω = 25.0 s-1  the ball performs steady-state oscillations with amplitude a = 1.3 cm. In this case the displace- ment of the ball lags in phase behind the external force by

  Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Find: (a) the quality factor of the given oscillator; (b) the work performed by the external force during one oscillation period. 

Ans. In the formula Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

we have

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Thus  Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Hence Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

and (a) the quality factor

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 (b) work done is 

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.91. A ball of mass m suspended by a weightless spring can perform vertical oscillations with damping coefficient β. The natural oscillation frequency is equal to ω0. Due to the external vertical force varying as Fx = Fo , cos ωt the ball performs steady-state harmonic oscillations. Find:
 (a) the mean power (P), developed by the force F, averaged over one oscillation period;
 (b) the frequency ω of the force F at which (P) is maximum; what is (P)max equal to? 

Ans. Here as usual   Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRevwhere φ is the phase lag of the displacement

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

(a) Mean power developed by the force over one oscillation period

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

(b) Mean power < P > is maximum when ω = ω0 (for the denominator is then minimuir Also

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Q.92. An external harmonic force F whose frequency can be varied, with amplitude maintained constant, acts in a vertical direction on a ball suspended by a weightless spring. The damping coefficient is times less than the natural oscillation frequency ωo of the ball. How much, in per cent, does the mean power (P) developed by the force F at the frequency of displacement resonance differ from the maximum mean power (P)max?  Averaging is performed over one oscillation period. 

Ans. Given Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRevThen from the previous problem

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

At displacement resonance Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

  

Q.93. A uniform horizontal disc fixed at its centre to an elastic vertical rod performs forced torsional oscillations due to the moment of forces Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev The oscillations obey the law φ Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev Find: (a) the work performed by friction forces acting on the disc during one oscillation period; (b) the quality factor of the given oscillator if the moment of inertia of the disc relative to the axis is equal to I. 

Ans. The equation of the disc is
Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Then as before

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

where

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

 (a) Work performed by frictional forces

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

(b) The quality factor

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Related Searches

practice quizzes

,

Important questions

,

Objective type Questions

,

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

,

mock tests for examination

,

Sample Paper

,

Free

,

Extra Questions

,

Viva Questions

,

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

,

Summary

,

pdf

,

Irodov Solutions: Mechanical Oscillations- 7 Notes | EduRev

,

Semester Notes

,

ppt

,

video lectures

,

Exam

,

study material

,

MCQs

,

shortcuts and tricks

,

Previous Year Questions with Solutions

,

past year papers

;