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 Page 1


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
Page 2


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
Page 3


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
 
 
 
  
 
   
2. 
 
 
23
Br AlBr ?
? ? ? ? ? ?
 Br 
 
 Which is intermediate of above reaction :   
 (1) 
 Br 
H 
  (2) 
 
Br 
H 
  (3) 
 AlCl
3 
  (4) 
 
Br 
AlBr
3 
 
Ans. (2) 
Sol. Step 1 : Formation of a stronger electrophile. 
  
Br – :
: :
Br    +   FeBr 
3
: :
: Br – :
: :
Br – 
: :
?
?
FeBr 
3
:
?
?
 
 Step 2 : Electrophilic attack and formation of the sigma complex. 
          
Br – :
: :
Br  FeBr 
3
: :
:
+ H
H
H
H
H
H
? ? ? ? ? ? + FeBr
4
¯ 
 Step 3 : Loss of a proton gives the products. 
    
Br
H
H
H
H
H
bromobenzene
+ HBr + FeBr
3
        
 Other halogenating agents are ICl, HOCl etc.  
 order of effectiveness – Cl
2
 > BrCl > Br
2
 > ICl > I
2
 
 
3. Which of the following is substitution reaction -  
 (1) 
 R–C–OH 
O 
  
ROH/H
?
? ? ? ? ?
 R–C–OR 
O 
   (2) 
 OH 
 
H
?
?
? ? ? ? 
 
   
 (3) 
 R 
C=O 
R 
2
H O/H
?
? ? ? ? ?  
 R 
C 
R 
OH 
OH 
 
  (4) R–MgBr + CH3COOH —? R–H 
Ans. (1) 
Sol.  Reaction involving replacement of –OH group : 
   
 This is nucleophilic substitution reactions. 
 
Page 4


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
 
 
 
  
 
   
2. 
 
 
23
Br AlBr ?
? ? ? ? ? ?
 Br 
 
 Which is intermediate of above reaction :   
 (1) 
 Br 
H 
  (2) 
 
Br 
H 
  (3) 
 AlCl
3 
  (4) 
 
Br 
AlBr
3 
 
Ans. (2) 
Sol. Step 1 : Formation of a stronger electrophile. 
  
Br – :
: :
Br    +   FeBr 
3
: :
: Br – :
: :
Br – 
: :
?
?
FeBr 
3
:
?
?
 
 Step 2 : Electrophilic attack and formation of the sigma complex. 
          
Br – :
: :
Br  FeBr 
3
: :
:
+ H
H
H
H
H
H
? ? ? ? ? ? + FeBr
4
¯ 
 Step 3 : Loss of a proton gives the products. 
    
Br
H
H
H
H
H
bromobenzene
+ HBr + FeBr
3
        
 Other halogenating agents are ICl, HOCl etc.  
 order of effectiveness – Cl
2
 > BrCl > Br
2
 > ICl > I
2
 
 
3. Which of the following is substitution reaction -  
 (1) 
 R–C–OH 
O 
  
ROH/H
?
? ? ? ? ?
 R–C–OR 
O 
   (2) 
 OH 
 
H
?
?
? ? ? ? 
 
   
 (3) 
 R 
C=O 
R 
2
H O/H
?
? ? ? ? ?  
 R 
C 
R 
OH 
OH 
 
  (4) R–MgBr + CH3COOH —? R–H 
Ans. (1) 
Sol.  Reaction involving replacement of –OH group : 
   
 This is nucleophilic substitution reactions. 
 
 
 
 
  
 
   
4. Which is the following undergoes self oxidation and self reduction in same reaction  
 (1) C7H8O  (2) CH2O   (3) C3H7O  (4) C2H4O 
Ans. (2) 
Sol. Cannizzaro reaction :  
 Aldehydes which do not have an ?-hydrogen atom, undergo self oxidation and reduction 
(disproportionation) reaction on treatment with a concentrated alkali. 
       
 
5. Which of the following reaction produces ethylacetoacetate -  
 (1) Cannizaro reaaction    (2) Claisen reaction    
 (3) Reformatsky reaction   (4) Aldol reaction  
Ans. (2) 
Sol. 
 
CH
3
–C–CH
2
–C–O–C
2
H
5
 
O
 
O
 
(ethyl aceto acetate)
 
 
 This is a ?-keto ester which is form by clasinen ester condensation. 
 
6. 
 CH=O 
 
33
3
CH COOCOCH
CH COONa
? ? ? ? ? ? ? ? P ;  
 Major product of above reaction :  
 (1) C6H5–CH=CH–COOH    (2) C6H5–COOH   
 (3) C6H5–CH=CH–COOCH3    (4) C6H5–CH2–CHO 
Ans.  
Sol. Perkin reaction :  
 When aromatic aldehyde like benzaldehyde is treated with anhydride in the presence of sodium salt of 
acid from which anhydride is derived we get ? ? ? ?-unsaturated acid. 
     
 
7. Which of the following alcohol will react fastest with HCl    
 (1) 
 CH
3 
OH
 
  (2) 
 CH
2
OH 
  (3) 
 CH
3
 
OH 
  (4) 
 
H
3
C 
OH 
 
Ans. (4) 
 
Page 5


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
 
 
 
  
 
   
2. 
 
 
23
Br AlBr ?
? ? ? ? ? ?
 Br 
 
 Which is intermediate of above reaction :   
 (1) 
 Br 
H 
  (2) 
 
Br 
H 
  (3) 
 AlCl
3 
  (4) 
 
Br 
AlBr
3 
 
Ans. (2) 
Sol. Step 1 : Formation of a stronger electrophile. 
  
Br – :
: :
Br    +   FeBr 
3
: :
: Br – :
: :
Br – 
: :
?
?
FeBr 
3
:
?
?
 
 Step 2 : Electrophilic attack and formation of the sigma complex. 
          
Br – :
: :
Br  FeBr 
3
: :
:
+ H
H
H
H
H
H
? ? ? ? ? ? + FeBr
4
¯ 
 Step 3 : Loss of a proton gives the products. 
    
Br
H
H
H
H
H
bromobenzene
+ HBr + FeBr
3
        
 Other halogenating agents are ICl, HOCl etc.  
 order of effectiveness – Cl
2
 > BrCl > Br
2
 > ICl > I
2
 
 
3. Which of the following is substitution reaction -  
 (1) 
 R–C–OH 
O 
  
ROH/H
?
? ? ? ? ?
 R–C–OR 
O 
   (2) 
 OH 
 
H
?
?
? ? ? ? 
 
   
 (3) 
 R 
C=O 
R 
2
H O/H
?
? ? ? ? ?  
 R 
C 
R 
OH 
OH 
 
  (4) R–MgBr + CH3COOH —? R–H 
Ans. (1) 
Sol.  Reaction involving replacement of –OH group : 
   
 This is nucleophilic substitution reactions. 
 
 
 
 
  
 
   
4. Which is the following undergoes self oxidation and self reduction in same reaction  
 (1) C7H8O  (2) CH2O   (3) C3H7O  (4) C2H4O 
Ans. (2) 
Sol. Cannizzaro reaction :  
 Aldehydes which do not have an ?-hydrogen atom, undergo self oxidation and reduction 
(disproportionation) reaction on treatment with a concentrated alkali. 
       
 
5. Which of the following reaction produces ethylacetoacetate -  
 (1) Cannizaro reaaction    (2) Claisen reaction    
 (3) Reformatsky reaction   (4) Aldol reaction  
Ans. (2) 
Sol. 
 
CH
3
–C–CH
2
–C–O–C
2
H
5
 
O
 
O
 
(ethyl aceto acetate)
 
 
 This is a ?-keto ester which is form by clasinen ester condensation. 
 
6. 
 CH=O 
 
33
3
CH COOCOCH
CH COONa
? ? ? ? ? ? ? ? P ;  
 Major product of above reaction :  
 (1) C6H5–CH=CH–COOH    (2) C6H5–COOH   
 (3) C6H5–CH=CH–COOCH3    (4) C6H5–CH2–CHO 
Ans.  
Sol. Perkin reaction :  
 When aromatic aldehyde like benzaldehyde is treated with anhydride in the presence of sodium salt of 
acid from which anhydride is derived we get ? ? ? ?-unsaturated acid. 
     
 
7. Which of the following alcohol will react fastest with HCl    
 (1) 
 CH
3 
OH
 
  (2) 
 CH
2
OH 
  (3) 
 CH
3
 
OH 
  (4) 
 
H
3
C 
OH 
 
Ans. (4) 
 
 
 
 
  
 
   
8. Which is correct for cellulose – 
 (1) branched, ?(1,4) – glucose    (2) Unbranched, ?(1,6) – glucose   
 (3) Unbranched, ?(1,4) – glucose  (4) branched, ?(1,4) band ? (1, 6) 
Ans. (3) 
Sol.  
 
Polysaccharide Structure Monomeric unit 
linkage 
Amylose 
 
 
 
 
C1- ? ?D-Glucose + 
C4- ? ?D-Glucose + 
C1- ? ?D-Glucose + 
C4- ? ?D-Glucose... 
Amylopection 
 
 
 
C1- ? ?D-Glucose + 
C4- ? ?D-Glucose... 
Branching at  C1 
? ?D-Glucose + C6 
? ?D-Glucose…. 
Cellulose 
 
CH OH
2
CH OH
2
H
H
OH
OH
OH
OH
H
H
H
H
H
6
6
5
5
1
1
4
4
2
2
3
3
O
O
O
H
H O
n
Cellulose
H
? ? ? (1 4)
 
 
C1- ? ?D-Glucose + 
C4-??D-Glucose + 
C1- ? ?D-Glucose + 
C4-??D-Glucose... 
 
 Unbranched, ?(1,4) – glucose 
 
9. Which of the following is correct for Lactose 
 (1) It is nonreducing sugar   
 (2) Glycosidic bond [1,4] between glucose and galactose    
 (3) Glycosidic bond [1,4] between glucose and fructose   
 (4) Glycosidic bond [1,2] between glucose and galactose 
Ans. (2) 
Sol. Lactose = Glycosidic bond [1,4] between glucose and galactose 
 
10. 
 CH
3 
CH
3 Cl
 
H
 
H
 
H
 
 
and  
 CH
2
Cl 
H
 H
 
CH
3 
H H
 
 are :-  
 (1) Enantiomers  (2) Conformers  (3) Positional isomers (4) None of these  
Ans. (3) 
Sol. 
 CH
3 
CH
3 Cl
 
H
 
H
 
H
 
 
 CH
2
Cl 
H
 H
 
CH
3 
H H
 
 
 
 CH
3 
– CH
2
 – CH – CH
3 
Cl
 
2–Chlorobutane
 
CH
2 
– CH
2
 – CH
2
 – CH
3 
Cl
 
1–Chlorobutane
 
Position Isomer to each each other
 
 
 
 
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FAQs on JIPMER Entrance Exam Solved Paper - 2018 - JIPMER: Subject wise Tests & Practice Mock Tests 2024 - NEET

1. What is the JIPMER Entrance Exam?
Ans. The JIPMER Entrance Exam is an entrance examination conducted by Jawaharlal Institute of Postgraduate Medical Education and Research (JIPMER) for admission to its undergraduate medical programs. It is a highly competitive exam for students aspiring to pursue MBBS at JIPMER.
2. How can I apply for the JIPMER Entrance Exam?
Ans. To apply for the JIPMER Entrance Exam, candidates need to visit the official website of JIPMER and fill out the online application form. They must provide their personal details, academic qualifications, and upload necessary documents as per the instructions provided on the website. After submitting the form, candidates need to pay the application fee and take a printout of the confirmation page for future reference.
3. What is the eligibility criteria for the JIPMER Entrance Exam?
Ans. The eligibility criteria for the JIPMER Entrance Exam include: - Candidates must be Indian nationals or Overseas Citizens of India (OCI). - They should have completed 17 years of age at the time of admission or will complete the age on or before 31st December of the admission year. - Candidates must have passed the qualifying examination (10+2) with Physics, Chemistry, Biology/Biotechnology, and English as core subjects. - They should have obtained a minimum aggregate of 60% (50% for SC/ST/OBC/OPH candidates) in the qualifying examination.
4. What is the exam pattern of the JIPMER Entrance Exam?
Ans. The JIPMER Entrance Exam is a computer-based test consisting of multiple-choice questions. The exam is divided into two sections: Physics, Chemistry, and Biology (100 questions each) and English Language and Comprehension (10 questions). The total number of questions is 200, and each correct answer carries one mark. There is no negative marking in the exam.
5. What is the syllabus for the JIPMER Entrance Exam?
Ans. The syllabus for the JIPMER Entrance Exam is based on the curriculum of the 11th and 12th standard (CBSE/State Board). The topics covered include Physics, Chemistry, Biology, English Language, and Comprehension. Candidates should thoroughly study these subjects and refer to the official JIPMER website for a detailed syllabus.
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JIPMER Entrance Exam Solved Paper - 2018 | JIPMER: Subject wise Tests & Practice Mock Tests 2024 - NEET

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