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NCERT Solutions Exercise 5.5: Continuity & Differentiability

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 Page 1


 
 
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability 
 
Exercise 5.5                                                                Page No: 178 
 
Differentiate the functions with respect to x in Exercise 1 to 5. 
 
1.  
 Solution:  Let  
Taking logs on both sides, we get 
  
=  
Now, 
  
  
  
  
  
  [using value of y] 
2.  
 Solution:  Let   
 
 
 
Page 2


 
 
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability 
 
Exercise 5.5                                                                Page No: 178 
 
Differentiate the functions with respect to x in Exercise 1 to 5. 
 
1.  
 Solution:  Let  
Taking logs on both sides, we get 
  
=  
Now, 
  
  
  
  
  
  [using value of y] 
2.  
 Solution:  Let   
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
= 
Taking logs on both sides, we get 
 [using the value of y] 
3. 
 Solution:  Let 
Taking logs on both sides, we get 
 [By Product rule] 
Page 3


 
 
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability 
 
Exercise 5.5                                                                Page No: 178 
 
Differentiate the functions with respect to x in Exercise 1 to 5. 
 
1.  
 Solution:  Let  
Taking logs on both sides, we get 
  
=  
Now, 
  
  
  
  
  
  [using value of y] 
2.  
 Solution:  Let   
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
= 
Taking logs on both sides, we get 
 [using the value of y] 
3. 
 Solution:  Let 
Taking logs on both sides, we get 
 [By Product rule] 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
4. 
 Solution:  Let 
Put  and 
 ……….(1) 
Now, 
????
????
 =  ……….(2) 
Again, 
Page 4


 
 
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability 
 
Exercise 5.5                                                                Page No: 178 
 
Differentiate the functions with respect to x in Exercise 1 to 5. 
 
1.  
 Solution:  Let  
Taking logs on both sides, we get 
  
=  
Now, 
  
  
  
  
  
  [using value of y] 
2.  
 Solution:  Let   
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
= 
Taking logs on both sides, we get 
 [using the value of y] 
3. 
 Solution:  Let 
Taking logs on both sides, we get 
 [By Product rule] 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
4. 
 Solution:  Let 
Put  and 
 ……….(1) 
Now, 
????
????
 =  ……….(2) 
Again, 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
 ……….(3) 
Put the values from (2) and (3) in (1), 
5. 
 Solution:  Let 
Taking logs on both sides, we get 
Now, 
(using value of y) 
Differentiate the functions with respect to  in Exercise 6 to 11. 
6. 
 Solution:  Let 
Page 5


 
 
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability 
 
Exercise 5.5                                                                Page No: 178 
 
Differentiate the functions with respect to x in Exercise 1 to 5. 
 
1.  
 Solution:  Let  
Taking logs on both sides, we get 
  
=  
Now, 
  
  
  
  
  
  [using value of y] 
2.  
 Solution:  Let   
 
 
 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
= 
Taking logs on both sides, we get 
 [using the value of y] 
3. 
 Solution:  Let 
Taking logs on both sides, we get 
 [By Product rule] 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
4. 
 Solution:  Let 
Put  and 
 ……….(1) 
Now, 
????
????
 =  ……….(2) 
Again, 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
 ……….(3) 
Put the values from (2) and (3) in (1), 
5. 
 Solution:  Let 
Taking logs on both sides, we get 
Now, 
(using value of y) 
Differentiate the functions with respect to  in Exercise 6 to 11. 
6. 
 Solution:  Let 
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and 
Differentiability
Put  and 
 ……….(1) 
Now 
=  ……….(2) 
Again 
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