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JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 1
Date : 3
rd
 September 2020
Time : 09 : 00 am - 12 : 00 pm
Subject : Chemistry
1. It is true that :
(1) A second order reaction is always a multistep reaction
(2) A first order reaction is always a single step reaction
(3) A zero order reaction is a multistep reaction
(4) A zero order reaction is a single step reaction
Sol. 3
Factual
2. An acidic buffer is obtained on mixing :
(1) 100 mL of 0.1 M HCl and 200 mL of 0.1 M CH
3
COONa
(2) 100 mL of 0.1 M HCl and 200 mL of 0.1 M NaCl
(3) 100 mL of 0.1 M CH
3
 COOH and 100 mL of 0.1 M NaOH
(4) 100 mL of 0.1 M CH
3
COOH and 200 mL of 0.1 M NaOH
Sol. 1
2HCl + CH
3
COO
–
 ?? CH
3
COOH + OH
–
10 20
X 10 10
Acidic buffer
3. The Kjeldahl method of Nitrogen estimation fails for which of the following reaction
products?
(a)  
NO
2
Sn/HCl (b) 
LiAlH
4
(c) 
(i) SnCl + HCl
2
(ii) H O
2
(d) 
NaNO
2
HCl
(1) (a), (c) and (d) (2) (b) and (c)
(3) (c) and (d) (4) (a) and (d)
Page 2


JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 1
Date : 3
rd
 September 2020
Time : 09 : 00 am - 12 : 00 pm
Subject : Chemistry
1. It is true that :
(1) A second order reaction is always a multistep reaction
(2) A first order reaction is always a single step reaction
(3) A zero order reaction is a multistep reaction
(4) A zero order reaction is a single step reaction
Sol. 3
Factual
2. An acidic buffer is obtained on mixing :
(1) 100 mL of 0.1 M HCl and 200 mL of 0.1 M CH
3
COONa
(2) 100 mL of 0.1 M HCl and 200 mL of 0.1 M NaCl
(3) 100 mL of 0.1 M CH
3
 COOH and 100 mL of 0.1 M NaOH
(4) 100 mL of 0.1 M CH
3
COOH and 200 mL of 0.1 M NaOH
Sol. 1
2HCl + CH
3
COO
–
 ?? CH
3
COOH + OH
–
10 20
X 10 10
Acidic buffer
3. The Kjeldahl method of Nitrogen estimation fails for which of the following reaction
products?
(a)  
NO
2
Sn/HCl (b) 
LiAlH
4
(c) 
(i) SnCl + HCl
2
(ii) H O
2
(d) 
NaNO
2
HCl
(1) (a), (c) and (d) (2) (b) and (c)
(3) (c) and (d) (4) (a) and (d)
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 2
Sol. 3
(A) 
NO
2
Sn/HCl
NH
2
(B) 
CN
LiAlH
4
CH NH
2 2
(C) 
CH CN
2
(i) SnCl + HCl
2
(ii) H O
2
CH CHO
2
+ NH Cl
4
(D) 
NH
2
N Cl
2
NaNO
2
HCl
Diazo compound and inorganic nitrogen can't be estimeted by kjeldal method.
4. If the boiling point of H
2
O is 373 K, the boiling point of H
2
S will be :
(1) greater than 300 K but less than 373 K
(2) equal to 373 K
(3) more than 373 K
(4) less than 300 K
Sol. 4
Less than 300 K (factual)
5. The complex that can show optical activity is :
(1) ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
(2) ? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
(3) ? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
(4) ? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
Sol. 1
Cr
Cl
O
Cl
O O
O
Nonsuper imposable
M.I.
optically active
 ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
Page 3


JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 1
Date : 3
rd
 September 2020
Time : 09 : 00 am - 12 : 00 pm
Subject : Chemistry
1. It is true that :
(1) A second order reaction is always a multistep reaction
(2) A first order reaction is always a single step reaction
(3) A zero order reaction is a multistep reaction
(4) A zero order reaction is a single step reaction
Sol. 3
Factual
2. An acidic buffer is obtained on mixing :
(1) 100 mL of 0.1 M HCl and 200 mL of 0.1 M CH
3
COONa
(2) 100 mL of 0.1 M HCl and 200 mL of 0.1 M NaCl
(3) 100 mL of 0.1 M CH
3
 COOH and 100 mL of 0.1 M NaOH
(4) 100 mL of 0.1 M CH
3
COOH and 200 mL of 0.1 M NaOH
Sol. 1
2HCl + CH
3
COO
–
 ?? CH
3
COOH + OH
–
10 20
X 10 10
Acidic buffer
3. The Kjeldahl method of Nitrogen estimation fails for which of the following reaction
products?
(a)  
NO
2
Sn/HCl (b) 
LiAlH
4
(c) 
(i) SnCl + HCl
2
(ii) H O
2
(d) 
NaNO
2
HCl
(1) (a), (c) and (d) (2) (b) and (c)
(3) (c) and (d) (4) (a) and (d)
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 2
Sol. 3
(A) 
NO
2
Sn/HCl
NH
2
(B) 
CN
LiAlH
4
CH NH
2 2
(C) 
CH CN
2
(i) SnCl + HCl
2
(ii) H O
2
CH CHO
2
+ NH Cl
4
(D) 
NH
2
N Cl
2
NaNO
2
HCl
Diazo compound and inorganic nitrogen can't be estimeted by kjeldal method.
4. If the boiling point of H
2
O is 373 K, the boiling point of H
2
S will be :
(1) greater than 300 K but less than 373 K
(2) equal to 373 K
(3) more than 373 K
(4) less than 300 K
Sol. 4
Less than 300 K (factual)
5. The complex that can show optical activity is :
(1) ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
(2) ? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
(3) ? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
(4) ? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
Sol. 1
Cr
Cl
O
Cl
O O
O
Nonsuper imposable
M.I.
optically active
 ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 3
Fe
CN
CN
CN
CN
NH
3
NH
3
 POS optically inactive e
? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
Cr
O O
O O
Cl
Cl
 ? POS optically inactive e
? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
Fe
CN
CN
CN
CN
NH
3
NH
3
 ? POS opticaly inactive e
? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
6. Which one of the following compounds possesses the most acidic hydrogen?
(1) 
3
H C C C H ? ? ? (2) 
O O
H
MeO
OHe
OMe
O
(3) 
N C ? C N ?
H H
(4) 
O
CH
3
H C
3
Sol. 3
C
H
H
 has most acidic hydrogen among given compound , this is due to strong –
M effect of –CN group which stabilize –ve charge significantly.
7. Aqua regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this
process is :
(1) N
2
O
3
(2) N
2
(3) N
2
O
5
(4) NO
Page 4


JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 1
Date : 3
rd
 September 2020
Time : 09 : 00 am - 12 : 00 pm
Subject : Chemistry
1. It is true that :
(1) A second order reaction is always a multistep reaction
(2) A first order reaction is always a single step reaction
(3) A zero order reaction is a multistep reaction
(4) A zero order reaction is a single step reaction
Sol. 3
Factual
2. An acidic buffer is obtained on mixing :
(1) 100 mL of 0.1 M HCl and 200 mL of 0.1 M CH
3
COONa
(2) 100 mL of 0.1 M HCl and 200 mL of 0.1 M NaCl
(3) 100 mL of 0.1 M CH
3
 COOH and 100 mL of 0.1 M NaOH
(4) 100 mL of 0.1 M CH
3
COOH and 200 mL of 0.1 M NaOH
Sol. 1
2HCl + CH
3
COO
–
 ?? CH
3
COOH + OH
–
10 20
X 10 10
Acidic buffer
3. The Kjeldahl method of Nitrogen estimation fails for which of the following reaction
products?
(a)  
NO
2
Sn/HCl (b) 
LiAlH
4
(c) 
(i) SnCl + HCl
2
(ii) H O
2
(d) 
NaNO
2
HCl
(1) (a), (c) and (d) (2) (b) and (c)
(3) (c) and (d) (4) (a) and (d)
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 2
Sol. 3
(A) 
NO
2
Sn/HCl
NH
2
(B) 
CN
LiAlH
4
CH NH
2 2
(C) 
CH CN
2
(i) SnCl + HCl
2
(ii) H O
2
CH CHO
2
+ NH Cl
4
(D) 
NH
2
N Cl
2
NaNO
2
HCl
Diazo compound and inorganic nitrogen can't be estimeted by kjeldal method.
4. If the boiling point of H
2
O is 373 K, the boiling point of H
2
S will be :
(1) greater than 300 K but less than 373 K
(2) equal to 373 K
(3) more than 373 K
(4) less than 300 K
Sol. 4
Less than 300 K (factual)
5. The complex that can show optical activity is :
(1) ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
(2) ? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
(3) ? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
(4) ? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
Sol. 1
Cr
Cl
O
Cl
O O
O
Nonsuper imposable
M.I.
optically active
 ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 3
Fe
CN
CN
CN
CN
NH
3
NH
3
 POS optically inactive e
? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
Cr
O O
O O
Cl
Cl
 ? POS optically inactive e
? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
Fe
CN
CN
CN
CN
NH
3
NH
3
 ? POS opticaly inactive e
? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
6. Which one of the following compounds possesses the most acidic hydrogen?
(1) 
3
H C C C H ? ? ? (2) 
O O
H
MeO
OHe
OMe
O
(3) 
N C ? C N ?
H H
(4) 
O
CH
3
H C
3
Sol. 3
C
H
H
 has most acidic hydrogen among given compound , this is due to strong –
M effect of –CN group which stabilize –ve charge significantly.
7. Aqua regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this
process is :
(1) N
2
O
3
(2) N
2
(3) N
2
O
5
(4) NO
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 4
Sol. 4
Au + HNO
3
 + HCl ? HAuCl
4
 + NO + H
2
O
Pt + 
3
aqua regia
HNO HCl ?
? ? ? ? ? ? ?
 ? H
2
PtCl
6
 + NO + H
2
O
8. The antifertilituy drug “Novestrol” can react with :
(1) Br
2
/water; ZnCl
2
/HCl; FeCl
3
(2) Br
2
/water; ZnCl
2
/HCl; NaOCl
(3) Alcoholic HCN; NaOCl; ZnCl
2
/HCl (4) ZnCl
2
/HCl; FeCl
3
; Alcoholic HCN
Sol. 1
Novestrol
OH
HO
It can reacts with Br
2
/water due to presence of unsaturation, with ZnCl
2
/HCl due to –
OH group and with FeCl
3
 due to phenol.
9. Which of the following compounds produces an optically inactive compound on hydro-
genation?
(1) 
CH
3
H
(2) 
CH
3
H
(3) 
CH
3
H
(4) 
CH
3
H
Sol. 3
H
CH
3
H
2
CH
3
(optically inactive)
10. Of the species, NO, NO
+
, NO
2+
 and NO
-
, the one with minimum bond strength is :
(1) NO
–
(2) NO
+
(3) NO
2+
(4) NO
Sol. 1
B.O. NO
–
 = 2
BO NO
+
 = 3
BO NO
2+
 = 2.5
BO NO = 2.5
B.O ? 
1
B.L
Page 5


JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 1
Date : 3
rd
 September 2020
Time : 09 : 00 am - 12 : 00 pm
Subject : Chemistry
1. It is true that :
(1) A second order reaction is always a multistep reaction
(2) A first order reaction is always a single step reaction
(3) A zero order reaction is a multistep reaction
(4) A zero order reaction is a single step reaction
Sol. 3
Factual
2. An acidic buffer is obtained on mixing :
(1) 100 mL of 0.1 M HCl and 200 mL of 0.1 M CH
3
COONa
(2) 100 mL of 0.1 M HCl and 200 mL of 0.1 M NaCl
(3) 100 mL of 0.1 M CH
3
 COOH and 100 mL of 0.1 M NaOH
(4) 100 mL of 0.1 M CH
3
COOH and 200 mL of 0.1 M NaOH
Sol. 1
2HCl + CH
3
COO
–
 ?? CH
3
COOH + OH
–
10 20
X 10 10
Acidic buffer
3. The Kjeldahl method of Nitrogen estimation fails for which of the following reaction
products?
(a)  
NO
2
Sn/HCl (b) 
LiAlH
4
(c) 
(i) SnCl + HCl
2
(ii) H O
2
(d) 
NaNO
2
HCl
(1) (a), (c) and (d) (2) (b) and (c)
(3) (c) and (d) (4) (a) and (d)
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 2
Sol. 3
(A) 
NO
2
Sn/HCl
NH
2
(B) 
CN
LiAlH
4
CH NH
2 2
(C) 
CH CN
2
(i) SnCl + HCl
2
(ii) H O
2
CH CHO
2
+ NH Cl
4
(D) 
NH
2
N Cl
2
NaNO
2
HCl
Diazo compound and inorganic nitrogen can't be estimeted by kjeldal method.
4. If the boiling point of H
2
O is 373 K, the boiling point of H
2
S will be :
(1) greater than 300 K but less than 373 K
(2) equal to 373 K
(3) more than 373 K
(4) less than 300 K
Sol. 4
Less than 300 K (factual)
5. The complex that can show optical activity is :
(1) ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
(2) ? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
(3) ? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
(4) ? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
Sol. 1
Cr
Cl
O
Cl
O O
O
Nonsuper imposable
M.I.
optically active
 ? ? ? ?
3
2
2
cis CrCl ox ox oxalate
?
? ? ? ?
? ?
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 3
Fe
CN
CN
CN
CN
NH
3
NH
3
 POS optically inactive e
? ? ? ?
3
2 4
trans Fe NH CN
?
? ? ?
? ?
Cr
O O
O O
Cl
Cl
 ? POS optically inactive e
? ? ? ?
3
2
2
trans Cr Cl ox
?
? ? ?
? ?
Fe
CN
CN
CN
CN
NH
3
NH
3
 ? POS opticaly inactive e
? ? ? ?
3
2 4
cis Fe NH CN
?
? ? ?
? ?
6. Which one of the following compounds possesses the most acidic hydrogen?
(1) 
3
H C C C H ? ? ? (2) 
O O
H
MeO
OHe
OMe
O
(3) 
N C ? C N ?
H H
(4) 
O
CH
3
H C
3
Sol. 3
C
H
H
 has most acidic hydrogen among given compound , this is due to strong –
M effect of –CN group which stabilize –ve charge significantly.
7. Aqua regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this
process is :
(1) N
2
O
3
(2) N
2
(3) N
2
O
5
(4) NO
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 4
Sol. 4
Au + HNO
3
 + HCl ? HAuCl
4
 + NO + H
2
O
Pt + 
3
aqua regia
HNO HCl ?
? ? ? ? ? ? ?
 ? H
2
PtCl
6
 + NO + H
2
O
8. The antifertilituy drug “Novestrol” can react with :
(1) Br
2
/water; ZnCl
2
/HCl; FeCl
3
(2) Br
2
/water; ZnCl
2
/HCl; NaOCl
(3) Alcoholic HCN; NaOCl; ZnCl
2
/HCl (4) ZnCl
2
/HCl; FeCl
3
; Alcoholic HCN
Sol. 1
Novestrol
OH
HO
It can reacts with Br
2
/water due to presence of unsaturation, with ZnCl
2
/HCl due to –
OH group and with FeCl
3
 due to phenol.
9. Which of the following compounds produces an optically inactive compound on hydro-
genation?
(1) 
CH
3
H
(2) 
CH
3
H
(3) 
CH
3
H
(4) 
CH
3
H
Sol. 3
H
CH
3
H
2
CH
3
(optically inactive)
10. Of the species, NO, NO
+
, NO
2+
 and NO
-
, the one with minimum bond strength is :
(1) NO
–
(2) NO
+
(3) NO
2+
(4) NO
Sol. 1
B.O. NO
–
 = 2
BO NO
+
 = 3
BO NO
2+
 = 2.5
BO NO = 2.5
B.O ? 
1
B.L
JEE Main 2020 Paper
         3
rd
 September 2020 | (Shift-1), Chemistry     Page | 5
11. Glycerol is separated in soap industries by :
(1) Fractional distillation (2) Distillation under reduced pressure
(3) Differential extraction (4) Steam distillation
Sol. 2
conceptual
Glycerol is separated in soap industries by distillation under reduced pressure
12. Thermal power plants can lead to :
(1) Ozone layer depletion (2) Blue baby syndrome
(3) Eutrophication (4) Acid rain
Sol. 4
Refer enviornmental chemistry
It emits CO
2
 that combine with mositure of atmosphere and forms H
2
CO
3
 (carbonic
acid)
13. Henry’s constant (in kbar) for four gases , , ? ? ? and ? in water at 298 K is given below:
? ? ? ?
K
H
50 2 2 x 10
-5
0.5
(density of water = 10
3
 kg m
-3
 at 298 K)
This table implies that :
(1) solubility of ? at 308 K is lower than at 298 K
(2) The pressure of a 55.5 molal solution of ? is 250 bar
(3) ? has the highest solubility in water at a given pressure
(4) The pressure of a 55.5 molal solutio of ? is 1 bar
Sol. 1
p = K
H
X mol fraction of gas in liquid.
On increasing tamp, ‘K’
H
 increases
Hence solubility ?
therefore, option 1
14. The electronic spectrum of [Ti(H
2
O)
6
]
3+
 shows a single broad peak with a maximum at
20,300 cm
-1
. The crystal field stabillization energy (CFSE) of the complex ion, in
kJ mol
-1
, is :
(1 kJ mol-1 = 83.7 cm
-1
)
(1) 83.7 (2) 242.5 (3) 145.5 (4) 97
Sol. 4
[Ti(H
2
O)
6
]
3+
 Ti
3+
 3d
1
 in octahedral field of ligend
 eg
t g
2
3d
1
CFSE = –0.4 ?
0
CFSE = 
0.4 20300
83.7
? ?
= 97 kJ mol
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