LMTD Parallel Flow Heat Exchanger (GATE Previous Year Question), Heat and Mass Transfer, GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME - Mechanical Engineering

Oh Joel Kumar said and in this video
taught well I'm going to share with you
and industrial gas I mean of course a
coefficient for media exchanger and it's
the case of parallel flow heat exchanger
you can read it here in the second line
only so how are you are you ready okay
one suggestion I would like to share
with you before watching this video just
pause this video just all this video
don't write this quotient read the
question and try to write what they have
given in the portion and of course don't
forget to remember the simple diagram I
must say that a simple diagram of
parallel flow heat exchanger because in
these type of problems if you know the
tie down then you can utilize the themes
quite easy because heat exchanger is not
situated with you right now so we have
to visualize the things right if you can
base lies better I mean you can be like
visualize it quite easy then you can
solve the problem quite easily don't
have any column I mean you will not face
any problem all right so this is the
case of what parallel flow heat
exchanger right now what did I have
given basically in case of parallel for
X in there okay in just areas flows with
it nah
yeah so they have said that in this Cal
gas CP so they how much they have been
entering 250 degree centigrade CP is
equal to 1 kilo joule per kg Kelvin and
they said with the flow rate 2 kg mass
flow rate is equal to 2 kg per second
right to a heat water steam water stream
CP is equal to 4 kilo joule per kg
Kelvin right and enters a tip enters at
50 degree centigrade oh sorry it's
entering here 50 degree centigrade
now at a flow rate 1 kg per second if
effectiveness that is epsilon is equal
to 0.75 then T h2 is equal to what that
is gas steam temperature
is what so what we have then basically
we need to look at that thing
we have even word we have given th one
we have given TC 1 we have given
effectiveness we have even all these
head capacity so first of all we'll find
out from these heat capacity that is CH
is equal to MCP
m is 2 density is 1 so it's 2 now look
at its unit kilo Joule per kg Kelvin
mass kg per second Casey get cancelled
so 2 kilo Joule per Kelvin second got it
for this is for hot fluid no I mean Cod
stink yes you can say that is given in
the question now go for the coal do one
that is for water right now
C C is equal to again mass flow rate CP
is equal to one multiple it's one I
think so right yeah it's for even CP is
equal to 4 and it's the water CP is 4
and aah-aah mass what is one so for
multiple one kilo Joule per Kelvin
seconds so 4 kilo Joule per Kelvin
seconds so which one is minimum this hot
one is me why I'm sharing with you
because we know the effectiveness of
heat exchange are equal to Q by Q max so
we can write is CH T H 1 minus T H 2 and
C minimum T H 1 minus TC 1 so what we
have to find out from here this and all
values we got to put and we need to just
find out D s 2 and that is our required
answer in this question so we'll put all
values CH what is CH basically to see
minimum is 2 what is th one basically
250 that you can see and what is th 2
that is we have to find out and th one
is 250 minus TC 1 is 50 okay so 2 to get
cancel what is epsilon 0.75 we have
given already you can
Here I am written already right so this
is what this is 200 so 200 multiple 0.75
is equal to 250 minus T edge to the
airport d h2 is equal to 250 minus 200
multiple 7.75 so what is the answer
basically we are getting we have to just
do calculation so hundred now mean it
would be what centigrade degree
centigrade right so the answer is of
Sonia or Sun B is the right answer for
this potion I hope you got some new
information about this question you have
understand the question then share with
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very much hope to see you again in my
next video daughter well bye bye