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NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

Exercise 14.1
Question 1: Draw a circle of radius 3.2 cm.
Answer 1:
Steps of construction:
(a) Open the compass for the required radius of 3.2 cm.
(b) Make a point with a sharp pencil where we want the centre of circle to be.
(c) Name it O.
(d) Place the pointer of compasses on O.
(e) Turn the compasses slowly to draw the circle.

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

Hence, it is the required circle.

Question 2: With the same centre O, draw two circles of radii 4 cm and 2.5 cm.
Answer 2:
Steps of construction:
(a) Marks a point ‘O’ with a sharp pencil where we want the centre of the circle.
(b) Open the compasses 4 cm.
(c) Place the pointer of the compasses on O.
(d) Turn the compasses slowly to draw the circle.
(e) Again open the compasses 2.5 cm and place the pointer of the compasses on D.
(f) Turn the compasses slowly to draw the second circle.

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

Hence, it is the required figure.


Question 3: Draw a circle and any two of its diameters. If you join the ends of these diameters, what is the figure obtained? What figure is obtained if the diameters are perpendicular to each other? How do you check your answer?
Answer 3:
(i) By joining the ends of two diameters, we get a rectangle. By measuring, we find AB = CD = 3 cm, BC = AD = 2 cm i.e., pairs of opposite sides are equal and also ∠A = ∠B = ∠C = ∠D = 90o  i.e., each angle is of 90o.
Hence, it is a rectangle.

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

(ii) If the diameters are perpendicular to each other, then by joining the ends of two diameters, we get a square. By measuring, we find that AB = BC = CD = DA = 2.5 cm, i.e., all four sides are equal. Also ∠A = ∠B = ∠C = ∠D = 90o, i.e., each angle is of 90o.
Hence, it is a square.

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry


Question 4: Draw any circle and mark points A, B and C such that:
(a) A is on the circle.
(b) B is in the interior of the circle.
(c) C is in the exterior of the circle.
Answer 4:
(i) Mark a point ‘O’ with sharp pencil where we want centre of the circle.
(ii) Place the pointer of the compasses at ‘O’. Then move the compasses slowly to draw a circle.
(a) Point A is on the circle.
(b) Point B is in interior of the circle.
(c) Point C is in the exterior of the circle.

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry


Question 5: Let A, B be the centres of two circles of equal radii; draw them so that each one of them passes through the centre of the other. Let them intersect at C and D.
Examine whether NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometryare at right angles.
Answer 5: 
Draw two circles of equal radii taking A and B as their centre such that one of them passes through the centre of the other. They intersect at C and D. Join AB and CD.
Yes, AB and CD intersect at right angle as ∠COB is 90o .

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry


Exercise 14.2
Question 1: Draw a line segment of length 7.3 cm, using a ruler.
Answer 1:
Steps of construction:

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

(i) Place the zero mark of the ruler at a point A.
(ii) Mark a point B at a distance of 7.3 cm from A.
(iii) Join AB.
Hence, NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is the required line segment of length 7.3 cm.

Question 2: Construct a line segment of length 5.6 cm using ruler and compasses.
Answer 2: Steps of construction:

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

(i) Draw a line 'l'. l Mark a point A on this line.
(ii) Place the compasses pointer on zero mark of the ruler. Open it to place the pencil point up to 5.6 cm mark.
(iii) Without changing the opening of the compasses. Place the pointer on A and cut an arc 'l'  at B.NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is the required line segment of length 5.6 cm.


Question 3:
Construct NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry of length 7.8 cm. From this, cut off  NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometryof length 4.7 cm. Measure NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry
Answer:
Steps of construction:

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry(i) Place the zero mark of the ruler at A.
(ii) Mark a point B at a distance 7.8 cm from A.
(iii) Again, mark a point C at a distance 4.7 from A.
Hence, by measuring  NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry, we find that BC = 3.1 cm.

Question 4: Given NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry of length 3.9 cm, construct NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is twice that of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry. Verify by measurement.

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry(Hint: construct NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry ; then cut off NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry also has the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry.)
Answer 4:
Steps of construction:
NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

(i) Draw a line 'l'.
(ii) Construct NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry
(iii) Then cut of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry also has the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry.
(iv) Thus the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry and the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry added together make twice the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry
Verification: Hence, by measurement we find that PQ = 7.8 cm
= 3.9 cm + 3.9 cm
NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

Question 5: Given NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry of length 7.3 cm and NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry of length 3.4 cm, construct a line segment NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is equal to the difference between the lengths of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry Verify by measurement.
Answer 5:
Steps of construction:
(i) Draw a line 'l' and take a point X on it.
(ii) Construct NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that length NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = 7.3 cm
(iii) Then cut off NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = 3.4 cm
(iv) Thus the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry = length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry – length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

Verification:
Hence, by measurement we find that length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry
= 3.9 cm
= 73. cm – 3.4 cm
= NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry - NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

Exercise 14.3
Question 1:
Draw any line segment NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry. Without measuring NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry, construct a copy of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry.
Answer 1:
Steps of construction:

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

(i) Given NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry  whose length is not known.
(ii) Fix the compasses pointer on P and the pencil end on Q. The opening of the instrument now gives the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry .
(iii) Draw any line 'l'. Choose a point A on 'l'. Without changing the compasses setting, place the pointer on A.
(iv) Draw an arc that cuts 'l' at a point, say B.
Hence, NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry  is the copy of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry .

Question 2:
Given some line segment NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry , whose length you do not know, construct NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry such that the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is twice that of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry.
Answer 2:
Steps of construction:

NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

(i) Given NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry whose length is not known.
(ii) Fix the compasses pointer on A and the pencil end on B. The opening of the instrument now gives the length of NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry.
(iii) Draw any line 'l'. Choose a point P on 'l'. Without changing the compasses setting, place the pointer on Q.
(iv) Draw an arc that cuts 'l' at a point R.
(v) Now place the pointer on R and without changing the compasses setting, draw another arc that cuts 'l' at a point Q.
Hence, NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is the required line segment whose length is twice that of AB.

The document NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry is a part of the Class 6 Course Mathematics (Maths) Class 6.
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FAQs on NCERT Solutions for Class 8 Maths chapter 14 - (Ex: 14.1 to 14.3): Practical Geometry

1. What is practical geometry?
Ans. Practical geometry is the branch of geometry that deals with the construction of geometrical figures and solving problems related to them using the ruler, compass, and other geometrical tools.
2. What are some essential tools required for practical geometry?
Ans. Some essential tools required for practical geometry are a compass, a ruler, a protractor, a set square, a divider, a pencil, and an eraser.
3. What is the difference between a ruler and a compass?
Ans. A ruler is a tool used for measuring lengths and drawing straight lines, whereas a compass is a tool used for drawing circles and arcs.
4. What are some common constructions in practical geometry?
Ans. Some common constructions in practical geometry are bisecting a line segment, constructing perpendiculars, constructing angles, and constructing triangles.
5. How is practical geometry useful in real-life situations?
Ans. Practical geometry is useful in various real-life situations, such as designing buildings, constructing roads, and creating maps. It is also used in the field of engineering, architecture, and design to create accurate and precise drawings.
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