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Page 1 2024 Q1 - 2024 (01 Feb Shift 1) A particle moving in a circle of radius ?? with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle ?? to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection ?? is then given by : (1) sin -1 2?? ?? 2 ?? 2 ?? 1 2 (2) sin -1 ?? 2 R 2gT 2 1 2 (3) cos -1 2gT 2 ?? 2 R 1 2 (4) cos -1 ?? R 2gT 2 1 2 Q2 - 2024 (29 Jan Shift 1) If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of: (1) 3:2 (2) 1: 3 (3) 3:1 (4) 2: 3 Q3 - 2024 (29 Jan Shift 1) A ball rolls off the top of a stairway with horizontal velocity ?? . The steps are 0.1m high and 0.1m wide. The minimum velocity u with which that ball just hits the step 5 of the stairway will be xms -1 where x = [use g = 10m/s 2 . Q4 - 2024 (30 Jan Shift 1) Page 2 2024 Q1 - 2024 (01 Feb Shift 1) A particle moving in a circle of radius ?? with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle ?? to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection ?? is then given by : (1) sin -1 2?? ?? 2 ?? 2 ?? 1 2 (2) sin -1 ?? 2 R 2gT 2 1 2 (3) cos -1 2gT 2 ?? 2 R 1 2 (4) cos -1 ?? R 2gT 2 1 2 Q2 - 2024 (29 Jan Shift 1) If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of: (1) 3:2 (2) 1: 3 (3) 3:1 (4) 2: 3 Q3 - 2024 (29 Jan Shift 1) A ball rolls off the top of a stairway with horizontal velocity ?? . The steps are 0.1m high and 0.1m wide. The minimum velocity u with which that ball just hits the step 5 of the stairway will be xms -1 where x = [use g = 10m/s 2 . Q4 - 2024 (30 Jan Shift 1) A particle of mass ?? projected with a velocity ' ?? ' making an angle of 30 ° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height his : (1) 3 16 ?? ?? 3 ?? (2) 3 2 ?? ?? 2 ?? (3) ?? ?? 3 2?? (4) zero Q5 - 2024 (30 Jan Shift 2) Projectiles A and B are thrown at angles of 45 ° and 60 ° with vertical respectively from top of a 400m high tower. If their ranges and times of flight are same, the ratio of their speeds of projection ?? ?? :?? ?? is : [We changed options. In official NTA paper no option was correct.] (1) 1: 3 (2) 2:1 (3) 1:2 (4) 1:1 Q6 - 2024 (31 Jan Shift 1) A body starts falling freely from height H hits an inclined plane in its path at height h. As a result of this perfectly elastic impact, the direction of the velocity of the body becomes horizontal. The value of ?? h for which the body will take the maximum time to reach the ground is Answer Key Q1 (1) Q2 (1) Q3 (2) Q4 (1) Q5 (4) Q6 (2) Solutions Q1 2?? R T = V Page 3 2024 Q1 - 2024 (01 Feb Shift 1) A particle moving in a circle of radius ?? with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle ?? to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection ?? is then given by : (1) sin -1 2?? ?? 2 ?? 2 ?? 1 2 (2) sin -1 ?? 2 R 2gT 2 1 2 (3) cos -1 2gT 2 ?? 2 R 1 2 (4) cos -1 ?? R 2gT 2 1 2 Q2 - 2024 (29 Jan Shift 1) If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of: (1) 3:2 (2) 1: 3 (3) 3:1 (4) 2: 3 Q3 - 2024 (29 Jan Shift 1) A ball rolls off the top of a stairway with horizontal velocity ?? . The steps are 0.1m high and 0.1m wide. The minimum velocity u with which that ball just hits the step 5 of the stairway will be xms -1 where x = [use g = 10m/s 2 . Q4 - 2024 (30 Jan Shift 1) A particle of mass ?? projected with a velocity ' ?? ' making an angle of 30 ° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height his : (1) 3 16 ?? ?? 3 ?? (2) 3 2 ?? ?? 2 ?? (3) ?? ?? 3 2?? (4) zero Q5 - 2024 (30 Jan Shift 2) Projectiles A and B are thrown at angles of 45 ° and 60 ° with vertical respectively from top of a 400m high tower. If their ranges and times of flight are same, the ratio of their speeds of projection ?? ?? :?? ?? is : [We changed options. In official NTA paper no option was correct.] (1) 1: 3 (2) 2:1 (3) 1:2 (4) 1:1 Q6 - 2024 (31 Jan Shift 1) A body starts falling freely from height H hits an inclined plane in its path at height h. As a result of this perfectly elastic impact, the direction of the velocity of the body becomes horizontal. The value of ?? h for which the body will take the maximum time to reach the ground is Answer Key Q1 (1) Q2 (1) Q3 (2) Q4 (1) Q5 (4) Q6 (2) Solutions Q1 2?? R T = V Maximum height H = v 2 sin 2 ? ?? 2g 4R = 4?? 2 R 2 T 2 2g sin 2 ? ?? sin? ?? = 2gT 2 ?? 2 R ?? = sin -1 ? 2gT 2 ?? 2 R 1 2 Q2 Given m 1 = m 2 and ?? 1 ?? 2 = 3 4 As centripetal force ?? = ?? 2 ?? In order to have constant (same in this question) centripetal force F 1 = F 2 m 1 v 1 2 r 1 = m 2 v 2 2 r 2 ? v 1 v 2 = r 1 r 2 = 3 2 Q3 Page 4 2024 Q1 - 2024 (01 Feb Shift 1) A particle moving in a circle of radius ?? with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle ?? to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection ?? is then given by : (1) sin -1 2?? ?? 2 ?? 2 ?? 1 2 (2) sin -1 ?? 2 R 2gT 2 1 2 (3) cos -1 2gT 2 ?? 2 R 1 2 (4) cos -1 ?? R 2gT 2 1 2 Q2 - 2024 (29 Jan Shift 1) If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of: (1) 3:2 (2) 1: 3 (3) 3:1 (4) 2: 3 Q3 - 2024 (29 Jan Shift 1) A ball rolls off the top of a stairway with horizontal velocity ?? . The steps are 0.1m high and 0.1m wide. The minimum velocity u with which that ball just hits the step 5 of the stairway will be xms -1 where x = [use g = 10m/s 2 . Q4 - 2024 (30 Jan Shift 1) A particle of mass ?? projected with a velocity ' ?? ' making an angle of 30 ° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height his : (1) 3 16 ?? ?? 3 ?? (2) 3 2 ?? ?? 2 ?? (3) ?? ?? 3 2?? (4) zero Q5 - 2024 (30 Jan Shift 2) Projectiles A and B are thrown at angles of 45 ° and 60 ° with vertical respectively from top of a 400m high tower. If their ranges and times of flight are same, the ratio of their speeds of projection ?? ?? :?? ?? is : [We changed options. In official NTA paper no option was correct.] (1) 1: 3 (2) 2:1 (3) 1:2 (4) 1:1 Q6 - 2024 (31 Jan Shift 1) A body starts falling freely from height H hits an inclined plane in its path at height h. As a result of this perfectly elastic impact, the direction of the velocity of the body becomes horizontal. The value of ?? h for which the body will take the maximum time to reach the ground is Answer Key Q1 (1) Q2 (1) Q3 (2) Q4 (1) Q5 (4) Q6 (2) Solutions Q1 2?? R T = V Maximum height H = v 2 sin 2 ? ?? 2g 4R = 4?? 2 R 2 T 2 2g sin 2 ? ?? sin? ?? = 2gT 2 ?? 2 R ?? = sin -1 ? 2gT 2 ?? 2 R 1 2 Q2 Given m 1 = m 2 and ?? 1 ?? 2 = 3 4 As centripetal force ?? = ?? 2 ?? In order to have constant (same in this question) centripetal force F 1 = F 2 m 1 v 1 2 r 1 = m 2 v 2 2 r 2 ? v 1 v 2 = r 1 r 2 = 3 2 Q3 The ball needs to just cross 4 steps to just hit 5 th step Therefore, horizontal range (R)= 0.4m R = u.t Similarly, in vertical direction h = 1 2 gt 2 0.4 = 1 2 gt 2 0.4 = 1 2 g 0.4 u 2 u 2 = 2 u = 2m/s Therefore, ?? = 2 Q4 L =?? ?? cos? ?? ?? =?? ?? cos? ?? × ?? 2 sin 2 ? ?? 2?? = ?? ?? 3 2?? × 3 2 × 1 2 2 = 3?? ?? 3 16?? Q5 Page 5 2024 Q1 - 2024 (01 Feb Shift 1) A particle moving in a circle of radius ?? with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle ?? to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection ?? is then given by : (1) sin -1 2?? ?? 2 ?? 2 ?? 1 2 (2) sin -1 ?? 2 R 2gT 2 1 2 (3) cos -1 2gT 2 ?? 2 R 1 2 (4) cos -1 ?? R 2gT 2 1 2 Q2 - 2024 (29 Jan Shift 1) If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of: (1) 3:2 (2) 1: 3 (3) 3:1 (4) 2: 3 Q3 - 2024 (29 Jan Shift 1) A ball rolls off the top of a stairway with horizontal velocity ?? . The steps are 0.1m high and 0.1m wide. The minimum velocity u with which that ball just hits the step 5 of the stairway will be xms -1 where x = [use g = 10m/s 2 . Q4 - 2024 (30 Jan Shift 1) A particle of mass ?? projected with a velocity ' ?? ' making an angle of 30 ° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height his : (1) 3 16 ?? ?? 3 ?? (2) 3 2 ?? ?? 2 ?? (3) ?? ?? 3 2?? (4) zero Q5 - 2024 (30 Jan Shift 2) Projectiles A and B are thrown at angles of 45 ° and 60 ° with vertical respectively from top of a 400m high tower. If their ranges and times of flight are same, the ratio of their speeds of projection ?? ?? :?? ?? is : [We changed options. In official NTA paper no option was correct.] (1) 1: 3 (2) 2:1 (3) 1:2 (4) 1:1 Q6 - 2024 (31 Jan Shift 1) A body starts falling freely from height H hits an inclined plane in its path at height h. As a result of this perfectly elastic impact, the direction of the velocity of the body becomes horizontal. The value of ?? h for which the body will take the maximum time to reach the ground is Answer Key Q1 (1) Q2 (1) Q3 (2) Q4 (1) Q5 (4) Q6 (2) Solutions Q1 2?? R T = V Maximum height H = v 2 sin 2 ? ?? 2g 4R = 4?? 2 R 2 T 2 2g sin 2 ? ?? sin? ?? = 2gT 2 ?? 2 R ?? = sin -1 ? 2gT 2 ?? 2 R 1 2 Q2 Given m 1 = m 2 and ?? 1 ?? 2 = 3 4 As centripetal force ?? = ?? 2 ?? In order to have constant (same in this question) centripetal force F 1 = F 2 m 1 v 1 2 r 1 = m 2 v 2 2 r 2 ? v 1 v 2 = r 1 r 2 = 3 2 Q3 The ball needs to just cross 4 steps to just hit 5 th step Therefore, horizontal range (R)= 0.4m R = u.t Similarly, in vertical direction h = 1 2 gt 2 0.4 = 1 2 gt 2 0.4 = 1 2 g 0.4 u 2 u 2 = 2 u = 2m/s Therefore, ?? = 2 Q4 L =?? ?? cos? ?? ?? =?? ?? cos? ?? × ?? 2 sin 2 ? ?? 2?? = ?? ?? 3 2?? × 3 2 × 1 2 2 = 3?? ?? 3 16?? Q5 For u A &u B time of flight and range can not be same. So above options are incorrect. Q6 Total time of flight = TRead More
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