JEE Advanced Previous Year Questions (2021-2023): p-block Elements | Chemistry for JEE Main & Advanced PDF Download

 Page 1


JEE Advanced Previous Year Questions 
(2021-2023): p-block Elements 
2023 
Single Correct Type 
JEE Advanced 2023 Paper 1 Online 
Q1. MCQ (Single Correct Answer) +?? - ?? 
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their 
products given in List-II and choose the correct option. 
 
List - I List - II 
(P) ?? ?? ?? ?? + ?? ?? ?? ?? ? (1) ?? (?? )(?????? ?? )????
?? 
(Q) ?? ?? + ?????????? + ?? ?? ?? ?? ? (2) ?? ?? ????
?? 
(R) ?????? ?? + ????
?? ???????? ? (3) ????
?? 
(S) ?? ?? ????
?? + ?? ?? ?? ?? + ?? ???????? ?? ? (4) ???????? ?? 
 (5) ?? ?? ????
?? 
 
A. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
Ans: (D) 
P
2
O
3
+ 3H
2
O ? H
3
PO
3
, P ? 2 
P
4
+ 3NaOH + 3H
2
O ? PH
3
+ NaH
2
PO
2
, Q ? 3 
PCl
5
+ CH
3
COOH ? CH
3
COCl + POCl
3
, R ? 4 
H
3
PO
2
+ 2H
2
O + 4AgNO
3
? H
3
PO
4
+ Ag + HNO
3
,  S ? 5 
 
Page 2


JEE Advanced Previous Year Questions 
(2021-2023): p-block Elements 
2023 
Single Correct Type 
JEE Advanced 2023 Paper 1 Online 
Q1. MCQ (Single Correct Answer) +?? - ?? 
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their 
products given in List-II and choose the correct option. 
 
List - I List - II 
(P) ?? ?? ?? ?? + ?? ?? ?? ?? ? (1) ?? (?? )(?????? ?? )????
?? 
(Q) ?? ?? + ?????????? + ?? ?? ?? ?? ? (2) ?? ?? ????
?? 
(R) ?????? ?? + ????
?? ???????? ? (3) ????
?? 
(S) ?? ?? ????
?? + ?? ?? ?? ?? + ?? ???????? ?? ? (4) ???????? ?? 
 (5) ?? ?? ????
?? 
 
A. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
Ans: (D) 
P
2
O
3
+ 3H
2
O ? H
3
PO
3
, P ? 2 
P
4
+ 3NaOH + 3H
2
O ? PH
3
+ NaH
2
PO
2
, Q ? 3 
PCl
5
+ CH
3
COOH ? CH
3
COCl + POCl
3
, R ? 4 
H
3
PO
2
+ 2H
2
O + 4AgNO
3
? H
3
PO
4
+ Ag + HNO
3
,  S ? 5 
 
2022 
Numerical Type  
JEE Advanced 2022 Paper 1 Online 
Q1. Dissolving ?? . ???? ?? of white phosphorous in boiling ???????? solution in an inert atmosphere 
gives a gas ?? . The amount of ???????? ?? (in ?? ) required to completely consume the gas ?? is 
[Given: Atomic mass of ?? = ?? , ?? = ???? , ???? = ???? , ?? = ???? , ?? = ???? , ???? = ???? ] 
Ans: 2.37 to 2.41 
 
P
4
1.24 g
 or 
0.01 mole 
+ 3NaOH + 3H
2
O ? PH
3
+ 3NaH
2
PO
2
 
As NaOH is present in excess. So, amount of phosphine formed is 0.01 mole (as P
4
 is limiting) 
2PH
3
0.01 mole 
+ 3CuSO
4
? Cu
3
P
2
+ 3H
2
SO
4
 
Amount of CuSO
4
 required =
3×0.01
2
 mole 
Mass of CuSO
4
(in g) required =
0.03
2
× (63 + 32 + 16 × 4) 
=
0.03
2
× 159 = 2.38 g, 
 
JEE Advanced 2022 Paper 2 Online 
Q2.The reaction of ???????? ?? with ?????? gives a paramagnetic gas, which upon reaction with ?? ?? 
produces 
(A) ????
?? ?? 
(B) ?????? ?? 
(C) ????
?? ?? ?? 
(D) ????
?? ?? ?? 
Ans: (C) 
HClO
3
 reacts with HCl according to the following equation, 
2HClO
3
+ 2HCl ? 2ClO
2
+ Cl
2
+ 2H
2
O 
ClO
2
 molecule is paramagnetic, as it contains odd number of electrons. 
2ClO
2
+ 2O
3
? Cl
2
O
6
+ 2O
2
 
 
JEE Advanced 2022 Paper 2 Online 
Q3. The reaction of ???? (????
?? )
?? and ???????? in water produces a precipitate that dissolves upon the 
addition of ?????? of appropriate concentration. The dissolution of the precipitate is due to the 
formation of 
(A) ???????? ?? 
(B) ?? ?????? ?? 
(C) [???????? ?? ]
?? -
 
(D) [???????? ?? ]
?? -
 
Page 3


JEE Advanced Previous Year Questions 
(2021-2023): p-block Elements 
2023 
Single Correct Type 
JEE Advanced 2023 Paper 1 Online 
Q1. MCQ (Single Correct Answer) +?? - ?? 
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their 
products given in List-II and choose the correct option. 
 
List - I List - II 
(P) ?? ?? ?? ?? + ?? ?? ?? ?? ? (1) ?? (?? )(?????? ?? )????
?? 
(Q) ?? ?? + ?????????? + ?? ?? ?? ?? ? (2) ?? ?? ????
?? 
(R) ?????? ?? + ????
?? ???????? ? (3) ????
?? 
(S) ?? ?? ????
?? + ?? ?? ?? ?? + ?? ???????? ?? ? (4) ???????? ?? 
 (5) ?? ?? ????
?? 
 
A. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
Ans: (D) 
P
2
O
3
+ 3H
2
O ? H
3
PO
3
, P ? 2 
P
4
+ 3NaOH + 3H
2
O ? PH
3
+ NaH
2
PO
2
, Q ? 3 
PCl
5
+ CH
3
COOH ? CH
3
COCl + POCl
3
, R ? 4 
H
3
PO
2
+ 2H
2
O + 4AgNO
3
? H
3
PO
4
+ Ag + HNO
3
,  S ? 5 
 
2022 
Numerical Type  
JEE Advanced 2022 Paper 1 Online 
Q1. Dissolving ?? . ???? ?? of white phosphorous in boiling ???????? solution in an inert atmosphere 
gives a gas ?? . The amount of ???????? ?? (in ?? ) required to completely consume the gas ?? is 
[Given: Atomic mass of ?? = ?? , ?? = ???? , ???? = ???? , ?? = ???? , ?? = ???? , ???? = ???? ] 
Ans: 2.37 to 2.41 
 
P
4
1.24 g
 or 
0.01 mole 
+ 3NaOH + 3H
2
O ? PH
3
+ 3NaH
2
PO
2
 
As NaOH is present in excess. So, amount of phosphine formed is 0.01 mole (as P
4
 is limiting) 
2PH
3
0.01 mole 
+ 3CuSO
4
? Cu
3
P
2
+ 3H
2
SO
4
 
Amount of CuSO
4
 required =
3×0.01
2
 mole 
Mass of CuSO
4
(in g) required =
0.03
2
× (63 + 32 + 16 × 4) 
=
0.03
2
× 159 = 2.38 g, 
 
JEE Advanced 2022 Paper 2 Online 
Q2.The reaction of ???????? ?? with ?????? gives a paramagnetic gas, which upon reaction with ?? ?? 
produces 
(A) ????
?? ?? 
(B) ?????? ?? 
(C) ????
?? ?? ?? 
(D) ????
?? ?? ?? 
Ans: (C) 
HClO
3
 reacts with HCl according to the following equation, 
2HClO
3
+ 2HCl ? 2ClO
2
+ Cl
2
+ 2H
2
O 
ClO
2
 molecule is paramagnetic, as it contains odd number of electrons. 
2ClO
2
+ 2O
3
? Cl
2
O
6
+ 2O
2
 
 
JEE Advanced 2022 Paper 2 Online 
Q3. The reaction of ???? (????
?? )
?? and ???????? in water produces a precipitate that dissolves upon the 
addition of ?????? of appropriate concentration. The dissolution of the precipitate is due to the 
formation of 
(A) ???????? ?? 
(B) ?? ?????? ?? 
(C) [???????? ?? ]
?? -
 
(D) [???????? ?? ]
?? -
 
Ans: (C) 
Pb
2+
 on reaction with Cl
-
, produces white precipitate of PbCl
2
 
Pb
2+
+ 2Cl
-
? PbCl
2
? (White) 
This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate (II) 
ion 
PbCl
2
? +2Cl
-
? [PbCl
4
]
2-
 
Multiple Correct Type 
JEE Advanced 2022 Paper 2 Online 
Q4. The compound(s) which react(s) with ????
?? to give boron nitride (BN) is(are) 
A. ?? 
B. ?? ?? ?? ?? 
C. ?? ?? ?? ?? 
D. ?????? ?? 
Ans: (A,B,C) 
The compound(s) which react with NH
3
 to form Boron nitride (BN) is/are: 
(A) Amorphous B + NH
3
?
 Very high 
 Tempreature 
BN + H
2
 
(B) B
2
H
6
+ NH
3
?
,?????? h ?????????????????????? (BN)
x
 
(C) B
2
O
3
+ 2NH
3
?
900 deg ?? 2BN + 3H
2
O 
(D) HBF
4
+ NH
3
? [NH
4
?
][BF
4
?
] 
Hence, (?? , ?? , ?? ) are correct 
 
 
 
 
 
 
 
 
Page 4


JEE Advanced Previous Year Questions 
(2021-2023): p-block Elements 
2023 
Single Correct Type 
JEE Advanced 2023 Paper 1 Online 
Q1. MCQ (Single Correct Answer) +?? - ?? 
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their 
products given in List-II and choose the correct option. 
 
List - I List - II 
(P) ?? ?? ?? ?? + ?? ?? ?? ?? ? (1) ?? (?? )(?????? ?? )????
?? 
(Q) ?? ?? + ?????????? + ?? ?? ?? ?? ? (2) ?? ?? ????
?? 
(R) ?????? ?? + ????
?? ???????? ? (3) ????
?? 
(S) ?? ?? ????
?? + ?? ?? ?? ?? + ?? ???????? ?? ? (4) ???????? ?? 
 (5) ?? ?? ????
?? 
 
A. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? 
Ans: (D) 
P
2
O
3
+ 3H
2
O ? H
3
PO
3
, P ? 2 
P
4
+ 3NaOH + 3H
2
O ? PH
3
+ NaH
2
PO
2
, Q ? 3 
PCl
5
+ CH
3
COOH ? CH
3
COCl + POCl
3
, R ? 4 
H
3
PO
2
+ 2H
2
O + 4AgNO
3
? H
3
PO
4
+ Ag + HNO
3
,  S ? 5 
 
2022 
Numerical Type  
JEE Advanced 2022 Paper 1 Online 
Q1. Dissolving ?? . ???? ?? of white phosphorous in boiling ???????? solution in an inert atmosphere 
gives a gas ?? . The amount of ???????? ?? (in ?? ) required to completely consume the gas ?? is 
[Given: Atomic mass of ?? = ?? , ?? = ???? , ???? = ???? , ?? = ???? , ?? = ???? , ???? = ???? ] 
Ans: 2.37 to 2.41 
 
P
4
1.24 g
 or 
0.01 mole 
+ 3NaOH + 3H
2
O ? PH
3
+ 3NaH
2
PO
2
 
As NaOH is present in excess. So, amount of phosphine formed is 0.01 mole (as P
4
 is limiting) 
2PH
3
0.01 mole 
+ 3CuSO
4
? Cu
3
P
2
+ 3H
2
SO
4
 
Amount of CuSO
4
 required =
3×0.01
2
 mole 
Mass of CuSO
4
(in g) required =
0.03
2
× (63 + 32 + 16 × 4) 
=
0.03
2
× 159 = 2.38 g, 
 
JEE Advanced 2022 Paper 2 Online 
Q2.The reaction of ???????? ?? with ?????? gives a paramagnetic gas, which upon reaction with ?? ?? 
produces 
(A) ????
?? ?? 
(B) ?????? ?? 
(C) ????
?? ?? ?? 
(D) ????
?? ?? ?? 
Ans: (C) 
HClO
3
 reacts with HCl according to the following equation, 
2HClO
3
+ 2HCl ? 2ClO
2
+ Cl
2
+ 2H
2
O 
ClO
2
 molecule is paramagnetic, as it contains odd number of electrons. 
2ClO
2
+ 2O
3
? Cl
2
O
6
+ 2O
2
 
 
JEE Advanced 2022 Paper 2 Online 
Q3. The reaction of ???? (????
?? )
?? and ???????? in water produces a precipitate that dissolves upon the 
addition of ?????? of appropriate concentration. The dissolution of the precipitate is due to the 
formation of 
(A) ???????? ?? 
(B) ?? ?????? ?? 
(C) [???????? ?? ]
?? -
 
(D) [???????? ?? ]
?? -
 
Ans: (C) 
Pb
2+
 on reaction with Cl
-
, produces white precipitate of PbCl
2
 
Pb
2+
+ 2Cl
-
? PbCl
2
? (White) 
This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate (II) 
ion 
PbCl
2
? +2Cl
-
? [PbCl
4
]
2-
 
Multiple Correct Type 
JEE Advanced 2022 Paper 2 Online 
Q4. The compound(s) which react(s) with ????
?? to give boron nitride (BN) is(are) 
A. ?? 
B. ?? ?? ?? ?? 
C. ?? ?? ?? ?? 
D. ?????? ?? 
Ans: (A,B,C) 
The compound(s) which react with NH
3
 to form Boron nitride (BN) is/are: 
(A) Amorphous B + NH
3
?
 Very high 
 Tempreature 
BN + H
2
 
(B) B
2
H
6
+ NH
3
?
,?????? h ?????????????????????? (BN)
x
 
(C) B
2
O
3
+ 2NH
3
?
900 deg ?? 2BN + 3H
2
O 
(D) HBF
4
+ NH
3
? [NH
4
?
][BF
4
?
] 
Hence, (?? , ?? , ?? ) are correct 
 
 
 
 
 
 
 
 
2021 
JEE Advanced 2021 Paper 2 Online 
Q6. The correct statement(s) related to oxoacids of phosphorous is(are) 
A. Upon heating, ?? ?? ????
?? undergoes disproportionation reaction to produce ?? ?? ????
?? and ????
?? . 
B. While ?? ?? ????
?? can act as reducing agent, ?? ?? ????
?? cannot. 
C. ?? ?? ????
?? is a monobasic acid. 
D. The ?? atom of ?? - ?? bond in ?? ?? ????
?? is not ionizable in water. 
Ans: (A,B,D) 
(a) H
3
PO
3
 gives H
3
PO
4
 and PH
3
 on heating. This reaction is known as disproportionation reaction. 
4H
3
PO
3
? 3H
3
PO
4
+ PH
3
 
(b) P in H
3
PO
4
 is in its highest oxidation state i.e. +5 hence, it cannot act as reducing agent. But P in 
H
3
PO
3
 is in oxidation state, +3 hence, it can act as reducing agent. 
(c) H
3
PO
3
 contains two -OH groups, hence it is a dibasic acid. 
 
(d) Hydrogen attached to P, does not ionise in water. Therefore, options (a), (b) and (d) are correct.