Maths Olympiad Previous Year Paper -2 | Maths Olympiad Class 6 PDF Download

Ans: (c)

• The woman refers to Ankit's mother as the only daughter of her own mother, which means she is Ankit's mother.
• This indicates that the woman is Ankit's mother herself, as she is talking about her own child.
• Thus, the correct answer is that the lady is Ankit's mother.

Ans: (a)

• The series consists of three parts: letters, numbers, and letters again.
• The first letters are increasing by 2: B, D, F, H, and the next is J.
• The numbers are increasing by 3: 4, 7, 11, 16, leading to 22.
• The last letters are decreasing by 1: M, L, K, J, so the next is I.

Ans: (a)

• The letters given are L, J, N, U, G, E.
• By following the combination 2, 4, 3, 5, 1, 6, we get the arrangement: J, U, N, G, L, E.
• This spells the meaningful word "JUNGLE".
• Thus, the correct option is (a) as it forms a valid English word.

Ans: (b)

• The coding system rearranges the letters of the word.
• In the example, CREDIT is transformed into CDEIRT by sorting the letters.
• Applying the same method to SAFEST, we sort the letters to get AEFSST.
• Thus, the correct coded form of SAFEST is AEFSST.

Ans: (c)

• First, replace the symbols according to the given definitions: 14 ÷ 6 becomes 14 × 6, 8 remains 8, 4 × 10 becomes 4 – 10, and 6 – 8 becomes 6 + 8.
• Now, calculate: 14 × 6 = 84, then 84 – 8 = 76, and finally 76 + 4 = 76.
• The final result is 76, which corresponds to option (c).
• Thus, the answer is 76.

Ans: (c)
Total female members in the family = 1 + 4 + 3 + 2 × 2 + 2 × 1 = 14

Ans: (b)
The pattern followed is,

Ans: (a)

Ans: (c)
Each level has 9 cubes and there are two levels. Total is 18

Ans: (a)

Ans: (c)

Ans: (b)

Ans: (a)

Ans: (a)
Pattern is +5, +7, +9, +11
So next number will be +13
=> 33+13 = 46

Ans: (d)

Ans: (d)

• The word "MATHEMATICS" has a total of 11 letters.
• It contains 4 vowels: A, E, A, I.
• The fraction of vowels is calculated as number of vowels divided by total letters, which is 4/11.
• Thus, the correct answer is 4/11.

Ans: (a)

• The face value of a digit is the value of the digit itself, which for 3 is simply 3.
• The place value of a digit depends on its position in the number. In 637258, the 3 is in the thousands place, so its place value is 3000.
• To find the difference, subtract the face value from the place value: 3000 - 3 = 2997.
• Thus, the difference between the place value and face value of 3 in 637258 is 2997.

Ans: (b)

• To find the prime factors of 7350, we start by dividing it by the smallest prime number, which is 2. This gives us 3675.
• Next, we continue factoring 3675 by dividing by 3, resulting in 1225.
• Then, we factor 1225 by dividing by 5, leading to 245, and again by 5 to get 49.
• Finally, we factor 49 as 7 multiplied by 7. Thus, the prime factors of 7350 are 2, 3, 5, and 7.
• Counting these, we find there are 4 distinct prime factors: 2, 3, 5, and 7.

Ans: (d)

• Vicky is 5 years older than his cousin.
• If Vicky's age is x years, then to find his cousin's age, we need to subtract 5 from x.
• This gives us the formula: cousin's age = x - 5.
• Thus, the correct answer is (d) x – 5.

Ans: (b)

• First, we add 0.90 and 34.77, which gives us 35.67.
• Next, we subtract 23.03 from 35.67.
• The calculation is 35.67 - 23.03 = 12.64.
• Thus, the final answer is 12.64, which corresponds to option (b).

Ans: (c)

• The expression 75 divided by 491/1000 can be simplified by multiplying 75 by the reciprocal of 491/1000, which is 1000/491.
• This calculation results in approximately 75.491, which is the correct decimal form.
• Understanding how to convert fractions to decimals is key here, as it involves basic division.
• Thus, the correct answer is 75.491.

Ans: (c)

• The rectangle has two lines of symmetry: one vertical and one horizontal.
• In contrast, an equilateral triangle has three lines of symmetry, while an isosceles triangle has one.
• A square has four lines of symmetry, which is more than two.
• Thus, the only shape with exactly two lines of symmetry is the rectangle.

Ans: (b)

• The phrase describes a large number broken down into parts: two hundred fifty-three million (253,000,000), five hundred three thousand (503,000), and four hundred two (402).
• When combined, these parts form the number 253,503,402.
• In the International System of Numeration, commas are used to separate groups of three digits, making it easier to read large numbers.
• Thus, the correct numeral form is 253,503,402.

Ans: (b)

• The statement that every whole number has a successor is true. A successor is the number that comes right after a given number.
• For example, the successor of 5 is 6, and this applies to all whole numbers.
• In contrast, the smallest natural number is 1, not 0, and the smallest whole number is 0.
• Also, the predecessor of a two-digit number can be a one-digit number, so that statement is incorrect.

Ans: (d)

• To find out how many times the player scored at least 2 goals, we need to count the occurrences of scores that are 2 or higher.
• The scores are: 2, 3, 2, 1, 0, 4, 3, 1, 2, 0, 3, 2, 1, 3, 0, 2, 5, 2, 4, 3, 1, 2, 1, 3.
• Counting the scores of 2, 3, 4, and 5, we find that they appear 16 times in total.
• Thus, the player scored at least 2 goals a total of 16 times.

Ans: (a)
If (9 × 4) + (n × 5) = 9 × (4 + 5)  then by distributive property, n = 9

Ans: (b)

Ans: (b)

Ans: (b) Straight angle = 180º  
A + 63º = 180º  
A = 180º – 63º  
A = 117º

Ans: (a)

In right angled ΔADC,

Ans: (b) 
(–11) + 1 = (–10) 

Ans: (d) 
+5°C + (–10°C) = –5°C

Ans: (c)

Ans: (b)
Fraction of shaded parts in the picture = 3/8
Reciprocal of shaded parts in the picture

Ans: (a)
Let the total no. of athletes = x 

Ans: (c)

• First, calculate the length of the park: Length = 2 * Breadth - 7 = 2 * 65 - 7 = 130 - 7 = 123 m.
• Next, find the perimeter of the rectangular park: Perimeter = 2 * (Length + Breadth) = 2 * (123 + 65) = 2 * 188 = 376 m.
• Now, to find the total distance Arpita travels, multiply the perimeter by the number of rounds: Total Distance = 5 * Perimeter = 5 * 376 = 1880 m.
• Thus, the total distance travelled by Arpita is 1880 meters.

Ans: (b)

• The problem requires finding the least common multiple (LCM) of the numbers 2, 3, 5, and 6.
• The LCM is the smallest number that can be evenly divided by all these group sizes.
• The LCM of 2, 3, 5, and 6 is 30, which means 30 students can be divided into groups of these sizes without any remainder.
• Thus, the minimum number of students in the class is 30.

Ans: (d)

• To find the cost of one egg, divide the total cost of 5 eggs by 5: 27.50 / 5 = 5.50.
• To find the cost of one omelette, divide the total cost of 5 omelettes by 5: 60 / 5 = 12.
• The ratio of the cost of one egg to the cost of one omelette is 5.50:12.
• To simplify, convert 5.50 to a fraction: 5.50 = 11/2, so the ratio becomes (11/2):12, which simplifies to 11:24.

Ans: (a)

• First, convert the distances to improper fractions: km is 8/5 km and km is 3/2 km.
• Next, find a common denominator to subtract: 8/5 km - 3/2 km = 8/5 km - 15/10 km = 16/10 km - 15/10 km = 1/10 km.
• Thus, the distance Rohit still needs to run is 1/10 km.

Ans: (c)

• To find the side of the square field, we first need to determine the area of the field. The area can be calculated by dividing the total cost by the cost per square meter.
• The total cost is ₹ 612 and the cost per square meter is ₹ 17. So, the area = 612 / 17 = 36 sq. m.
• Since the field is square, the area (A) is equal to the side length (s) squared: A = s². Therefore, s² = 36.
• Taking the square root of both sides gives us s = 6 m. Thus, the side of the field is 6 meters.

Ans: (c)

• The number 2860 in Roman numerals is represented as MMDCCCLX.
• To break it down: 2000 is MM, 800 is DCCC, and 60 is LX.
• When combined, they form MMDCCCLX, which is the correct representation.
• Thus, the answer is option (c).

Ans: (a)

• Initially, Arun has ₹ 125 in his account.
• After withdrawing ₹ 117, the balance becomes ₹ 8 (125 - 117).
• Then, he deposits ₹ 45, making the new balance ₹ 53 (8 + 45).
• Finally, after withdrawing ₹ 69, the balance is ₹ (16) (53 - 69).
• Since the amount is negative, it is represented as ₹ (–16).

Ans: (d)

• To find the total production of Q type laptops, we need to subtract the production of P type laptops from the total production.
• The total production is 8,75,677 and the production of P type laptops is 3,37,563.
• So, the calculation is: 8,75,677 - 3,37,563 = 5,38,114.
• Thus, the total production of Q type laptops is 5,38,114.

Ans: (a)

• First, calculate the total spent on chocolates: 2 boxes × ₹ 52.98 = ₹ 105.96.
• Next, calculate the total for chips: 3 packets × ₹ 12.98 = ₹ 38.94.
• Then, calculate the total for books: 2 books × ₹ 300.05 = ₹ 600.10.
• Add all the expenses: ₹ 105.96 + ₹ 38.94 + ₹ 600.10 = ₹ 744.00.
• Finally, subtract the total expenses from the initial amount: ₹ 5000 - ₹ 744.00 = ₹ 4256.00.

Thus, Prerna has ₹ 4255 left after her purchases.

Ans: (d)

• First, we round each number to the nearest ten:
• 1248 rounds to 1250 (since 8 is 5 or more).
• 3127 rounds to 3130 (since 7 is 5 or more).
• 4105 rounds to 4110 (since 5 is 5 or more).
• Now, we add these rounded numbers: 1250 + 3130 + 4110 = 8490.
• Since 8490 is not listed in the options, the correct answer is None of these.

Ans: (a)

Ans: (c)

Ans: (c) 
Data obtained in original form is called  Raw data.

Ans: (a)

Ans: (d)
Average age of 5 children = 8 yrs 4 months 
Total age of 5 children 
= 5 x (8 yrs 4 months) 
= 40 yrs 20 months 
= 41 yrs 8 months 
Average age of 4 children = 7 yrs. 10 months 
Total age of 4 children =4 x (7 yrs 10 months) = 31 yrs 4 months
∴ Age of fifth child
= 41 yrs 8 months - 31 yrs 4 months
= 10 yrs 4 months