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NCERT Solutions Chapter 12 - Heron's Formula (I), Class 9, Maths PDF Download

1. A traffic signal board, indicating 'SCHOOL AHEAD', is an equilateral triangle with side 'a'. Find the area of the signal board, using Heron’s formula. If its perimeter is 180 cm, what will be the area of the signal board?

Answer
Length of the side of equilateral triangle = a
Perimeter of the signal board = 3a = 180 cm
∴ 3a = 180 cm ⇒ a = 60 cm
Semi perimeter of the signal board (s) = 3a/2
Using heron's formula,
Area of the signal board
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths

2. The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield an earning of ₹5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

Class IX, Mathematics, NCERT, CBSE, Questions and Answer, Q and A, Important

Answer
The sides of the triangle are 122 m, 22 m and 120 m.
Perimeter of the triangle is 122 + 22 + 120 = 264m
Semi perimeter of triangle (s) = 264/2 = 132 m
Using heron's formula,
Class IX, Mathematics, NCERT, CBSE, Questions and Answer, Q and A, Important



3. There is a slide in a park. One of its side walls has been painted in some colour with a message “KEEP THE PARK GREEN AND CLEAN” (see Fig. 12.10 ). If the sides of the wall are 15 m, 11 m and 6 m, find the area painted in colour.

Class IX, Mathematics, NCERT, CBSE, Questions and Answer, Q and A, Important

Answer

Sides of the triangular wall are 15 m, 11 m and 6 m.
Semi perimeter of triangular wall (s) = (15 + 11 + 6)/2 m = 16 m
Using heron's formula, 
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths


4. Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.

 Answer

Two sides of the triangle = 18cm and 10cm
Perimeter of the triangle = 42cm
Third side of triangle = 42 - (18+10) cm = 14cm
Semi perimeter of triangle = 42/2 = 21cm
Using heron's formula,
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths

5. Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540cm. Find its area.

 Answer

Ratio of the sides of the triangle = 12 : 17 : 25
Let the common ratio be x then sides are 12x, 17x and 25x
Perimeter of the triangle = 540cm
12x + 17x + 25x = 540 cm
⇒ 54x = 540cm
⇒ x = 10
Sides of triangle are,
12x = 12 × 10 = 120cm
17x = 17 × 10 = 170cm
25x = 25 × 10 = 250cm
Semi perimeter of triangle(s) = 540/2 = 270cm
Using heron's formula,
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths  

6. An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
 Answer

Length of the equal sides = 12cm
Perimeter of the triangle = 30cm
Length of the third side = 30 - (12+12) cm = 6cm
Semi perimeter of the triangle(s) = 30/2 cm = 15cm
Using heron's formula,
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths
NCERT Solutions Chapter 12 - Heron`s Formula (I), Class 9, Maths

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FAQs on NCERT Solutions Chapter 12 - Heron's Formula (I), Class 9, Maths

1. What is Heron's formula?
Ans. Heron's formula is used to calculate the area of a triangle when the lengths of all three sides are known. It states that the area (A) of a triangle with side lengths a, b, and c can be calculated using the formula: A = √(s(s-a)(s-b)(s-c)), where s is the semi-perimeter of the triangle calculated as (a+b+c)/2.
2. How is Heron's formula derived?
Ans. Heron's formula can be derived using the principle of area addition. By dividing a triangle into smaller triangles, we can find the area of the original triangle by summing up the areas of these smaller triangles. By applying trigonometry and simplifying the expression, we arrive at the formula A = √(s(s-a)(s-b)(s-c)).
3. What is the significance of Heron's formula?
Ans. Heron's formula is significant because it provides a direct method to calculate the area of a triangle without relying on the height or base length. It is particularly useful when the height or base length is not known, or when dealing with irregular triangles that cannot be easily divided into right-angled triangles.
4. Can Heron's formula be used for all types of triangles?
Ans. Yes, Heron's formula can be used for all types of triangles, including equilateral, isosceles, and scalene triangles. It is a general formula that applies to any triangle as long as the lengths of all three sides are known.
5. How is Heron's formula helpful in real-life applications?
Ans. Heron's formula is used in various real-life applications, especially in fields such as architecture, engineering, and construction. It helps in calculating the areas of irregularly shaped land or surfaces, which is crucial for determining the required materials, estimating costs, and planning projects accurately. Additionally, it is also used in geometry problems and mathematical modeling.
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