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NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Exercise 2.2

Fractions and Decimals Fractions and Decimals 

Q1. Find: 
(i) 1/4 of 
(a) 1/4 
(b) 3/5 
(c) 4/3
(ii) 1/7 of 

(a) 2/9 
(b) 6/5 
(c) 3/10

Ans: 
By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
(i)
 (a) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(b)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(c)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(ii)
 (a)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(b)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(c)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q2: Multiply and reduce to lowest form (if possible): 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vi)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans:
(i) First, convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 8/3,

By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(ii) By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iii) By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iv) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(v) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vi) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vii) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Multiplying FractionMultiplying FractionQ3. Multiply the following fractions: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans: 
(i) First convert the given mixed fraction into improper fraction.
= 5 ¼ = 21/4
Now,
= (2/5) × (21/4)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


(ii) First, convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 32/5Now,= (32/5) × (7/9)

By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then, 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iii) First, convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 16/3
Now,
= (3/2) × (16/3)
By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv) First convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 17/7
Now,
= (5/6) × (17/7)
By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(v) First convert the given mixed fraction into improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 17/5
Now,
= (17/5) × (4/7)

By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vi) First convert the given mixed fraction into improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 13/5
Now,
= (13/5) × (3/1)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vii) First convert the given mixed fraction into improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 25/7
Now,
= (25/7) × (3/5)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,  
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q4. Which is greater: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
⇒  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
⇒   NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
⇒   NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q5. Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is 3/4 m. Find the distance between the first and the last sapling.

Ans: The distance between two adjacent saplings = 3/4 m
Saili planted 4 saplings in a row, then number of gap in saplings = 3
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
Therefore,
The distance between the first and the last saplings  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
Thus the distance between the first and the last saplings is NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q6. Lipika reads a book forNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)hours every day. She reads the entire book in 6 days. How many hours in ail were required by her to read the book?

Ans: Time is taken by Lipika to read a book = NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)hours
She reads the entire book in 6 days.
Now, the total hours are taken by her to read the entire book  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
Thus, 10 hours were required by her to read the book.  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q7. A car runs 16 km using 1 litre of petrol. How much distance will it cover using  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)of petrol?

Ans: In 1 litre of petrol, car covers the distance = 16 km
In NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)litres of petrol, car covers the distance =  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
Thus, the car will cover 44 km distance.


Q8. 
(a) 
(i) Provide the number in the box 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) The simplest form of the number obtained in NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(b)
 (i) Provide the number in the box
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) The simplest form of the number obtained in NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans:
 (a)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) The simplest form NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(b)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) The simplest form NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Exercise 2.3 

Q1.
Find: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans: 
(i) We have,
= 12 × reciprocal of ¾

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(ii) We have,
= 14 × reciprocal of (5/6)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iii) We have,
= 8× reciprocal of (7/3)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iv) We have,
= 4 × reciprocal of (8/3)

 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(v) While dividing a whole number by a mixed fraction, first convert the mixed fraction into improper fraction We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 7/3
Then,
= 3 ÷ (7/3)
= 3 × reciprocal of (7/3)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vi) While dividing a whole number by a mixed fraction, first convert the mixed fraction into improper fraction We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 25/7
Then,
= 5 ÷ (25/7)
= 5 × reciprocal of (25/7)   
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.

(i) 3/7
Ans: Reciprocal of (3/7) is (7/3) [∵ ((3/7) × (7/3)) = 1]
So, it is an improper fraction.
Improper fraction is that fraction in which numerator is greater than its denominator.
(ii) 5/8
Ans: Reciprocal of (5/8) is (8/5) [∵ ((5/8) × (8/5)) = 1]
So, it is an improper fraction.
Improper fraction is that fraction in which numerator is greater than its denominator.
(iii) 9/7
Ans: Reciprocal of (9/7) is (7/9) [∵ ((9/7) × (7/9)) = 1]
So, it is a proper fraction.
A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.
(iv) 6/5
Ans: Reciprocal of (6/5) is (5/6) [∵ ((6/5) × (5/6)) = 1]
So, it is a proper fraction.
A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.
(v) 12/7
Ans: Reciprocal of (12/7) is (7/12) [∵ ((12/7) × (7/12)) = 1]
So, it is a proper fraction.
A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.
(vi) 1/8
Ans: Reciprocal of (1/8) is (8/1) or 8 [∵ ((1/8) × (8/1)) = 1]
So, it is a whole number.
Whole numbers are collection of all positive integers including 0.
(vii) 1/11
Ans: Reciprocal of (1/11) is (11/1) or 11 [∵ ((1/11) × (11/1)) = 1]
So, it is a whole number.
Whole numbers are collection of all positive integers including 0.


Q3. Find: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vi)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans: 
(i) We have,
= (7/3) × reciprocal of 2
= (7/3) × (1/2)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) We have,
= (4/9) × reciprocal of 5
= (4/9) × (1/5)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iii) We have,
= (6/13) × reciprocal of 7
= (6/13) × (1/7)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iv) First convert the mixed fraction into improper fraction. We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 13/3 Then,
= (13/3) × reciprocal of 3

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(v) First convert the mixed fraction into improper fraction.
We have,
= 3 ½ = 7/2
Then,
= (7/2) × reciprocal of 4

 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vi) First convert the mixed fraction into improper fraction.
We have,

=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 31/7
Then,
= (31/7) × reciprocal of 7

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q4.  Find 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

(viii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Ans: 
(i) We have,
= (2/5) × reciprocal of ½
= (2/5) × (2/1)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) We have,
= (4/9) × reciprocal of (2/3)
= (4/9) × (3/2)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii) We have,
= (3/7) × reciprocal of (8/7)
= (3/7) × (7/8)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv) First convert the mixed fraction into improper fraction.
We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 7/3
Then,
= (7/3) × reciprocal of (3/5)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v) First convert the mixed fraction into improper fraction.
We have,
= 3 ½ = 7/2
Then,
= (7/2) × reciprocal of (8/3)
= (7/2) × (3/8)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vi) First convert the mixed fraction into improper fraction.
We have,
= 1 ½ = 3/2
Then,
= (2/5) × reciprocal of (3/2)

= (2/5) × (2/3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(vii) First convert the mixed fraction into improper fraction.
We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 16/5

=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 5/3Then,= (16/5) × reciprocal of (5/3)= (16/5) × (3/5)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(viii) First convert the mixed fraction into improper fraction.
We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 11/5

=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 6/5
Then,
= (11/5) × reciprocal of (6/5)
= (11/5) × (5/6)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Deleted Exercise 

Q1: Which is greater: 
(i) 0.5 or 0.05 
(ii) 0.7or 0.5 
(iii) 7 or 0.7
(iv) 1.37 or 1.49 
(v)  3.03 or 2.30 
(vi) 0.8 or 0.88
Ans: 
(i)  0.5 > 0.05    
(ii)  0.7 > 0.5
(iii) 7 >0.7
(iv) 1.37 <1.49
(v)  2.03 < 2.30
(vi) 0.8 <0.88

Q2: Express as rupees using decimals: 
(i) 7 paise 
(ii) 7 rupees 7 paise 
(iii) 77 rupees 77 paise 
(iv) 50 paise 
(v) 235 paise 
Ans: We know that,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q3:
 (i) Express 5 cm in metre and kilometre. 
(ii) Express 35 mm in cm, m and km. 
Ans: 
(i) Express 5 cm in meter and kilometer.
We know that, 100 cm = 1 meter
∴ 1 cm = 1/100 meter
⇒ 5 cm = 5/100 = 0.05 meter
Now,
∴ 1000 meters = 1 kilometers
∴ 1 meters = 1/1000 kilometer
⇒ 0.05 meter = 0.05/1000 = 0.00005 kilometer
(ii) Express 35 mm in cm, m and km.
∵ 10 mm = 1 cm
∴ 1 mm  = 1/10 cm
⇒ 35 mm = 35/100 = 3.5 cm
Now, ∵ 100 cm = 1 meter
∴ 1 cm = 1/100 meter
⇒ 3.5 cm  = 3.5/100 = 0.035 meter
Again,
∵ 1000 meters = 1 kilometers
∴ 1 meter = 1/1000 kilometers
⇒ 0.035 meter = 0.035/1000 = 0.000035 kilometer

Q4:  Express in kg. 
(i) 200 g 
(ii) 3470 g 
(iii) 4 kg 8 g 
Ans: 
Let us consider, 1000 g = 1 kg

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii)  4kg 8 g = NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)= 5 kg + 0.008 kg = 4.005 kg

Q5: Write the following decimal numbers in the expanded form: 
(i) 20.03 
(ii) 2.03 
(iii) 200.03 
(iv) 2.034 
Ans: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)


Q6: Write the place value of 2 in the following decimal numbers: 
(i) 2.56 
(ii) 21.37 
(iii) 10.25 
(iv) 9.42
(v) 63.352
Ans: 
(i) Place value of 2 in 2.56 = 2 x 1 = 2 ones
(ii)  Place value of 2 in 21.37 = 2 x 10 = 2 tens
(iii) Place value of 2 in 10.25 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(iv) Place value of 2 in 9.42 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
(v) Place value of 2 in 63.352 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Q7: Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much? 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)
Ans: 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

Distance travelled by Dinesh when he went from place A to place B = 7.5 km and from place B to C = 12.7 km.
Total distance covered by Dinesh = AB + BC
= 7.5 + 12.7
= 20.2 km
Total distance covered by Ayub = AD + DC
= 9.3 + 11.8
= 21.1 km
On comparing the total distance of Ayub and Dinesh,
21.1 km > 20.2 km
Therefore, Ayub covered more distance by 21.1 – 20.2 = 0.9 km = 900 m
∴Ayub travelled 0.9 km more than Dinesh. 

Q8: Shyam bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits? 
Ans: From the question, it is given that, Fruits bought by Shyama = 5 kg 300 g

= 5 kg + (300/1000) kg
= 5 kg + 0.3 kg
= 5.3 kg
Fruits bought by Sarala = 4 kg 800 g + 4 kg 150 g
= (4 + (800/1000)) + (4 + (150/1000))
= (4 + 0.8) kg + (4 + .150) kg
= 4.8 kg + 4.150kg
= 8.950 kg
So, Sarala bought more fruits.

Q9: How much less is 28 km than 42.6 km? 
Ans: 
We have to find the difference between 42.6 km and 28 km.
Difference = 42.6 – 28.0 = 14.6 km
Therefore,14.6 km less is 28 km than 42.6 km.

The document NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3) is a part of the Class 7 Course NCERT Textbooks & Solutions for Class 7.
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FAQs on NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.2 and 2.3)

1. What are fractions and decimals?
Ans. Fractions and decimals are types of numbers used to represent parts of a whole or a quantity. Fractions represent a part of a whole by dividing it into equal parts, whereas decimals represent a part of a whole in the form of a decimal point followed by digits.
2. What is the difference between a fraction and a decimal?
Ans. The main difference between a fraction and a decimal is the way they are expressed. Fractions are expressed in the form of a numerator and a denominator, whereas decimals are expressed in the form of a decimal point followed by digits. Fractions represent a part of a whole by dividing it into equal parts, whereas decimals represent a part of a whole in the form of a decimal point followed by digits.
3. How are fractions and decimals related?
Ans. Fractions and decimals are related because they both represent parts of a whole or a quantity. A fraction can be converted into a decimal by dividing the numerator by the denominator, whereas a decimal can be converted into a fraction by writing the digits after the decimal point as the numerator and the appropriate power of 10 as the denominator.
4. How can fractions and decimals be used in everyday life?
Ans. Fractions and decimals are used in everyday life in many ways. For example, when cooking or baking, recipes often require measurements in fractions or decimals. In finance, decimals are used to represent currency values and fractions are used to calculate interest rates. Fractions are also used in construction and engineering to measure angles and distances.
5. What are some common operations performed with fractions and decimals?
Ans. Common operations performed with fractions and decimals include addition, subtraction, multiplication, and division. When performing these operations, it is important to ensure that the fractions have a common denominator or that the decimals have the same number of digits after the decimal point. It is also important to simplify the fraction or round the decimal to the appropriate number of digits.
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