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Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 PDF Download

Note: The questions provided in this document are similar to the questions that were asked in the actual Olympiad exam. So, we recommend you study these for your Olympiad preparation

Logical Reasoning

Q1: Introducing Aman, Kritika says, "The mother of his daughter is the sole daughter of my father's wife." How is Kritika connected to Aman?
(a) Sister
(b) Sister-in-law
(c) Wife
(d) Cousin

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Ans: (c)

  • Kritika refers to "my father's wife," which is her mother.
  • Since she mentions "the only daughter," it indicates that Kritika is the daughter of her mother.
  • This means Kritika is the wife of Aman, as she is the mother of his daughter.
  • Thus, Kritika is related to Aman as his wife.

Q2: Arrange the following words in the order they would appear in a dictionary and choose the correct option. 
1. Feminine 
2. Feature 
3. Feeding 
4. Fenestration 
5. Feather
(a) 5, 2, 3, 4, 1
(b) 2, 5, 3, 4, 1
(c) 5, 2, 1, 3, 4
(d) 5, 2, 3, 1, 4

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Ans: (d)

  • To arrange the words in dictionary order, we look at the first letter of each word.
  • The first word starting with 'F' is Feather (5), followed by Feature (2), then Feeding (3), and Fenestration (4).
  • Finally, Feminine (1) comes last as it starts with 'F' but is alphabetically after the others.
  • Thus, the correct order is 5, 2, 3, 1, 4, which corresponds to option (d).

Q3: If ‘+’ represents ‘division’, ‘–’ signifies ‘addition’, ‘×’ indicates ‘subtraction’, and ‘÷’ means ‘multiplication’, what is the result of 18 – 12 + 6 ÷ 2 × 5?
(a) 17
(b) 25
(c) 15
(d) 13

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Ans: (a)

  • First, replace the symbols according to the given definitions: 18 + 12 ÷ 6 × 5.
  • Next, perform the operations in the correct order: division first, then multiplication.
  • Calculate 12 ÷ 6 = 2, then 2 × 5 = 10.
  • Finally, add 18 + 10 = 28, but since we have to subtract 12, we do 28 - 12 = 17.

Q4: Identify the number that does not belong in the group.
(a) 13
(b) 15
(c) 21
(d) 28 

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Ans: (a)

  • The question asks to find the odd one out among the numbers listed.
  • All the numbers except 13 are composite numbers, meaning they have more than two factors.
  • 13 is a prime number, which only has two factors: 1 and 13 itself.
  • Thus, 13 is the only number that does not fit with the others in this context.

Q5: If the digits of the following numbers are flipped and then the numbers are sorted in descending order, what will be the total of the digits of the second number?
(a) 20
(b) 21
(c) 11
(d) 25

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Ans: (b)

  • First, reverse the digits of each number provided.
  • Next, arrange these reversed numbers in descending order.
  • Identify the second number in this ordered list.
  • Finally, calculate the sum of its digits to find the answer.

Q6: The bar graph shows the sale of chocolates in 5 months from January to May: What is the total sale of chocolates from January to May?
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) 3000 
(b) 3800 
(c) 4000 
(d) 4500

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Ans: (b)

Q7: How many of the following figures have exactly one line of symmetry?
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) 5 
(b) 6 
(c) 7 
(d) 8

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Ans: (d)

Q8: The portion of a circle bounded by a chord and the arc subtended by the chord is called ____________ of a circle. 
(a) Sector 
(b) Segment 
(c) Radius 
(d) Diameter

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Ans: (b)

Q9: How many lines of symmetry are there in an equilateral triangle? 
(a) 0 
(b) 1 
(c) 2 
(d) 3

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Ans: (d)

Q10: If a train travels 60 km in 1 hour, how far will it travel in 3.5 hours? 
(a) 180 km 
(b) 200 km 
(c) 210 km 
(d) 220 km

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Ans: (c)
The train travels 60 km per hour, so in 3.5 hours it will travel 60 × 3.5 = 210 km.

Q11: A rectangle has a length of 8 cm and a width of 5 cm. What is its perimeter? 
(a) 26 cm 
(b) 30 cm 
(c) 40 cm 
(d) 45 cm

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Ans: (b)
Perimeter of a rectangle is 2 × (length + width) = 2 × (8 + 5) = 26 cm.

Q12: If the sum of two numbers is 30 and one of the numbers is 12, what is the other number? 
(a) 15 
(b) 18 
(c) 12 
(d) 20

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Ans: (b)
The other number is 30 – 12 = 18.

Q13: If a book has 240 pages and you read 30 pages every day, how many days will it take to finish the book? 
(a) 6 
(b) 7 
(c) 8 
(d) 9 

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Ans: (c) 
It will take 240 ÷ 30 = 8 days to finish the book.

Q14: What is the average of these numbers: 
6, 8, 10, 12? 
(a) 8 
(b) 9 
(c) 10 
(d) 11

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Ans: (c)
The average is (6 + 8 + 10 + 12) ÷ 4 = 36 ÷ 4 = 9.

Q15: A box contains 20 red balls and 30 blue balls. What is the ratio of red balls to blue balls? 
(a) 2 : 3 
(b) 1 : 1 
(c) 2 : 5 
(d) 3 : 5

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Ans: (a)
The ratio of red balls to blue balls is 20:30, which simplifies to 2:3.

Mathematical Reasoning

Q16: Determine the value of m, given that the numbers m, 24, 72, and 96 are in proportion.
(a) 12
(b) 36
(c) 18
(d) 26

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Ans: (c)

  • To find m, we use the property of proportions, which states that the product of the means equals the product of the extremes.
  • Here, we set up the equation: m * 96 = 24 * 72.
  • Calculating the right side: 24 * 72 = 1728.
  • Now, we have m * 96 = 1728, so m = 1728 / 96 = 18.
  • Thus, the value of m is 18, confirming that the numbers are in proportion.

Q17: By how much is two-fifths of 125 less than three-eighths of 256?
(a) 52
(b) 46
(c) 58
(d) 42

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Ans: (b)

  • First, calculate two-fifths of 125: (2/5) * 125 = 50.
  • Next, calculate three-eighths of 256: (3/8) * 256 = 96.
  • Now, find the difference: 96 - 50 = 46.
  • Thus, two-fifths of 125 is 46 less than three-eighths of 256.

Q18: The area of a rectangle is 49 cm². If its breadth is 2.8 cm, then find its perimeter.
(a) 40.6 cm
(b) 42.4 cm
(c) 38.6 cm
(d) 46.4 cm 

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Ans: (a)

  • To find the perimeter of the rectangle, we first need to determine its length.
  • Using the formula for the area of a rectangle, Area = Length × Breadth, we can rearrange it to find Length: Length = Area / Breadth.
  • Substituting the values: Length = 49 cm² / 2.8 cm = 17.5 cm.
  • Now, we can calculate the perimeter using the formula: Perimeter = 2 × (Length + Breadth).
  • So, Perimeter = 2 × (17.5 cm + 2.8 cm) = 2 × 20.3 cm = 40.6 cm.

Q19: Which of the following shapes has all the faces the same?
(a) Square Pyramid
(b) Triangular Prism
(c) Cube
(d) Sphere

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Ans: (c)

  • The cube is a three-dimensional shape where all six faces are squares and are identical in size and shape.
  • In contrast, a square pyramid has a square base and triangular faces, while a triangular prism has two triangular bases and rectangular sides.
  • A sphere is a round shape with no faces at all, making it different from the cube.
  • Thus, the only shape with all identical faces is the cube.

Q20: Calculate the total of all odd factors of 42.
(a) 31
(b) 11
(c) 32
(d) 34

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Ans: (c)

  • To find the odd factors of 42, we first determine its prime factorization: 42 = 2 × 3 × 7.
  • We ignore the factor of 2 since we are only interested in odd factors.
  • The odd factors come from the product of the remaining prime factors: 3 and 7.
  • The odd factors of 42 are: 1, 3, 7, and 21. Adding these gives us 1 + 3 + 7 + 21 = 32.

Q21: Which of the following is equivalent to ( 0.004/0.4 + 0.4/0.004 )?
(a) 10.001
(b) 100.1
(c) 100.01
(d) 10.01

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Ans: (c)

  • To solve the expression, first calculate 0.004/0.4, which equals 0.01.
  • Next, calculate 0.4/0.004, which equals 100.
  • Now, add the two results: 0.01 + 100 = 100.01.
  • Thus, the final answer is 100.01, which corresponds to option (c).

Q22: If x = 30, y = 40, and z = 8, what is the result of x ÷ (y ÷ z)?
(a) 25
(b) 5
(c) 6
(d) 4

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Ans: (c)

  • To solve for x ÷ (y ÷ z), first calculate y ÷ z.
  • Here, y = 40 and z = 8, so 40 ÷ 8 = 5.
  • Now, substitute this back into the equation: x ÷ 5 where x = 30.
  • Thus, 30 ÷ 5 = 6, which is the final answer.

Q23: Which of the following properties is illustrated in the equation 3 × (7 + 5) = (3 × 7) + (3 × 5)?
(a) Closure
(b) Commutative
(c) Distributive
(d) Identity

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Ans: (c)

  • The equation demonstrates the Distributive Property, which states that multiplying a number by a sum is the same as multiplying that number by each addend and then adding the results.
  • In this case, 3 is distributed to both 7 and 5 inside the parentheses.
  • This property is essential in simplifying expressions and solving equations.
  • Closure, Commutative, and Identity properties do not apply to this specific equation.

Q24: The sum of all the factors of a perfect number is ________ the number.
(a) Twice
(b) Equal to
(c) Half of
(d) Can’t be determined

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Ans: (a)

  • The definition of a perfect number is that it is equal to the sum of its proper divisors (excluding itself).
  • For example, the number 6 is a perfect number because its factors are 1, 2, and 3, and 1 + 2 + 3 = 6.
  • When you include the number itself, the sum of all factors becomes twice the perfect number.
  • Thus, the correct answer is that the sum of all factors of a perfect number is twice the number itself.

Q25: Subtract the total of 23.456 and 18.75 from 98.735 and round the result to the nearest hundredths.
(a) 56.52
(b) 56.53
(c) 56.50
(d) 56.529

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Ans: (b)

  • First, calculate the sum of 23.456 and 18.75, which equals 42.206.
  • Next, subtract this sum from 98.735: 98.735 - 42.206 = 56.529.
  • Finally, round 56.529 to the nearest hundredths, which gives you 56.53.
  • Thus, the correct answer is (b) 56.53.

Q26: The perpendicular bisector of a line segment is a perpendicular to the line segment that divides it into ________ parts.
(a) Two unequal
(b) Three unequal
(c) Three equal
(d) Two equal

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Ans: (d)

  • The perpendicular bisector is a line that cuts another line segment into two equal parts at a 90-degree angle.
  • This means that the two segments created by the bisector are of equal length.
  • Thus, the correct answer is that it divides the line segment into two equal parts.
  • Options (a), (b), and (c) are incorrect because they suggest unequal or more than two parts.

Q27: Examine the following statements and choose the accurate option. 
P: The Roman numeral V can only be subtracted from X. 
Q: The smallest 4-digit number that can be created using the digits 1, 4, 0, and 9 without repeating any digit is 1409. 
(a) Both P and Q are true. 
(b) Both P and Q are false. 
(c) Only P is true. 
(d) Only Q is true. 

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Ans: (b)

  • Statement P is false because V can also be subtracted from other Roman numerals, not just X.
  • Statement Q is also false since the smallest 4-digit number formed by the digits 1, 4, 0, and 9 is actually 1049, not 1409.
  • Thus, both statements are incorrect, leading to the conclusion that the correct answer is option (b).

Q28: Which of the following is best represented by the integer -50?
(a) Price of mangoes is increased by ₹50 per kg.
(b) Size of a shape is enlarged by 50%.
(c) A submarine is 50 km below sea level.
(d) The height of the tower is 50 feet below sea level.

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Ans: (c)

  • The integer -50 indicates a negative value, which is often used to represent something below a reference point.
  • In this case, a submarine being 50 km below sea level is the correct interpretation of -50, as it signifies depth.
  • The other options either represent positive changes or heights above sea level, which do not align with the negative integer.
  • Thus, the correct answer is that the submarine's position is best represented by -50.

Q29: Determine the value of p in the equation 2p – p/3 = 35.
(a) 5
(b) 3
(c) 15
(d) 21

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Ans: (d)

  • To solve the equation 2p – p/3 = 35, first, we need to eliminate the fraction. We can do this by multiplying the entire equation by 3.
  • This gives us 6p - p = 105 (since 3 * 35 = 105).
  • Now, combine like terms: 5p = 105.
  • Next, divide both sides by 5 to find p = 21.

Q30: Product of a number by 3 is equal to 171 then the number is:
(a) 53
(b) 63
(c) 57
(d) 97

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Ans: (c) 
The product of a number by 3 is equal to 171.
3x = 171
x = 171/3 = 57 ⇒ x = 57

Q31: Find the number which when multiplied by 12 gives 36.
(a) 3
(b) 8
(c) 4
(d) 12

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Ans: (a) 
The number which when multiplied by 12 gives 36
12 × x=36x 
x = 36/12 = 3

Q32: The point that lies in the interior of ∠SOP is
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) X
(b) Z
(c) Y
(d) T

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Ans: (b) 
The point Z lies in the interior of ∠SOP.

Q33: How many triangles are there in the figure?
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) 4
(b) 8
(c) 7
(d) 5

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (b)

Q34: Look at the given figure and note that no 3 points are collinear points. The maximum number of triangles that can be formed by using any 3 points is ___________.
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) 35
(b) 40
(c) 25
(d) 30

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Ans: (a)

Q35: The number of angles in the figure is
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) 3
(b) 4
(c) 5
(d) 6

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (d)

Everyday Mathematics

Q36: Mrs. Sharma has a monthly income of ₹45000. After spending ₹38750, she saves the remaining amount. What is the ratio of her savings to her total income?
(a) 4 : 35
(b) 6 : 35
(c) 7 : 36
(d) 5 : 36 

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (d)

  • Mrs. Sharma's total income is ₹45000.
  • Her total spending is ₹38750.
  • To find her savings, subtract spending from income: ₹45000 - ₹38750 = ₹6250.
  • The ratio of her savings to her income is 6250 : 45000, which simplifies to 5 : 36.

Q37: A scientist took two samples. He froze one sample at –39°C and the other at –62°C. What is the temperature difference between these two samples?
(a) 31°C
(b) 23°C
(c) –23°C
(d) –31°C 

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Ans: (b)

  • To find the temperature difference, subtract the lower temperature from the higher temperature.
  • The higher temperature is –39°C and the lower temperature is –62°C.
  • Calculating this gives: –39°C - (–62°C) = –39°C + 62°C = 23°C.
  • Thus, the temperature difference between the two samples is 23°C.

Q38: 950 crankcases are produced daily in a factory. If the factory operates every day during the months of October, November, and December, how many crankcases will be produced in total during these three months?
(a) 83700
(b) 85400
(c) 84700
(d) 87400

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Ans: (d)

  • The total number of days in October, November, and December is 31 + 30 + 31 = 92 days.
  • Daily production is 950 crankcases.
  • To find the total production, multiply the daily production by the total number of days: 950 * 92 = 87400.
  • Thus, the total number of crankcases manufactured in these three months is 87400.

Q39: The floor of a room with dimensions 15 m and 13 m is to be covered with square tiles. If each square tile is of side 25 cm, then find the number of tiles required.
(a) 3240
(b) 3040
(c) 2860
(d) 3120

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Ans: (d)

  • First, calculate the area of the room: 15 m * 13 m = 195 m2.
  • Convert the area to square centimeters: 195 m2 = 1,950,000 cm² (since 1 m² = 10,000 cm2).
  • Next, find the area of one tile: (25 cm)2 = 625 cm2.
  • Finally, divide the total area of the room by the area of one tile: 1,950,000 cm2 / 625 cm2 = 3120 tiles.

Q40: Sneha has ₹40x. She spent ₹250 on food, ₹75y on clothes, ₹375 on travel, and received ₹1500 as a birthday gift. How much money is left with her?
(a) ₹(40x + 75y – 875)
(b) ₹(40x – 75y + 875)
(c) ₹(40x – 75y – 875)
(d) ₹(40x + 25y + 845)

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Ans: (b)

  • To find out how much money Sneha has left, we start with her total amount, which is ₹40x.
  • She spent ₹250 on food, ₹75y on clothes, and ₹375 on travel, totaling ₹(250 + 75y + 375) = ₹(625 + 75y).
  • She also received ₹1500 as a birthday gift, so we add this to her total.
  • The final calculation for the money left is: ₹40x + ₹1500 - (₹625 + 75y) = ₹(40x - 75y + 875).

Q41: A milkman delivers 28 litres of milk to a community in the morning and 36 litres in the evening. If the price of milk is ₹62 per litre, what is the total amount of money the milkman makes in a day?
(a) ₹3246
(b) ₹4242
(c) ₹3968
(d) ₹3846

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Ans: (c)

  • First, calculate the total milk supplied: 28 litres in the morning + 36 litres in the evening = 64 litres.
  • Next, find the total earnings by multiplying the total litres by the cost per litre: 64 litres × ₹62 = ₹3968.
  • Thus, the milkman earns ₹3968 in a day from selling milk.

Q42: Sarthak purchased Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 meters of ribbon, while Saumya acquired Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 meters of ribbon. Who has more ribbon and by what amount?
(a) Sarthak, 11/72 m
(b) Sarthak, 13/72 m
(c) Saumya, 11/72 m
(d) Saumya, 13/72 m

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (a)

  • To determine who bought more ribbon, we need to compare Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 m and Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 m.
  • First, convert both mixed numbers to improper fractions: Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 = 99/8 and Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 = 110/9.
  • Next, find a common denominator (which is 72) to compare the two fractions: 99/8 = 891/72 and 110/9 = 880/72.
  • Since 891/72 is greater than 880/72, Sarthak bought more ribbon by 11/72 m.

Q43: The population of a city in the year 2019 was 3546253. Round off the population to the nearest ten thousands.
(a) 3540000
(b) 3550000
(c) 3546000
(d) 3500000 

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (b)

  • To round off the number 3546253 to the nearest ten thousand, we look at the digit in the thousands place, which is 6.
  • Since 6 is greater than or equal to 5, we round up the ten thousand place from 4 to 5.
  • This means that 3546000 becomes 3550000 when rounded to the nearest ten thousand.
  • Thus, the rounded population is 3550000.

Q44: Deepak had 17.45 litres of water. After giving 8.30 litres to his neighbour, how much water does he have left?
(a) 9.30 litres
(b) 5.45 litres
(c) 9.15 litres
(d) 5.82 litres 

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Ans: (c)

  • To find out how much water Deepak has left, we need to subtract the amount he gave away from the total he had.
  • He started with 17.45 litres and gave away 8.30 litres.
  • So, we calculate: 17.45 - 8.30 = 9.15 litres.
  • This means Deepak has 9.15 litres of water remaining.

Q45: Find the value of y from the given figure.
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6(a) 30°
(b) 100°
(c) 170°
(d) 80°

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (a) 
70°+y=100° 
y=100°-70° =30°

Achievers Section

Q46: Examine the statements below and choose the accurate option. Enclosed by an arc and a chord. 
Statement-1: A chord of a circle is a line segment connecting any two points on the circle. 
Statement-2: A segment of a circle is a region within the circle.
(a) Both Statement-1 and Statement-2 are false.
(b) Both Statement-1 and Statement-2 are true.
(c) Statement-1 is true but Statement-2 is false.
(d) Statement-1 is false but Statement-2 is true.

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Ans: (b)

  • Statement-1 is true because a chord indeed connects any two points on the circle.
  • Statement-2 is also true as a segment of a circle refers to the area enclosed by a chord and the arc connecting its endpoints.
  • Both statements accurately describe properties of a circle, making option (b) the correct choice.
  • Understanding these definitions is essential for grasping basic circle geometry.

Q47: The number of times an observation is repeated in a data is called
(a) Frequency
(b) Sample
(c) Pie chart
(d) None of these

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (a)

Q48: When it become tedious to represent data by pictograph, we go to represent data by
(a) Bar graph
(b) Line graph
(c) Tally marks
(d) None of these

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (a)

Q49: A rectangular room is 10 m wide and 6 m high. If the area of its four walls is 540 m2, then its length will be
(a) 40m
(b) 70m
(c) 45m
(d) 35m

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (d)
Area of room = 540 m2
2(l+b) h=540
Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6

Q50: Think of an even number 2x, then the next odd number is
(a) 2x-1
(b) 2x+1
(c) 2x+2
(d) 2x-2

Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6  View Answer

Ans: (b)

The document Maths Olympiad Model Test Papers -3 | Maths Olympiad Class 6 is a part of the Class 6 Course Maths Olympiad Class 6.
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FAQs on Maths Olympiad Model Test Papers -3 - Maths Olympiad Class 6

1. What topics are covered in the Class 6 Maths Olympiad Model Test Papers?
Ans.The Class 6 Maths Olympiad Model Test Papers typically cover a range of topics including Logical Reasoning, Mathematical Reasoning, and Everyday Mathematics. These areas help students develop their problem-solving skills and apply mathematical concepts in various situations.
2. How can I prepare effectively for the Class 6 Maths Olympiad?
Ans.To prepare effectively for the Class 6 Maths Olympiad, students should practice past exam papers, focus on understanding key concepts in each topic, and work on time management skills. Regular practice and solving model test papers can also greatly enhance confidence and performance.
3. Are there any specific strategies for solving Logical Reasoning questions in the Olympiad?
Ans.Yes, some effective strategies for solving Logical Reasoning questions include carefully reading the problem, identifying patterns or relationships, and using process of elimination to narrow down choices. Practicing different types of logical puzzles can also help improve these skills.
4. What is the importance of Everyday Mathematics in the Class 6 Maths Olympiad?
Ans.Everyday Mathematics is important in the Class 6 Maths Olympiad as it helps students apply mathematical concepts to real-life scenarios. This not only enhances their practical understanding of mathematics but also prepares them for everyday problem-solving situations.
5. How do Olympiad scores benefit students in their academic journey?
Ans.Olympiad scores can benefit students by showcasing their mathematical abilities and critical thinking skills, which can be advantageous for future academic opportunities, including scholarships and advanced courses. High scores also boost confidence and encourage a deeper interest in mathematics.
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