Page 1
Q1 - 2024 (01 Feb Shift 1)
The minimum energy required by a hydrogen atom in ground state to emit radiation in
Balmer series is nearly:
(1) 1.5eV
(2) 13.6eV
(3) 1.9eV
(4) 12.1eV
Solution: (4)
Transition from ?? = 1 to ?? = 3?E = 12.1eV
Q2 - 2024 (01 Feb Shift 2)
A particular hydrogen - like ion emits the radiation of frequency 3×10
15
Hz when it
makes transition from ?? = 2to ?? = 1. The frequency of radiation emitted in transition from
n = 3 to n = 1is
?? 9
×10
15
Hz, when x =
Solution: 32
?? = -13.6?? 2
1
?? ?? 2
-
1
?? ?? 2
E = C
1
n
f
2
-
1
n
i
2
h?? = ??
1
?? ?? 2
-
1
?? ?? 2
?? 1
?? 2
=
1
?? ?? 2
-
1
?? ?? 2
2-1
1
?? ?? 2
-
1
?? ?? 2
3-1
=
1
1
-
1
4
1
1
-
1
9
=
3/4
8/9
=
3
4
×
9
8
?? 1
?? 2
=
27
32
?? 2
=
32
27
?? 1
=
32
27
×3×10
15
Hz =
32
9
×10
15
Hz
Q3 - 2024 (27 Jan Shift 1)
The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth
stationary orbit will be:
Page 2
Q1 - 2024 (01 Feb Shift 1)
The minimum energy required by a hydrogen atom in ground state to emit radiation in
Balmer series is nearly:
(1) 1.5eV
(2) 13.6eV
(3) 1.9eV
(4) 12.1eV
Solution: (4)
Transition from ?? = 1 to ?? = 3?E = 12.1eV
Q2 - 2024 (01 Feb Shift 2)
A particular hydrogen - like ion emits the radiation of frequency 3×10
15
Hz when it
makes transition from ?? = 2to ?? = 1. The frequency of radiation emitted in transition from
n = 3 to n = 1is
?? 9
×10
15
Hz, when x =
Solution: 32
?? = -13.6?? 2
1
?? ?? 2
-
1
?? ?? 2
E = C
1
n
f
2
-
1
n
i
2
h?? = ??
1
?? ?? 2
-
1
?? ?? 2
?? 1
?? 2
=
1
?? ?? 2
-
1
?? ?? 2
2-1
1
?? ?? 2
-
1
?? ?? 2
3-1
=
1
1
-
1
4
1
1
-
1
9
=
3/4
8/9
=
3
4
×
9
8
?? 1
?? 2
=
27
32
?? 2
=
32
27
?? 1
=
32
27
×3×10
15
Hz =
32
9
×10
15
Hz
Q3 - 2024 (27 Jan Shift 1)
The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth
stationary orbit will be:
(1)
4
3
R
(2)
16
9
??
(3)
3
4
??
(4)
9
16
R
Solution: (2)
?? ?
?? 2
??
?? 4
?? 3
=
4
2
3
2
?? 4
=
16
9
??
Q4 - 2024 (27 Jan Shift 2)
If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be
?? 7?? , where ?? =
Solution: 144
Longest wavelength corresponds to transition between n = 3 and n = 4
1
?? = RZ
2
1
3
2
-
1
4
2
= RZ
2
1
9
-
1
16
=
7RZ
2
9×16
? ?? =
144
7R
forZ= 1 ? ?? = 144
Q5 - 2024 (29 Jan Shift 1)
When a hydrogen atom going from n = 2 to n= 1 emits a photon, its recoil speed is
x
5
m/s. Where x = . (Use : mass of hydrogen atom = 1.6×10
-27
kg )
Solution: 17
Page 3
Q1 - 2024 (01 Feb Shift 1)
The minimum energy required by a hydrogen atom in ground state to emit radiation in
Balmer series is nearly:
(1) 1.5eV
(2) 13.6eV
(3) 1.9eV
(4) 12.1eV
Solution: (4)
Transition from ?? = 1 to ?? = 3?E = 12.1eV
Q2 - 2024 (01 Feb Shift 2)
A particular hydrogen - like ion emits the radiation of frequency 3×10
15
Hz when it
makes transition from ?? = 2to ?? = 1. The frequency of radiation emitted in transition from
n = 3 to n = 1is
?? 9
×10
15
Hz, when x =
Solution: 32
?? = -13.6?? 2
1
?? ?? 2
-
1
?? ?? 2
E = C
1
n
f
2
-
1
n
i
2
h?? = ??
1
?? ?? 2
-
1
?? ?? 2
?? 1
?? 2
=
1
?? ?? 2
-
1
?? ?? 2
2-1
1
?? ?? 2
-
1
?? ?? 2
3-1
=
1
1
-
1
4
1
1
-
1
9
=
3/4
8/9
=
3
4
×
9
8
?? 1
?? 2
=
27
32
?? 2
=
32
27
?? 1
=
32
27
×3×10
15
Hz =
32
9
×10
15
Hz
Q3 - 2024 (27 Jan Shift 1)
The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth
stationary orbit will be:
(1)
4
3
R
(2)
16
9
??
(3)
3
4
??
(4)
9
16
R
Solution: (2)
?? ?
?? 2
??
?? 4
?? 3
=
4
2
3
2
?? 4
=
16
9
??
Q4 - 2024 (27 Jan Shift 2)
If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be
?? 7?? , where ?? =
Solution: 144
Longest wavelength corresponds to transition between n = 3 and n = 4
1
?? = RZ
2
1
3
2
-
1
4
2
= RZ
2
1
9
-
1
16
=
7RZ
2
9×16
? ?? =
144
7R
forZ= 1 ? ?? = 144
Q5 - 2024 (29 Jan Shift 1)
When a hydrogen atom going from n = 2 to n= 1 emits a photon, its recoil speed is
x
5
m/s. Where x = . (Use : mass of hydrogen atom = 1.6×10
-27
kg )
Solution: 17
??? = 10.2eV
Recoil speed (v) =
?E
mc
=
10.2eV
1.6×10
-27
×3×10
8
=
10.2×1.6×10
-19
1.6×10
-27
×3×10
8
v = 3.4m/s=
17
5
m/s
Therefore, ?? = 17
Q6 - 2024 (29 Jan Shift 2)
Given below are two statements :
Statement I : Most of the mass of the atom and all its positive charge are concentrated in
a tiny nucleus and the electrons revolve around it, is Rutherford's model.
Statement II : An atom is a spherical cloud of positive charges with electrons embedded
in it, is a special case of Rutherford's model.
In the light of the above statements, choose the most appropriate from the options given
below.
(1) Both statement I and statement II are false
(2) Statement I is false but statement II is true
(3) Statement I is true but statement II is false
(4) Both statement I and statement II are true
Solution: (3)
According to Rutherford atomic model, most of mass of atom and all its positive charge
is concentrated in tiny nucleus & electron revolve around it.
According to Thomson atomic model, atom is spherical cloud of positive charge with
electron embedded in it.
Hence,
Statement I is true but statement II false.
Q7 - 2024 (29 Jan Shift 2)
Hydrogen atom is bombarded with electrons accelerated through a potential different of
V, which causes excitation of hydrogen atoms. If the experiment is being formed at
Page 4
Q1 - 2024 (01 Feb Shift 1)
The minimum energy required by a hydrogen atom in ground state to emit radiation in
Balmer series is nearly:
(1) 1.5eV
(2) 13.6eV
(3) 1.9eV
(4) 12.1eV
Solution: (4)
Transition from ?? = 1 to ?? = 3?E = 12.1eV
Q2 - 2024 (01 Feb Shift 2)
A particular hydrogen - like ion emits the radiation of frequency 3×10
15
Hz when it
makes transition from ?? = 2to ?? = 1. The frequency of radiation emitted in transition from
n = 3 to n = 1is
?? 9
×10
15
Hz, when x =
Solution: 32
?? = -13.6?? 2
1
?? ?? 2
-
1
?? ?? 2
E = C
1
n
f
2
-
1
n
i
2
h?? = ??
1
?? ?? 2
-
1
?? ?? 2
?? 1
?? 2
=
1
?? ?? 2
-
1
?? ?? 2
2-1
1
?? ?? 2
-
1
?? ?? 2
3-1
=
1
1
-
1
4
1
1
-
1
9
=
3/4
8/9
=
3
4
×
9
8
?? 1
?? 2
=
27
32
?? 2
=
32
27
?? 1
=
32
27
×3×10
15
Hz =
32
9
×10
15
Hz
Q3 - 2024 (27 Jan Shift 1)
The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth
stationary orbit will be:
(1)
4
3
R
(2)
16
9
??
(3)
3
4
??
(4)
9
16
R
Solution: (2)
?? ?
?? 2
??
?? 4
?? 3
=
4
2
3
2
?? 4
=
16
9
??
Q4 - 2024 (27 Jan Shift 2)
If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be
?? 7?? , where ?? =
Solution: 144
Longest wavelength corresponds to transition between n = 3 and n = 4
1
?? = RZ
2
1
3
2
-
1
4
2
= RZ
2
1
9
-
1
16
=
7RZ
2
9×16
? ?? =
144
7R
forZ= 1 ? ?? = 144
Q5 - 2024 (29 Jan Shift 1)
When a hydrogen atom going from n = 2 to n= 1 emits a photon, its recoil speed is
x
5
m/s. Where x = . (Use : mass of hydrogen atom = 1.6×10
-27
kg )
Solution: 17
??? = 10.2eV
Recoil speed (v) =
?E
mc
=
10.2eV
1.6×10
-27
×3×10
8
=
10.2×1.6×10
-19
1.6×10
-27
×3×10
8
v = 3.4m/s=
17
5
m/s
Therefore, ?? = 17
Q6 - 2024 (29 Jan Shift 2)
Given below are two statements :
Statement I : Most of the mass of the atom and all its positive charge are concentrated in
a tiny nucleus and the electrons revolve around it, is Rutherford's model.
Statement II : An atom is a spherical cloud of positive charges with electrons embedded
in it, is a special case of Rutherford's model.
In the light of the above statements, choose the most appropriate from the options given
below.
(1) Both statement I and statement II are false
(2) Statement I is false but statement II is true
(3) Statement I is true but statement II is false
(4) Both statement I and statement II are true
Solution: (3)
According to Rutherford atomic model, most of mass of atom and all its positive charge
is concentrated in tiny nucleus & electron revolve around it.
According to Thomson atomic model, atom is spherical cloud of positive charge with
electron embedded in it.
Hence,
Statement I is true but statement II false.
Q7 - 2024 (29 Jan Shift 2)
Hydrogen atom is bombarded with electrons accelerated through a potential different of
V, which causes excitation of hydrogen atoms. If the experiment is being formed at
T = 0K. The minimum potential difference needed to observe any Balmer series lines in
the emission spectra will be
?? 10
V, where ?? =
Solution: (121)
For minimum potential difference electron has to make transition from ?? = 3 to ?? = 2
state but first electron has to reach to n = 3 state from ground state. So, energy of
bombarding electron should be equal to energy difference of ?? = 3 and ?? = 1 state.
?E = 13.6 1 -
1
3
2
e = eV
13.6×8
9
= V
V = 12.09V ˜ 12.1V
So, ?? = 121
Q8 - 2024 (30 Jan Shift 1)
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in
the 5
th
excited state of a hydrogen atom is:
(1) 4
(2)
1
4
(3)
1
2
(4) 1
Solution: (3)
1
2
|?? ?? | = ?? ?? for each value of n (orbit)
?
?? ?? |?? ?? |
=
1
2
Q9 - 2024 (30 Jan Shift 1)
A electron of hydrogen atom on an excited state is having energy E
n
= -0.85eV. The
maximum number of allowed transitions to lower energy level is
Solution: 6
?? ?? = -
13.6
?? 2
= -0.85
? ?? = 4
No of transition
Page 5
Q1 - 2024 (01 Feb Shift 1)
The minimum energy required by a hydrogen atom in ground state to emit radiation in
Balmer series is nearly:
(1) 1.5eV
(2) 13.6eV
(3) 1.9eV
(4) 12.1eV
Solution: (4)
Transition from ?? = 1 to ?? = 3?E = 12.1eV
Q2 - 2024 (01 Feb Shift 2)
A particular hydrogen - like ion emits the radiation of frequency 3×10
15
Hz when it
makes transition from ?? = 2to ?? = 1. The frequency of radiation emitted in transition from
n = 3 to n = 1is
?? 9
×10
15
Hz, when x =
Solution: 32
?? = -13.6?? 2
1
?? ?? 2
-
1
?? ?? 2
E = C
1
n
f
2
-
1
n
i
2
h?? = ??
1
?? ?? 2
-
1
?? ?? 2
?? 1
?? 2
=
1
?? ?? 2
-
1
?? ?? 2
2-1
1
?? ?? 2
-
1
?? ?? 2
3-1
=
1
1
-
1
4
1
1
-
1
9
=
3/4
8/9
=
3
4
×
9
8
?? 1
?? 2
=
27
32
?? 2
=
32
27
?? 1
=
32
27
×3×10
15
Hz =
32
9
×10
15
Hz
Q3 - 2024 (27 Jan Shift 1)
The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth
stationary orbit will be:
(1)
4
3
R
(2)
16
9
??
(3)
3
4
??
(4)
9
16
R
Solution: (2)
?? ?
?? 2
??
?? 4
?? 3
=
4
2
3
2
?? 4
=
16
9
??
Q4 - 2024 (27 Jan Shift 2)
If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be
?? 7?? , where ?? =
Solution: 144
Longest wavelength corresponds to transition between n = 3 and n = 4
1
?? = RZ
2
1
3
2
-
1
4
2
= RZ
2
1
9
-
1
16
=
7RZ
2
9×16
? ?? =
144
7R
forZ= 1 ? ?? = 144
Q5 - 2024 (29 Jan Shift 1)
When a hydrogen atom going from n = 2 to n= 1 emits a photon, its recoil speed is
x
5
m/s. Where x = . (Use : mass of hydrogen atom = 1.6×10
-27
kg )
Solution: 17
??? = 10.2eV
Recoil speed (v) =
?E
mc
=
10.2eV
1.6×10
-27
×3×10
8
=
10.2×1.6×10
-19
1.6×10
-27
×3×10
8
v = 3.4m/s=
17
5
m/s
Therefore, ?? = 17
Q6 - 2024 (29 Jan Shift 2)
Given below are two statements :
Statement I : Most of the mass of the atom and all its positive charge are concentrated in
a tiny nucleus and the electrons revolve around it, is Rutherford's model.
Statement II : An atom is a spherical cloud of positive charges with electrons embedded
in it, is a special case of Rutherford's model.
In the light of the above statements, choose the most appropriate from the options given
below.
(1) Both statement I and statement II are false
(2) Statement I is false but statement II is true
(3) Statement I is true but statement II is false
(4) Both statement I and statement II are true
Solution: (3)
According to Rutherford atomic model, most of mass of atom and all its positive charge
is concentrated in tiny nucleus & electron revolve around it.
According to Thomson atomic model, atom is spherical cloud of positive charge with
electron embedded in it.
Hence,
Statement I is true but statement II false.
Q7 - 2024 (29 Jan Shift 2)
Hydrogen atom is bombarded with electrons accelerated through a potential different of
V, which causes excitation of hydrogen atoms. If the experiment is being formed at
T = 0K. The minimum potential difference needed to observe any Balmer series lines in
the emission spectra will be
?? 10
V, where ?? =
Solution: (121)
For minimum potential difference electron has to make transition from ?? = 3 to ?? = 2
state but first electron has to reach to n = 3 state from ground state. So, energy of
bombarding electron should be equal to energy difference of ?? = 3 and ?? = 1 state.
?E = 13.6 1 -
1
3
2
e = eV
13.6×8
9
= V
V = 12.09V ˜ 12.1V
So, ?? = 121
Q8 - 2024 (30 Jan Shift 1)
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in
the 5
th
excited state of a hydrogen atom is:
(1) 4
(2)
1
4
(3)
1
2
(4) 1
Solution: (3)
1
2
|?? ?? | = ?? ?? for each value of n (orbit)
?
?? ?? |?? ?? |
=
1
2
Q9 - 2024 (30 Jan Shift 1)
A electron of hydrogen atom on an excited state is having energy E
n
= -0.85eV. The
maximum number of allowed transitions to lower energy level is
Solution: 6
?? ?? = -
13.6
?? 2
= -0.85
? ?? = 4
No of transition
=
?? (?? -1)
2
=
4(4 -1)
2
= 6
Q10 - 2024 (30 Jan Shift 2)
An electron revolving in n
th
Bohr orbit has magnetic moment ?? ?? . If ?? ?? ?? ?? ?? , the value of ??
is:
(1) 2
(2) 1
(3) 3
(4) 0
Solution: (2)
Magnetic moment = i?? r
2
?? =
evr
2
?? ??
1
?? ?? 2
?? ?? ??
?? =1
Q11 - 2024 (31 Jan Shift 1)
The mass defect in a particular reaction is 0.4g. The amount of energy liberated is
n×10
7
kWh, where n =
Solution: 1
E = ?mc
2
= 0.4×10
-3
× 3×10
8
2
= 3600×10
7
kWs
=
3600×10
7
3600
kWh = 1×10
7
kWh
(speed of light = 3×10
8
m/s)
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