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NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

Question: Observe the following tables and ⇒nd which pair of variables (here x and y) are in inverse proportion.

(i) 

x

so

40

30

20

y

5

6

7

S

(ii)

x

100

200

300

400

y

60

30

20

15

(iii)

x

90

60

45

30

20

5

y

10

15

20

25

30

35


Solution:
(i) ∵ x1 = 50 and y1 = 5 ⇒ x1y1 = 50 * 5 = 250
       x2 = 40 and y2 = 6 ⇒ x2y2 = 40 * 6 = 240
       x3 = 30 and y3 = 7 ⇒ x3y3 = 30 * 7 = 210
       x4 = 20 and y4 = 8 ⇒ x4y= 20 * 8 = 160

Also 250 ≠ 240 ≠ 210 ≠ 160 or
x1y1 ≠ x2y2 ≠ x3y3 ≠ x4y4
∴ x and y are not in inverse proportion

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
and x1y1 = x2y2 = x3y3 = x4y4

∴ x and y are in inverse proportion.

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
                NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
and x1y1 = x2y2 = x3y3 ≠ x4y4 ≠ x5y5 ≠ x6y6

∴ x and y are not in inverse variation.

EXERCISE 13.2

Question 1. Which of the following are in inverse proportion?

(i) The number of workers on a job and the time to complete the job.
(ii) The time taken for a journey and the distance travelled in a uniform speed.
(iii) Area of cultivated land and the crop harvested.
(iv) The time taken for a fixed journey and the speed of the vehicle.
(v) The population of a country and the area of land per person.

Solution:

REMEMBER

If an increase in one quantity brings about a corresponding decrease in the other and vice versa, then the two quantities vary inversely.

(i) If number of workers are increased then time to complete the job would decrease.
∴ It is a case of inverse variation.

(ii) For longer distance, more time would be required.
∴ It is not a case of inverse variation

(iii) For more area of land, more crops would be harvested.
∴ It is not a case of inverse variation.

(iv) If speed is more, time to cover a fixed distance would be less.
∴ It is a case of inverse variation.

(v) For more population, less area per person would be required.
∴ It is a case of inverse variation.

Question 2. In a television game show, the prize money of Rs 1,00,000 is to be divided equally amongst the winners. Complete the following table and find whether the prize money given to an individual winner is directly or inversely proportional to the number of winners?

Number of winners

1

2

4

5

8

10

20

Prize for each winner (in Rs)

1,00,000

50,000

 

...

...


Solution: If more the number of winners, less is the prize money.

∴ It is a case of inverse proportion.
NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
Thus, the table is completed as under:

Number of winners

1

2

4

5

8

10

20

Prize for each winner (in Rs)

1,00,000

50,000

25,000

20,000

12,500

10,000

5,000


Question 3. Rehman is making a wheel using spokes. He wants to fix equal spokes in such a way that the angles between any pair of consecutive spokes are equal. Help him by completing the following table.

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

Number of spokes4681012
Angle between a pair of consecutive spokes90o60o............


(i) Are the number of spokes and the angles formed between the pairs of consecutive spokes in inverse proportion?
(ii) Calculate the angle between a pair of consecutive spokes on a wheel with 15 spokes.
(iii) How many spokes would be needed, if the angle between a pair of consecutive spokes is 40°?

Solution: (i) Obviously, more the number of spokes, less is the measure of angle between a pair of consecutive spokes.

∴ It is a case of inverse variation.

Thus,

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
Thus, the table is completed as under

Number of spokes

4

6

8

10

12

Angle between a pair of consecutive spokes

90°

60°

45°

36°

30°


(ii) Let the required measure of angle be x°.

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
(iii) Let required number of spokes be n.

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
∴ The required number of spokes = 9

Question 4. If a box of sweets is divided among 24 children, they will get 5 sweets each. How many would each get, if the number of the children is reduced by 4?

Solution: Reduced number of children = 24 – 4 = 20

Since, more the number of children, less is the quantity of sweets.
∴ It is a case of inverse variation.
i.e. 24 * 5 = 20 * x
or   NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
∴ Each student will get 6 sweets.
 

Question 5. A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?

Solution: Number of animals added = 10

∴ Now, the total number of animals = 10 + 20 = 30

For more number of animals, the food will last less number of days.

∴ It is a case of inverse variation.

Thus, we have

30 * x = 20 * 6
or  NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
Therefore, the food will now last for 4 days.

Question 6. A contractor estimates that 3 persons could rewire jasminder’s house in 4 days. If, he uses 4 persons instead of three, how long should they take to complete the job?

Solution: More is the number of persons, less is the time to complete job.
∴ It is a case of inverse variation.

Number of personsNumber of days to complete the wiring job

3

4

4

x


∴ 3 * 4 = 4 * x
or x = 3 * 4 = 3
∴ The required number of days = 3

Question 7. A batch of bottles were packed in 25 boxes with 12 bottles in each box. If the same batch is packed using 20 bottles in each box, How many boxes would be filled?
NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

Solution: Let the number of boxes required = x
We have:

Number of bottles in a boxNumber of boxes

12
20

25
x


Since, more the number of bottles in a box, lesser will be the number of boxes required to be
filled.

∴ It is a case of inverse variation.
i.e. 
NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
or
Thus, the required number of boxes = 15

Question 8. A factory requires 42 machines to produce a given number of articles in 63 days. How many machines would be required to produce the same number of articles in 54 days?

Solution: Let the number of machines required be x.
We have:

Number of machines

Number of days

42

63

X

54


NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

or
Thus, the required number of machines = 49

Question 9. A car takes 2 hours to reach a destination by travelling at the speed of 60 km/h. How long will it take when the car travels at the speed of 80 km/h?

Solution: More the speed, lesser the number of hours to travel a fixed distance.
∴ It is a case of inverse variations.

Speed (km/h)

Time taken to cover the fixed distance

60

2

80

X

NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
or
Thus the required number of hours =  NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

Question 10. Two persons could fit new window in a house in 3 days.
(i) One of the persons fell ill before the work started. How long would the job take now?
(ii) How many persons would be needed to fit the windows in one day?

Solution: (i) Let the time taken by the remaining persons to complete the job be x.

∵ 2 persons – 1 person = 1 person and lesser the number of person, more will be the number of days to complete the job.
∴ It is a case of inverse proportion.
We have:

Number of persons

Number of (lays

2

3

1

X


NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
or
∴ 1 person will complete the job in 6 days.

(ii) We have

Number of persons

Number of days

2

3

X

1


NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
or
∴ 6 persons will be required to complete the job in 1 day.

Question 11. A school has 8 periods a day each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school houres to be the same?

Solution: For 9 periods, let the duration per period be x minutes.
∴ We have:

Number of periods

Duration of a period (in minutes)

8

9

45

X


For a fixed duration, more the periods, lesser will be the duration of one period.

∴  It is a case of inverse proportion.
i.e. 8 * 45 = 9 * x
NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
Thus, the required duration per period = 40 minutes.

Question 1. Take a sheet of paper. Fold it as shown in the figure. Count the number of parts and the area of a part in each case.
NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2
Tabulate your observations and discuss with your friends. Is it a case inverse proportion? Why?

Number of parts124816
Area of each partarea of the paper1/2 the area of the paper............


Solution:

Number of parts →124816
Area of one part →Area of the1/2 Area of the paper1/4 Area of the paper1/8 Area of the paper1/16 Area of the paper


Here, more the number of parts, lesser is the area of each part.
∴ It is a case of “inverse proportion”.

Question 2. Take a few containers of different sizes with circular bases. Fill the same amount of water in each container. Note the diameter of each container and the respective height at which the water level stands. Tabulate your observations. Is it a case of inverse proportion?
NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

Diameter of container (in cm)

 

 

 

Height of water level (in cm)

 

 

 


Solution:

Diameter of container (in cm)

d1

d2

d3

Height of water level (in cm)

h1

h2

h3


Here, lesser the diameter, more is the level of water in the container.

∴ It is a case of inverse proportion.

The document NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2 is a part of the Class 8 Course Class 8 Mathematics by VP Classes.
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FAQs on NCERT Solutions for Class 8 Maths - Direct and Inverse Proportions - 2

1. What is direct proportion?
Ans. Direct proportion is a relationship between two quantities in which they increase or decrease at the same rate. In other words, if one quantity doubles, the other quantity also doubles. For example, if the time taken to complete a task is directly proportional to the number of workers, then as the number of workers increases, the time taken to complete the task also increases proportionally.
2. What is inverse proportion?
Ans. Inverse proportion is a relationship between two quantities in which an increase in one quantity leads to a decrease in the other quantity, and vice versa. In other words, if one quantity doubles, the other quantity is halved. For example, if the speed of a car is inversely proportional to the time taken to travel a certain distance, then as the speed increases, the time taken to travel the distance decreases proportionally.
3. How can we determine if two quantities are in direct proportion or inverse proportion?
Ans. To determine if two quantities are in direct proportion or inverse proportion, we can use the following method: - If increasing or decreasing one quantity results in a proportional increase or decrease in the other quantity, then they are in direct proportion. - If increasing one quantity results in a proportional decrease in the other quantity, and vice versa, then they are in inverse proportion.
4. Can a quantity be both directly proportional and inversely proportional to another quantity?
Ans. No, a quantity cannot be both directly proportional and inversely proportional to another quantity at the same time. Direct proportion and inverse proportion are mutually exclusive relationships. If two quantities are directly proportional, any change in one quantity will result in a proportional change in the other quantity. However, in inverse proportion, any change in one quantity will lead to an opposite proportional change in the other quantity.
5. How can we solve problems involving direct and inverse proportions?
Ans. To solve problems involving direct and inverse proportions, we can follow these steps: - Identify the quantities involved and determine if they are in direct proportion or inverse proportion. - Formulate the proportionality statement or equation based on the relationship between the quantities. - Use the given information and the proportionality statement to set up a proportion or equation. - Solve the proportion or equation to find the unknown quantity. - Check the solution by substituting it back into the original proportionality statement to ensure it satisfies the given conditions.
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