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2021 
Numerical Type 
JEE Advanced 2021 Paper 2 Online 
Q1. A sample (?? . ?? ?? ) containing iron is completely dissolved in cold dilute ?????? to prepare a 
?????? ???? of solution. Titration of ???? . ?? ???? of this solution requires ???? . ?? ???? of ?? . ?????????????? 
?? 
solution to reach the end point. Number of moles of ????
?? +
 present in ?????? ???? solution is ?? × ????
-?? 
(consider complete dissolution of ????????
?? ). The amount of iron present in the sample is ?? % by 
weight. 
(Assume : ???????? ?? reacts only with ????
?? +
 in the solution 
Use : Molar mass of iron as ???? ?? ?????? -?? ) 
The value of ?? is 
Ans: 1.875 
Fe
(?? ×10
-2
?????? )
+ 2HCl ? FeCl
2
(?? ×10
-2
 mol)
+ H
2
 
Concentration of Fe
2+
, ?? 1
=
?? ×10
-2
250
× 1000 
=
10?? 250
?? =
?? 25
?? 
Volume of Fe
2+
 solution titrated, V
1
= 25.0 mL 
Concentration of MnO
4
-
, M
2
= 0.03M 
Volume of MnO
4
-
used, V
2
= 12.5 mL 
5Fe
2+
+ MnO
4
-
? Mn
2+
+ 5Fe
3+
 
Using relation, 
?? 1
?? 1
?? 1
=
?? 2
?? 2
?? 2
 
?? 2
?? 1
?? 1
= ?? 1
?? 2
?? 2
 [ ?? 1
 and ?? 2
 are number of moles of Fe
2+
 and MnO
4
-
reacting] 
1 ×
?? 25
× 25 = 5 × 0.03 × 12.5 ? ?? = 1.88 
The volume of x is 1.88 . 
JEE Advanced 2021 Paper 2 Online 
Q2. A sample (?? . ?? ?? ) containing iron is completely dissolved in cold dilute ?????? to prepare a 
?????? ?? ?? of solution. Titration of ???? . ?? ???? of this solution requires ???? . ?? ???? of ?? . ?????????????? ?? ?? 
solution to reach the end point. Number of moles of ????
?? +
 present in ?????? ???? solution is ?? × ????
-?? 
Page 2


 
2021 
Numerical Type 
JEE Advanced 2021 Paper 2 Online 
Q1. A sample (?? . ?? ?? ) containing iron is completely dissolved in cold dilute ?????? to prepare a 
?????? ???? of solution. Titration of ???? . ?? ???? of this solution requires ???? . ?? ???? of ?? . ?????????????? 
?? 
solution to reach the end point. Number of moles of ????
?? +
 present in ?????? ???? solution is ?? × ????
-?? 
(consider complete dissolution of ????????
?? ). The amount of iron present in the sample is ?? % by 
weight. 
(Assume : ???????? ?? reacts only with ????
?? +
 in the solution 
Use : Molar mass of iron as ???? ?? ?????? -?? ) 
The value of ?? is 
Ans: 1.875 
Fe
(?? ×10
-2
?????? )
+ 2HCl ? FeCl
2
(?? ×10
-2
 mol)
+ H
2
 
Concentration of Fe
2+
, ?? 1
=
?? ×10
-2
250
× 1000 
=
10?? 250
?? =
?? 25
?? 
Volume of Fe
2+
 solution titrated, V
1
= 25.0 mL 
Concentration of MnO
4
-
, M
2
= 0.03M 
Volume of MnO
4
-
used, V
2
= 12.5 mL 
5Fe
2+
+ MnO
4
-
? Mn
2+
+ 5Fe
3+
 
Using relation, 
?? 1
?? 1
?? 1
=
?? 2
?? 2
?? 2
 
?? 2
?? 1
?? 1
= ?? 1
?? 2
?? 2
 [ ?? 1
 and ?? 2
 are number of moles of Fe
2+
 and MnO
4
-
reacting] 
1 ×
?? 25
× 25 = 5 × 0.03 × 12.5 ? ?? = 1.88 
The volume of x is 1.88 . 
JEE Advanced 2021 Paper 2 Online 
Q2. A sample (?? . ?? ?? ) containing iron is completely dissolved in cold dilute ?????? to prepare a 
?????? ?? ?? of solution. Titration of ???? . ?? ???? of this solution requires ???? . ?? ???? of ?? . ?????????????? ?? ?? 
solution to reach the end point. Number of moles of ????
?? +
 present in ?????? ???? solution is ?? × ????
-?? 
(consider complete dissolution of ????????
?? ). The amount of iron present in the sample is ?? % by 
weight. 
(Assume : ???????? ?? reacts only with ????
?? +
 in the solution 
Use : Molar mass of iron as ???? ?? ?????? -?? ) 
The value of ?? is 
Ans: 18.75 
Explanation 
Mass of sample = 5.6 g 
Number of moles of Fe = 1.88 × 10
-2
 mol 
Molar mass of Fe = 56 g/mol 
Mass of Fe = Moles of Fe × Molar mass 
= 1.88 × 10
-2
× 56 = 1.05 g 
%Fe =
 Mass of Fe 
 Mass of sample 
× 100 =
1.05
5.6
× 100 
? y = 18.75% 
The value of y is 18.75 . 
JEE Advanced 2021 Paper 2 Online 
Q3. Ozonolysis of ?????? ?? produces an oxide of chlorine. The average oxidation state of chlorine 
in this oxide is 
Ans: 6 
2ClO
2
 Chlorine dioxide 
+ 2O
3
? Cl
2
O
6
 Chloral perchlorate 
+ 2O
2
 
Oxidation state of Cl
in 
Cl
2
O
6
= 2x + 6(-2) = 0 
2?? - 12 = 0 
2?? = 12 ? ?? = +6 
Average oxidation state of Cl in Cl
2
O
6
 is 6 . 
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FAQs on JEE Advanced Previous Year Questions (2021 - 2024): Redox Reactions - Chemistry for JEE Main & Advanced

1. What are redox reactions and how do they differ from other types of chemical reactions?
Ans.Redox reactions, or reduction-oxidation reactions, are processes in which the oxidation states of atoms are changed. These reactions involve the transfer of electrons between two species; one species gets oxidized (loses electrons) while the other gets reduced (gains electrons). Unlike other types of chemical reactions, redox reactions are characterized by changes in oxidation numbers, making them essential in various chemical and biological processes.
2. How can I identify oxidation and reduction in redox reactions?
Ans.Oxidation and reduction can be identified by changes in oxidation states of the elements involved. To determine this, assign oxidation states to all atoms in the reaction. An increase in oxidation state indicates oxidation, while a decrease indicates reduction. Additionally, you can look for the addition of oxygen (oxidation) or the removal of oxygen (reduction) as another method of identification.
3. What is the significance of balancing redox reactions in JEE Advanced?
Ans.Balancing redox reactions is crucial in JEE Advanced as it demonstrates a clear understanding of the conservation of mass and charge. In competitive exams, balanced equations are often required to solve stoichiometric problems, calculate yields, and predict the outcomes of reactions. Mastering the balancing of these reactions using half-reaction methods or oxidation state changes is essential for success in the exam.
4. What are some common redox reactions that I should study for JEE Advanced?
Ans.Some common redox reactions to study for JEE Advanced include the reaction between hydrogen and oxygen to form water, the reaction of metals with acids (like zinc with hydrochloric acid), and the rusting of iron. Other important redox systems include the electrolysis of water and the reactions involved in batteries, such as the lead-acid battery. Understanding these reactions will help in grasping the concepts effectively.
5. How do redox reactions relate to electrochemistry, which is part of the JEE syllabus?
Ans.Redox reactions are fundamental to electrochemistry, as they involve the transfer of electrons that generates electric current. In electrochemical cells, oxidation occurs at the anode and reduction at the cathode. Understanding the connection between redox reactions and electrochemical principles is crucial for solving problems related to galvanic cells, electrolytic cells, and electrode potentials in the JEE syllabus.
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