JEE Main 2020 Chemistry January 7 Shift 1 Paper & Solutions | Mock Tests for JEE Main and Advanced 2025 PDF Download

 Page 1


     
    
    
    
     
 
                       
  
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. V 34 . 0 º E
Cu / Cu
2 ? ? 
 V 522 . 0 º E
Cu / Cu
? ? 
 ? ? ?
Cu / Cu
2 º E ? 
 (1) 0.158V   (2) –0.158 V  (3) 0.182 V    (4) –0.182 V  
Ans. (1) 
Sol. 
 
Cu
2+
 
º
1
E 
Cu
+
 
0.522 
Cu 
0.34 
 
 2 × 0.34 = 522 . 0 1 E
º
1
? ? 
 522 . 0 – 68 . 0 E
º
1
? 
 158 . 0 E
º
1
? 
 
2. Correct order of electron gain enthalpy (kJ/mole) of F, Cl, Br, I   
 F, Cl, Br, I  dh bySDVªkWu xzg.k ,UFkSYih (kJ/eksy) dk lgh Øe gS \  
 (1) –296, – 325, – 333, – 349 
 (2) –333, – 349, – 325, –296 
 (3) –349, – 333, – 325, – 296 
 (4) –325, – 333, – 349, – 296  
Ans. (2) 
 
3. Arrange the following in order of their pKb value  
 fuEu dks buds pKb eku ds Øe O;ofLFkr dhft, & 
 (A) 
 
N NH 
N 
  (B)  CH3 –NH –CH3  (C) CH3 –CH=NH     
 (1) A > B > C   (2) B > A  > C  (3) C > B > A   (4) B > C > A      
Ans. (3) 
Sol. Option "A" represent Guanadine, the conjugate acid of which is resonance stabilised. The option 'B' is 
aliphatic amine, here the 'N' is sp
3
 whereas in option 'C' the 'N' is sp
2
, hence B is more basic than C. 
fodYi "A" xqokusfMu izdkj dk ;kSfxd iznf'kZr djrk gS ftldk la;qXeh vEy vuqukn }kjk LFkk;hd`r gSA fodYi (B) 
,fyQsfVd ,ehu iznf'kZr djrk gSA ftlesa 'N' sp
3
 ladfjr gS tcfd fodYi 'C' esa 'N' sp
2
 ladfjr gSA vr% B, C dh 
rqyuk esa vfèkd {kkjh; gksxkA 
 
 
Page 2


     
    
    
    
     
 
                       
  
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. V 34 . 0 º E
Cu / Cu
2 ? ? 
 V 522 . 0 º E
Cu / Cu
? ? 
 ? ? ?
Cu / Cu
2 º E ? 
 (1) 0.158V   (2) –0.158 V  (3) 0.182 V    (4) –0.182 V  
Ans. (1) 
Sol. 
 
Cu
2+
 
º
1
E 
Cu
+
 
0.522 
Cu 
0.34 
 
 2 × 0.34 = 522 . 0 1 E
º
1
? ? 
 522 . 0 – 68 . 0 E
º
1
? 
 158 . 0 E
º
1
? 
 
2. Correct order of electron gain enthalpy (kJ/mole) of F, Cl, Br, I   
 F, Cl, Br, I  dh bySDVªkWu xzg.k ,UFkSYih (kJ/eksy) dk lgh Øe gS \  
 (1) –296, – 325, – 333, – 349 
 (2) –333, – 349, – 325, –296 
 (3) –349, – 333, – 325, – 296 
 (4) –325, – 333, – 349, – 296  
Ans. (2) 
 
3. Arrange the following in order of their pKb value  
 fuEu dks buds pKb eku ds Øe O;ofLFkr dhft, & 
 (A) 
 
N NH 
N 
  (B)  CH3 –NH –CH3  (C) CH3 –CH=NH     
 (1) A > B > C   (2) B > A  > C  (3) C > B > A   (4) B > C > A      
Ans. (3) 
Sol. Option "A" represent Guanadine, the conjugate acid of which is resonance stabilised. The option 'B' is 
aliphatic amine, here the 'N' is sp
3
 whereas in option 'C' the 'N' is sp
2
, hence B is more basic than C. 
fodYi "A" xqokusfMu izdkj dk ;kSfxd iznf'kZr djrk gS ftldk la;qXeh vEy vuqukn }kjk LFkk;hd`r gSA fodYi (B) 
,fyQsfVd ,ehu iznf'kZr djrk gSA ftlesa 'N' sp
3
 ladfjr gS tcfd fodYi 'C' esa 'N' sp
2
 ladfjr gSA vr% B, C dh 
rqyuk esa vfèkd {kkjh; gksxkA 
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 2 
 
4. 1-Methylethylene oxide 
HBr
excess
? ? ? ? ? X,  Product 'X' will be – 
 1-esfFky,sfFkyhu vkWDlkbM vkf/kD; ? ? ? ? ? ?
 vkf/kD; HBr
 X,  mRikn 'X' gksxk & 
 (1) 
 
Br 
Br 
   (2) 
 
Br 
Br 
  (3) 
 
Br Br (4)
 
Br 
 
Ans. (2) 
Sol.  
 
Br 
Br 
O 
HBr 
O 
H 
? ?
Br
–
 
Br 
OH 
HBr 
 
 
5. Correct order of Intermolecular forces  
 (1) Dipole – Dipole > Ion – Ion > Dipole – Ion   
 (2) Ion – Ion > Dipole – Dipole > Dipole – Ion    
 (3) Dipole – Ion > Dipole – Dipole > Ion – Ion 
 (4) Ion – Ion > Dipole – Ion > Dipole – Dipole    
 vUrjvkf.od cyksa dk lgh Øe gS &  
 (1) f}/kzqo – f}/kzqo > vk;u – vk;u > f}/kzqo – vk;u  
 (2) vk;u – vk;u > f}/kzqo – f}/kzqo > f}/kzqo – vk;u  
 (3) f}/kzqo – vk;u > f}/kzqo – f}/kzqo > vk;u – vk;u 
 (4) vk;u – vk;u > f}/kzqo – vk;u > f}/kzqo – f}/kzqo 
Ans. (4) 
 
6. Hex-3-ynal 
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), formed product X will be: 
 gsDl-3-vkbuSy
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), izkIr mRikn X gksxk % 
 (1) 
 O 
C –OH 
    (2)  
 
C –OH 
O 
H 
H 
H 
 
  
 (3) 
 
O 
OH 
    (4) 
 
O 
OH 
 
Ans. (1) 
Sol. 
 
CHO 
4
NaBH
? ?? ? ?
 
OH 
3
PBr
? ? ? ?
 Br 
Mg/Ether 
 
          
 
COOH 
H
?
? ? ? ?
 O 
C –O 
2
CO
? ? ? ? MgBr  
 
 
Page 3


     
    
    
    
     
 
                       
  
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. V 34 . 0 º E
Cu / Cu
2 ? ? 
 V 522 . 0 º E
Cu / Cu
? ? 
 ? ? ?
Cu / Cu
2 º E ? 
 (1) 0.158V   (2) –0.158 V  (3) 0.182 V    (4) –0.182 V  
Ans. (1) 
Sol. 
 
Cu
2+
 
º
1
E 
Cu
+
 
0.522 
Cu 
0.34 
 
 2 × 0.34 = 522 . 0 1 E
º
1
? ? 
 522 . 0 – 68 . 0 E
º
1
? 
 158 . 0 E
º
1
? 
 
2. Correct order of electron gain enthalpy (kJ/mole) of F, Cl, Br, I   
 F, Cl, Br, I  dh bySDVªkWu xzg.k ,UFkSYih (kJ/eksy) dk lgh Øe gS \  
 (1) –296, – 325, – 333, – 349 
 (2) –333, – 349, – 325, –296 
 (3) –349, – 333, – 325, – 296 
 (4) –325, – 333, – 349, – 296  
Ans. (2) 
 
3. Arrange the following in order of their pKb value  
 fuEu dks buds pKb eku ds Øe O;ofLFkr dhft, & 
 (A) 
 
N NH 
N 
  (B)  CH3 –NH –CH3  (C) CH3 –CH=NH     
 (1) A > B > C   (2) B > A  > C  (3) C > B > A   (4) B > C > A      
Ans. (3) 
Sol. Option "A" represent Guanadine, the conjugate acid of which is resonance stabilised. The option 'B' is 
aliphatic amine, here the 'N' is sp
3
 whereas in option 'C' the 'N' is sp
2
, hence B is more basic than C. 
fodYi "A" xqokusfMu izdkj dk ;kSfxd iznf'kZr djrk gS ftldk la;qXeh vEy vuqukn }kjk LFkk;hd`r gSA fodYi (B) 
,fyQsfVd ,ehu iznf'kZr djrk gSA ftlesa 'N' sp
3
 ladfjr gS tcfd fodYi 'C' esa 'N' sp
2
 ladfjr gSA vr% B, C dh 
rqyuk esa vfèkd {kkjh; gksxkA 
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 2 
 
4. 1-Methylethylene oxide 
HBr
excess
? ? ? ? ? X,  Product 'X' will be – 
 1-esfFky,sfFkyhu vkWDlkbM vkf/kD; ? ? ? ? ? ?
 vkf/kD; HBr
 X,  mRikn 'X' gksxk & 
 (1) 
 
Br 
Br 
   (2) 
 
Br 
Br 
  (3) 
 
Br Br (4)
 
Br 
 
Ans. (2) 
Sol.  
 
Br 
Br 
O 
HBr 
O 
H 
? ?
Br
–
 
Br 
OH 
HBr 
 
 
5. Correct order of Intermolecular forces  
 (1) Dipole – Dipole > Ion – Ion > Dipole – Ion   
 (2) Ion – Ion > Dipole – Dipole > Dipole – Ion    
 (3) Dipole – Ion > Dipole – Dipole > Ion – Ion 
 (4) Ion – Ion > Dipole – Ion > Dipole – Dipole    
 vUrjvkf.od cyksa dk lgh Øe gS &  
 (1) f}/kzqo – f}/kzqo > vk;u – vk;u > f}/kzqo – vk;u  
 (2) vk;u – vk;u > f}/kzqo – f}/kzqo > f}/kzqo – vk;u  
 (3) f}/kzqo – vk;u > f}/kzqo – f}/kzqo > vk;u – vk;u 
 (4) vk;u – vk;u > f}/kzqo – vk;u > f}/kzqo – f}/kzqo 
Ans. (4) 
 
6. Hex-3-ynal 
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), formed product X will be: 
 gsDl-3-vkbuSy
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), izkIr mRikn X gksxk % 
 (1) 
 O 
C –OH 
    (2)  
 
C –OH 
O 
H 
H 
H 
 
  
 (3) 
 
O 
OH 
    (4) 
 
O 
OH 
 
Ans. (1) 
Sol. 
 
CHO 
4
NaBH
? ?? ? ?
 
OH 
3
PBr
? ? ? ?
 Br 
Mg/Ether 
 
          
 
COOH 
H
?
? ? ? ?
 O 
C –O 
2
CO
? ? ? ? MgBr  
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 3 
 
 
7. 
 
Cl N2 N 
CH3 
CH3 
+ SO3 
? ?
Na 
? ?
'X' 
, formed product 'X' is used as:
 
 (1) Lab test of Phenol    
 (2) Acid base titration indicator 
 (3) Food colouring  
 (4) It can be used as an alternative to detect amino acid in place of ninhydrin 
 
 
Cl N2 N 
CH3 
CH3 
+ SO3 
? ?
Na 
? ?
'X' 
, izkIr mRikn 'X' dk mi;ksx fd;k tkrk gS \
 
 (1) fQukWy ds iz;ksx'kkyk ijh{k.k esa   
 (2) vEy {kkj vuqekiu eas lwpd ds :i esa  
 (3) [kk| inkFkksaZ dksa jaxhu djus esa   
 (4) uhugkbMªhu ds LFkku ij ,ehuksa vEy ds fuèkkZj.k gsrq bldk mi;ksx fd;k tkrk gS  
Ans. (2) 
Sol. 
 
+ N2 
H3C 
SO3 
? ?
Methyl orange 
N 
H3C 
N=N 
H3C 
SO3 N 
H3C 
Na
?
 
 
 Methyl orange is used as an indicator in acid base titration. 
 esfFky vkWjsat dk mi;ksx vEy {kkj vuqekiu eas lwpd ds :i esa fd;k tkrk gSA  
 
8. In which of the following Saytzeff product will not be formed as major product ? 
 fuEu eas ls dkSulh vfHkfØ;k esa eq[; mRikn lSRtSQ mRikn ugha gksxk \ 
 (A) 
 
OH 
H
+
 
? ?
     (B)  
 
Br 
alc. KOH 
? ?
  
 (C) 
 
Br 
t BuO
–
K
+
 
? ?
    (D) 
 
H ? ?
O 
OH 
 
(1) Only dsoy C   (2) Only dsoy B  (3) A, C & D  (4) B & D 
Ans. (1) 
Sol. (1) 
 
OH 
H
+
 
? ?
  (2) 
 
Br 
alc. KOH 
? ?
 
 (3) 
 
Br 
t BuO
–
K
+
 
? ?
 (4) 
 
H ? ?
O 
OH 
H 
O 
 
 
 
Page 4


     
    
    
    
     
 
                       
  
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. V 34 . 0 º E
Cu / Cu
2 ? ? 
 V 522 . 0 º E
Cu / Cu
? ? 
 ? ? ?
Cu / Cu
2 º E ? 
 (1) 0.158V   (2) –0.158 V  (3) 0.182 V    (4) –0.182 V  
Ans. (1) 
Sol. 
 
Cu
2+
 
º
1
E 
Cu
+
 
0.522 
Cu 
0.34 
 
 2 × 0.34 = 522 . 0 1 E
º
1
? ? 
 522 . 0 – 68 . 0 E
º
1
? 
 158 . 0 E
º
1
? 
 
2. Correct order of electron gain enthalpy (kJ/mole) of F, Cl, Br, I   
 F, Cl, Br, I  dh bySDVªkWu xzg.k ,UFkSYih (kJ/eksy) dk lgh Øe gS \  
 (1) –296, – 325, – 333, – 349 
 (2) –333, – 349, – 325, –296 
 (3) –349, – 333, – 325, – 296 
 (4) –325, – 333, – 349, – 296  
Ans. (2) 
 
3. Arrange the following in order of their pKb value  
 fuEu dks buds pKb eku ds Øe O;ofLFkr dhft, & 
 (A) 
 
N NH 
N 
  (B)  CH3 –NH –CH3  (C) CH3 –CH=NH     
 (1) A > B > C   (2) B > A  > C  (3) C > B > A   (4) B > C > A      
Ans. (3) 
Sol. Option "A" represent Guanadine, the conjugate acid of which is resonance stabilised. The option 'B' is 
aliphatic amine, here the 'N' is sp
3
 whereas in option 'C' the 'N' is sp
2
, hence B is more basic than C. 
fodYi "A" xqokusfMu izdkj dk ;kSfxd iznf'kZr djrk gS ftldk la;qXeh vEy vuqukn }kjk LFkk;hd`r gSA fodYi (B) 
,fyQsfVd ,ehu iznf'kZr djrk gSA ftlesa 'N' sp
3
 ladfjr gS tcfd fodYi 'C' esa 'N' sp
2
 ladfjr gSA vr% B, C dh 
rqyuk esa vfèkd {kkjh; gksxkA 
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 2 
 
4. 1-Methylethylene oxide 
HBr
excess
? ? ? ? ? X,  Product 'X' will be – 
 1-esfFky,sfFkyhu vkWDlkbM vkf/kD; ? ? ? ? ? ?
 vkf/kD; HBr
 X,  mRikn 'X' gksxk & 
 (1) 
 
Br 
Br 
   (2) 
 
Br 
Br 
  (3) 
 
Br Br (4)
 
Br 
 
Ans. (2) 
Sol.  
 
Br 
Br 
O 
HBr 
O 
H 
? ?
Br
–
 
Br 
OH 
HBr 
 
 
5. Correct order of Intermolecular forces  
 (1) Dipole – Dipole > Ion – Ion > Dipole – Ion   
 (2) Ion – Ion > Dipole – Dipole > Dipole – Ion    
 (3) Dipole – Ion > Dipole – Dipole > Ion – Ion 
 (4) Ion – Ion > Dipole – Ion > Dipole – Dipole    
 vUrjvkf.od cyksa dk lgh Øe gS &  
 (1) f}/kzqo – f}/kzqo > vk;u – vk;u > f}/kzqo – vk;u  
 (2) vk;u – vk;u > f}/kzqo – f}/kzqo > f}/kzqo – vk;u  
 (3) f}/kzqo – vk;u > f}/kzqo – f}/kzqo > vk;u – vk;u 
 (4) vk;u – vk;u > f}/kzqo – vk;u > f}/kzqo – f}/kzqo 
Ans. (4) 
 
6. Hex-3-ynal 
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), formed product X will be: 
 gsDl-3-vkbuSy
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), izkIr mRikn X gksxk % 
 (1) 
 O 
C –OH 
    (2)  
 
C –OH 
O 
H 
H 
H 
 
  
 (3) 
 
O 
OH 
    (4) 
 
O 
OH 
 
Ans. (1) 
Sol. 
 
CHO 
4
NaBH
? ?? ? ?
 
OH 
3
PBr
? ? ? ?
 Br 
Mg/Ether 
 
          
 
COOH 
H
?
? ? ? ?
 O 
C –O 
2
CO
? ? ? ? MgBr  
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 3 
 
 
7. 
 
Cl N2 N 
CH3 
CH3 
+ SO3 
? ?
Na 
? ?
'X' 
, formed product 'X' is used as:
 
 (1) Lab test of Phenol    
 (2) Acid base titration indicator 
 (3) Food colouring  
 (4) It can be used as an alternative to detect amino acid in place of ninhydrin 
 
 
Cl N2 N 
CH3 
CH3 
+ SO3 
? ?
Na 
? ?
'X' 
, izkIr mRikn 'X' dk mi;ksx fd;k tkrk gS \
 
 (1) fQukWy ds iz;ksx'kkyk ijh{k.k esa   
 (2) vEy {kkj vuqekiu eas lwpd ds :i esa  
 (3) [kk| inkFkksaZ dksa jaxhu djus esa   
 (4) uhugkbMªhu ds LFkku ij ,ehuksa vEy ds fuèkkZj.k gsrq bldk mi;ksx fd;k tkrk gS  
Ans. (2) 
Sol. 
 
+ N2 
H3C 
SO3 
? ?
Methyl orange 
N 
H3C 
N=N 
H3C 
SO3 N 
H3C 
Na
?
 
 
 Methyl orange is used as an indicator in acid base titration. 
 esfFky vkWjsat dk mi;ksx vEy {kkj vuqekiu eas lwpd ds :i esa fd;k tkrk gSA  
 
8. In which of the following Saytzeff product will not be formed as major product ? 
 fuEu eas ls dkSulh vfHkfØ;k esa eq[; mRikn lSRtSQ mRikn ugha gksxk \ 
 (A) 
 
OH 
H
+
 
? ?
     (B)  
 
Br 
alc. KOH 
? ?
  
 (C) 
 
Br 
t BuO
–
K
+
 
? ?
    (D) 
 
H ? ?
O 
OH 
 
(1) Only dsoy C   (2) Only dsoy B  (3) A, C & D  (4) B & D 
Ans. (1) 
Sol. (1) 
 
OH 
H
+
 
? ?
  (2) 
 
Br 
alc. KOH 
? ?
 
 (3) 
 
Br 
t BuO
–
K
+
 
? ?
 (4) 
 
H ? ?
O 
OH 
H 
O 
 
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 4 
 
 
9. Match the column 
 Column-I     Column-II  
 (A) Thiamine      (P) Scurvy  
 (B) Riboflavin      (Q) Beri Beri    
 (C) Pyridoxine     (R) Cheilosis     
(D) Ascorbic acid     (S) Convulsions  
fuEu dk feyku dhft, & 
 dkWye-I      dkWye-II  
 (A) Fkk;kehu     (P) LdohZ  
 (B) jkbcks¶ysfou     (Q) csjh csjh  
 (C) ikbjhMksDlhu     (R) dhyksfll (Cheilosis)     
(D) ,LdksfcZd vEy    (S) ejksM+ iM+uk (Convulsions) 
(1) A ??Q  B ??R   C ??P  D ??S 
(2) A ??Q  B ??R   C ??S  D ??P 
(3) A ??R  B ??Q   C ??S  D ??P 
(4) A ??R  B ??Q   C ??P  D ??S 
Ans. (2) 
Sol.  
Vitamins Deficiency Diseases 
Vitamin B1 (Thiamine) Beri Beri 
Vitamin B2 (Riboflavin) Cheilosis 
Vitamin B6 (Pyridoxine) Convulsions 
Vitamin C (Ascorbic acid) Scurvy 
 
foVkehu ghurk tfur jksx 
foVkehu B1 (Fkk;kehu) csjh csjh 
foVkehu B2 (jkbcks¶ysfou) dhyksfll 
foVkehu B6 (ikbjhMksDlhu) ejksM+ iM+uk 
foVkehu C (,LdksfcZd vEy) LdohZ 
 
10. Atomic radius of Ag is similar to  
 Ag dh ijek.kq f=kT;k fdlds leku gksrh gS \ 
 (1) Cu     (2) Hg     (3) Au    (4) Ni 
Ans. (3) 
 
11. Correct IUPAC name of ? ? ? ? Cl ) NH CH ( Cl NH Pt
2 3 2 3
 is: 
 (1) Bis(ammine)chlorido(methylamine)platinum(II) chloride  
(2) Diamminechlorido(methylamine)platinum(II) chloride 
(3) Diamminechlorido(aminomethyl)platinum(II) chloride 
(4) Chloridobis(ammine)methylamineplatinum(II) chloride 
? ? ? ? Cl ) NH CH ( Cl NH Pt
2 3 2 3
 dk lgh IUPAC uke gS % 
 (1) fcl(,sEehu)DyksjkbMksa(esfFky,sehu)IysfVue(II) DyksjkbM  
(2) MkbZ,sEehuDyksjkbMks(esfFky,sehu)IysfVue(II) DyksjkbM 
(3) MkbZ,sEehuDyksjkbMks(,sehuksesfFky)IysfVue(II) DyksjkbM 
(4) DyksjkbMksfcl(,sEehu)esfFky,sehuIysfVue(II) DyksjkbM 
Ans. (2) 
Page 5


     
    
    
    
     
 
                       
  
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. V 34 . 0 º E
Cu / Cu
2 ? ? 
 V 522 . 0 º E
Cu / Cu
? ? 
 ? ? ?
Cu / Cu
2 º E ? 
 (1) 0.158V   (2) –0.158 V  (3) 0.182 V    (4) –0.182 V  
Ans. (1) 
Sol. 
 
Cu
2+
 
º
1
E 
Cu
+
 
0.522 
Cu 
0.34 
 
 2 × 0.34 = 522 . 0 1 E
º
1
? ? 
 522 . 0 – 68 . 0 E
º
1
? 
 158 . 0 E
º
1
? 
 
2. Correct order of electron gain enthalpy (kJ/mole) of F, Cl, Br, I   
 F, Cl, Br, I  dh bySDVªkWu xzg.k ,UFkSYih (kJ/eksy) dk lgh Øe gS \  
 (1) –296, – 325, – 333, – 349 
 (2) –333, – 349, – 325, –296 
 (3) –349, – 333, – 325, – 296 
 (4) –325, – 333, – 349, – 296  
Ans. (2) 
 
3. Arrange the following in order of their pKb value  
 fuEu dks buds pKb eku ds Øe O;ofLFkr dhft, & 
 (A) 
 
N NH 
N 
  (B)  CH3 –NH –CH3  (C) CH3 –CH=NH     
 (1) A > B > C   (2) B > A  > C  (3) C > B > A   (4) B > C > A      
Ans. (3) 
Sol. Option "A" represent Guanadine, the conjugate acid of which is resonance stabilised. The option 'B' is 
aliphatic amine, here the 'N' is sp
3
 whereas in option 'C' the 'N' is sp
2
, hence B is more basic than C. 
fodYi "A" xqokusfMu izdkj dk ;kSfxd iznf'kZr djrk gS ftldk la;qXeh vEy vuqukn }kjk LFkk;hd`r gSA fodYi (B) 
,fyQsfVd ,ehu iznf'kZr djrk gSA ftlesa 'N' sp
3
 ladfjr gS tcfd fodYi 'C' esa 'N' sp
2
 ladfjr gSA vr% B, C dh 
rqyuk esa vfèkd {kkjh; gksxkA 
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 2 
 
4. 1-Methylethylene oxide 
HBr
excess
? ? ? ? ? X,  Product 'X' will be – 
 1-esfFky,sfFkyhu vkWDlkbM vkf/kD; ? ? ? ? ? ?
 vkf/kD; HBr
 X,  mRikn 'X' gksxk & 
 (1) 
 
Br 
Br 
   (2) 
 
Br 
Br 
  (3) 
 
Br Br (4)
 
Br 
 
Ans. (2) 
Sol.  
 
Br 
Br 
O 
HBr 
O 
H 
? ?
Br
–
 
Br 
OH 
HBr 
 
 
5. Correct order of Intermolecular forces  
 (1) Dipole – Dipole > Ion – Ion > Dipole – Ion   
 (2) Ion – Ion > Dipole – Dipole > Dipole – Ion    
 (3) Dipole – Ion > Dipole – Dipole > Ion – Ion 
 (4) Ion – Ion > Dipole – Ion > Dipole – Dipole    
 vUrjvkf.od cyksa dk lgh Øe gS &  
 (1) f}/kzqo – f}/kzqo > vk;u – vk;u > f}/kzqo – vk;u  
 (2) vk;u – vk;u > f}/kzqo – f}/kzqo > f}/kzqo – vk;u  
 (3) f}/kzqo – vk;u > f}/kzqo – f}/kzqo > vk;u – vk;u 
 (4) vk;u – vk;u > f}/kzqo – vk;u > f}/kzqo – f}/kzqo 
Ans. (4) 
 
6. Hex-3-ynal 
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), formed product X will be: 
 gsDl-3-vkbuSy
4
(1)NaBH
? ??? ? ?
3
(2)PBr
? ?? ? ?
(3)Mg/Ether
? ?? ?? ? ?
2
(4)CO
? ?? ? ?
(5)H
?
? ? ? ? ? (X), izkIr mRikn X gksxk % 
 (1) 
 O 
C –OH 
    (2)  
 
C –OH 
O 
H 
H 
H 
 
  
 (3) 
 
O 
OH 
    (4) 
 
O 
OH 
 
Ans. (1) 
Sol. 
 
CHO 
4
NaBH
? ?? ? ?
 
OH 
3
PBr
? ? ? ?
 Br 
Mg/Ether 
 
          
 
COOH 
H
?
? ? ? ?
 O 
C –O 
2
CO
? ? ? ? MgBr  
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 3 
 
 
7. 
 
Cl N2 N 
CH3 
CH3 
+ SO3 
? ?
Na 
? ?
'X' 
, formed product 'X' is used as:
 
 (1) Lab test of Phenol    
 (2) Acid base titration indicator 
 (3) Food colouring  
 (4) It can be used as an alternative to detect amino acid in place of ninhydrin 
 
 
Cl N2 N 
CH3 
CH3 
+ SO3 
? ?
Na 
? ?
'X' 
, izkIr mRikn 'X' dk mi;ksx fd;k tkrk gS \
 
 (1) fQukWy ds iz;ksx'kkyk ijh{k.k esa   
 (2) vEy {kkj vuqekiu eas lwpd ds :i esa  
 (3) [kk| inkFkksaZ dksa jaxhu djus esa   
 (4) uhugkbMªhu ds LFkku ij ,ehuksa vEy ds fuèkkZj.k gsrq bldk mi;ksx fd;k tkrk gS  
Ans. (2) 
Sol. 
 
+ N2 
H3C 
SO3 
? ?
Methyl orange 
N 
H3C 
N=N 
H3C 
SO3 N 
H3C 
Na
?
 
 
 Methyl orange is used as an indicator in acid base titration. 
 esfFky vkWjsat dk mi;ksx vEy {kkj vuqekiu eas lwpd ds :i esa fd;k tkrk gSA  
 
8. In which of the following Saytzeff product will not be formed as major product ? 
 fuEu eas ls dkSulh vfHkfØ;k esa eq[; mRikn lSRtSQ mRikn ugha gksxk \ 
 (A) 
 
OH 
H
+
 
? ?
     (B)  
 
Br 
alc. KOH 
? ?
  
 (C) 
 
Br 
t BuO
–
K
+
 
? ?
    (D) 
 
H ? ?
O 
OH 
 
(1) Only dsoy C   (2) Only dsoy B  (3) A, C & D  (4) B & D 
Ans. (1) 
Sol. (1) 
 
OH 
H
+
 
? ?
  (2) 
 
Br 
alc. KOH 
? ?
 
 (3) 
 
Br 
t BuO
–
K
+
 
? ?
 (4) 
 
H ? ?
O 
OH 
H 
O 
 
 
 
     
    
    
    
     
 
                       
  
 
PAGE # 4 
 
 
9. Match the column 
 Column-I     Column-II  
 (A) Thiamine      (P) Scurvy  
 (B) Riboflavin      (Q) Beri Beri    
 (C) Pyridoxine     (R) Cheilosis     
(D) Ascorbic acid     (S) Convulsions  
fuEu dk feyku dhft, & 
 dkWye-I      dkWye-II  
 (A) Fkk;kehu     (P) LdohZ  
 (B) jkbcks¶ysfou     (Q) csjh csjh  
 (C) ikbjhMksDlhu     (R) dhyksfll (Cheilosis)     
(D) ,LdksfcZd vEy    (S) ejksM+ iM+uk (Convulsions) 
(1) A ??Q  B ??R   C ??P  D ??S 
(2) A ??Q  B ??R   C ??S  D ??P 
(3) A ??R  B ??Q   C ??S  D ??P 
(4) A ??R  B ??Q   C ??P  D ??S 
Ans. (2) 
Sol.  
Vitamins Deficiency Diseases 
Vitamin B1 (Thiamine) Beri Beri 
Vitamin B2 (Riboflavin) Cheilosis 
Vitamin B6 (Pyridoxine) Convulsions 
Vitamin C (Ascorbic acid) Scurvy 
 
foVkehu ghurk tfur jksx 
foVkehu B1 (Fkk;kehu) csjh csjh 
foVkehu B2 (jkbcks¶ysfou) dhyksfll 
foVkehu B6 (ikbjhMksDlhu) ejksM+ iM+uk 
foVkehu C (,LdksfcZd vEy) LdohZ 
 
10. Atomic radius of Ag is similar to  
 Ag dh ijek.kq f=kT;k fdlds leku gksrh gS \ 
 (1) Cu     (2) Hg     (3) Au    (4) Ni 
Ans. (3) 
 
11. Correct IUPAC name of ? ? ? ? Cl ) NH CH ( Cl NH Pt
2 3 2 3
 is: 
 (1) Bis(ammine)chlorido(methylamine)platinum(II) chloride  
(2) Diamminechlorido(methylamine)platinum(II) chloride 
(3) Diamminechlorido(aminomethyl)platinum(II) chloride 
(4) Chloridobis(ammine)methylamineplatinum(II) chloride 
? ? ? ? Cl ) NH CH ( Cl NH Pt
2 3 2 3
 dk lgh IUPAC uke gS % 
 (1) fcl(,sEehu)DyksjkbMksa(esfFky,sehu)IysfVue(II) DyksjkbM  
(2) MkbZ,sEehuDyksjkbMks(esfFky,sehu)IysfVue(II) DyksjkbM 
(3) MkbZ,sEehuDyksjkbMks(,sehuksesfFky)IysfVue(II) DyksjkbM 
(4) DyksjkbMksfcl(,sEehu)esfFky,sehuIysfVue(II) DyksjkbM 
Ans. (2) 
     
    
    
    
     
 
                       
  
 
PAGE # 5 
 
 
12. Vapour pressure of pure CS2 and CH3COCH3 are 512 mm of Hg and 312 mm of Hg respectively. Total 
vapour pressure of mixture is 600 mm of Hg then find incorrect statement: 
 (1) B A
B B
A A
? ? ? ?
?
?
?
? ? ?
? ? ?
 
 (2) Does not obey Raoult's law  
 (3) Endothermic solution 
(4) after adding 100 ml of each, then net volume is less than 200 ml  
'kq) CS2 rFkk CH3COCH3 dk ok"i nkc Øe'k% 512 mm Hg rFkk 312 mm Hg gSA buds feJ.k dk dqy ok"i nkc 
600 mm Hg gS rc vlR; dFku dh igpku dhft, & 
 (1) B A
B B
A A
? ? ? ?
?
?
?
? ? ?
? ? ?
 
 (2) jkmYV fu;e dh vuqikyuk ugha djrk gSA  
 (3) Å"ek'kks"kh foy;u 
(4) izR;sd ds 100 ml feykus ij ifj.kkeh vk;ru 200 ml ls de ik;k tkrk gSA 
Ans. (4) 
Sol. Above mixture of liquids show positive deviation from Raoult's Law 
 mijksDr feJ.k jkmYV fu;e ls /kukRed fopyu n'kkZrk gSA 
 
13. Purest form of commercial iron is:  
 (1) Wrought iron  (2) Cast iron   (3) Pig iron  (4) Iron scrap + pig iron   
 vkS|ksfxd ykSgs dk 'kq)r~e :i gS &  
 (1) fiVok ykSgk (Wrought iron)    (2) <yok ykSgk (Cast iron)   
 (3) dPpk ykSgk (Pig iron)     (4) jn~nh ykSgk + dPpk ykSgk (Iron scrap + pig iron)   
Ans. (1) 
Sol. Purest form is wrought iron. 
 vkS|ksfxd ykSgs dk 'kq)r~e :I fiVok ykSgk (Wrought iron) gSA  
 
14. 
 
COOH 
Cl 
(x) 
OH 
Cl 
(y) 
NH2 
Cl 
(z) 
 
 Mixture of above three organic compound was subjected to aq NaHCO3 and followed by dil NaOH. 
compounds which will be soluble in given solvent will be :   
 (1) x in aq NaHCO3 and y in dil. NaOH.  
 (2) x in aq NaHCO3 and z in dil. NaOH. 
 (3) y in aq NaHCO3 and x in dil. NaOH.   
 (4)  y is aq NaHCO3 and z in dil. NaOH.