Page 1 Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way that each row has the same number of marbles. He arranges them in the following ways and matches the total number of marbles. (i) 1 marble in each row Number of rows = 6 Total number of marbles = 1 × 6 = 6 (ii) 2 marbles in each row Number of rows = 3 Total number of marbles = 2 × 3 = 6 (iii) 3 marbles in each row Number of rows = 2 Total number of marbles = 3 × 2 = 6 (iv) He could not think of any arrangement in which each row had 4 marbles or 5 marbles. So, the only possible arrangement left was with all the 6 marbles in a row. Number of rows = 1 Total number of marbles = 6 × 1 = 6 From these calculations Ramesh observes that 6 can be written as a product of two numbers in different ways as 6 = 1 × 6; 6 = 2 × 3; 6 = 3 × 2; 6 = 6 × 1 3.1 Introduction Chapter 3 P P Pl l la a ay y yi i in n ng g g w w wi i it t th h h N N Nu u um m mb b be e er r rs s s Page 2 Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way that each row has the same number of marbles. He arranges them in the following ways and matches the total number of marbles. (i) 1 marble in each row Number of rows = 6 Total number of marbles = 1 × 6 = 6 (ii) 2 marbles in each row Number of rows = 3 Total number of marbles = 2 × 3 = 6 (iii) 3 marbles in each row Number of rows = 2 Total number of marbles = 3 × 2 = 6 (iv) He could not think of any arrangement in which each row had 4 marbles or 5 marbles. So, the only possible arrangement left was with all the 6 marbles in a row. Number of rows = 1 Total number of marbles = 6 × 1 = 6 From these calculations Ramesh observes that 6 can be written as a product of two numbers in different ways as 6 = 1 × 6; 6 = 2 × 3; 6 = 3 × 2; 6 = 6 × 1 3.1 Introduction Chapter 3 P P Pl l la a ay y yi i in n ng g g w w wi i it t th h h N N Nu u um m mb b be e er r rs s s PLAYING WITH NUMBERS 47 From 6 = 2 × 3 it can be said that 2 and 3 exactly divide 6. So, 2 and 3 are exact divisors of 6. From the other product 6 = 1 × 6, the exact divisors of 6 are found to be 1 and 6. Thus, 1, 2, 3 and 6 are exact divisors of 6. They are called the factors of 6. Try arranging 18 marbles in rows and find the factors of 18. 3.2 Factors and Multiples Mary wants to find those numbers which exactly divide 4. She divides 4 by numbers less than 4 this way. 1) 4 (4 2) 4 (2 3) 4 (1 4) 4 (1 â€“ 4 â€“ 4 â€“ 3 â€“ 4 0 0 1 0 Quotient is 4 Quotient is 2 Quotient is 1 Quotient is 1 Remainder is 0 Remainder is 0 Remainder is 1 Remainder is 0 4 = 1 × 4 4 = 2 × 2 4 = 4 × 1 She finds that the number 4 can be written as: 4 = 1 × 4; 4 = 2 × 2; 4 = 4 × 1 and knows that the numbers 1, 2 and 4 are exact divisors of 4. These numbers are called factors of 4. A factor of a number is an exact divisor of that number. Observe each of the factors of 4 is less than or equal to 4. Game-1 : This is a game to be played by two persons say A and B. It is about spotting factors. It requires 50 pieces of cards numbered 1 to 50. Arrange the cards on the table like this. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 Page 3 Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way that each row has the same number of marbles. He arranges them in the following ways and matches the total number of marbles. (i) 1 marble in each row Number of rows = 6 Total number of marbles = 1 × 6 = 6 (ii) 2 marbles in each row Number of rows = 3 Total number of marbles = 2 × 3 = 6 (iii) 3 marbles in each row Number of rows = 2 Total number of marbles = 3 × 2 = 6 (iv) He could not think of any arrangement in which each row had 4 marbles or 5 marbles. So, the only possible arrangement left was with all the 6 marbles in a row. Number of rows = 1 Total number of marbles = 6 × 1 = 6 From these calculations Ramesh observes that 6 can be written as a product of two numbers in different ways as 6 = 1 × 6; 6 = 2 × 3; 6 = 3 × 2; 6 = 6 × 1 3.1 Introduction Chapter 3 P P Pl l la a ay y yi i in n ng g g w w wi i it t th h h N N Nu u um m mb b be e er r rs s s PLAYING WITH NUMBERS 47 From 6 = 2 × 3 it can be said that 2 and 3 exactly divide 6. So, 2 and 3 are exact divisors of 6. From the other product 6 = 1 × 6, the exact divisors of 6 are found to be 1 and 6. Thus, 1, 2, 3 and 6 are exact divisors of 6. They are called the factors of 6. Try arranging 18 marbles in rows and find the factors of 18. 3.2 Factors and Multiples Mary wants to find those numbers which exactly divide 4. She divides 4 by numbers less than 4 this way. 1) 4 (4 2) 4 (2 3) 4 (1 4) 4 (1 â€“ 4 â€“ 4 â€“ 3 â€“ 4 0 0 1 0 Quotient is 4 Quotient is 2 Quotient is 1 Quotient is 1 Remainder is 0 Remainder is 0 Remainder is 1 Remainder is 0 4 = 1 × 4 4 = 2 × 2 4 = 4 × 1 She finds that the number 4 can be written as: 4 = 1 × 4; 4 = 2 × 2; 4 = 4 × 1 and knows that the numbers 1, 2 and 4 are exact divisors of 4. These numbers are called factors of 4. A factor of a number is an exact divisor of that number. Observe each of the factors of 4 is less than or equal to 4. Game-1 : This is a game to be played by two persons say A and B. It is about spotting factors. It requires 50 pieces of cards numbered 1 to 50. Arrange the cards on the table like this. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 MATHEMATICS 48 Steps (a) Decide who plays first, A or B. (b) Let A play first. He picks up a card from the table, and keeps it with him. Suppose the card has number 28 on it. (c) Player B then picks up all those cards having numbers which are factors of the number on Aâ€™s card (i.e. 28), and puts them in a pile near him. (d) Player B then picks up a card from the table and keeps it with him. From the cards that are left, A picks up all those cards whose numbers are factors of the number on Bâ€™s card. A puts them on the previous card that he collected. (e) The game continues like this until all the cards are used up. (f) A will add up the numbers on the cards that he has collected. B too will do the same with his cards. The player with greater sum will be the winner. The game can be made more interesting by increasing the number of cards. Play this game with your friend. Can you find some way to win the game? When we write a number 20 as 20 = 4 × 5, we say 4 and 5 are factors of 20. We also say that 20 is a multiple of 4 and 5. The representation 24 = 2 × 12 shows that 2 and 12 are factors of 24, whereas 24 is a multiple of 2 and 12. We can say that a number is a multiple of each of its factors Let us now see some interesting facts about factors and multiples. (a) Collect a number of wooden/paper strips of length 3 units each. (b) Join them end to end as shown in the following figure. The length of the strip at the top is 3 = 1 × 3 units. The length of the strip below it is 3 + 3 = 6 units. Also, 6 = 2 × 3. The length of the next strip is 3 + 3 + 3 = 9 units, and 9 = 3 × 3. Continuing this way we can express the other lengths as, 12 = 4 × 3 ; 15 = 5 × 3 We say that the numbers 3, 6, 9, 12, 15 are multiples of 3. The list of multiples of 3 can be continued as 18, 21, 24, ... Each of these multiples is greater than or equal to 3. The multiples of the number 4 are 4, 8, 12, 16, 20, 24, ... The list is endless. Each of these numbers is greater than or equal to 4. multiple ? 4 × 5 = 20 ? ? factor factor Find the possible factors of 45, 30 and 36. 3 3 3 3 6 3 3 3 9 3 3 3 3 12 3 3 3 3 3 15 Page 4 Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way that each row has the same number of marbles. He arranges them in the following ways and matches the total number of marbles. (i) 1 marble in each row Number of rows = 6 Total number of marbles = 1 × 6 = 6 (ii) 2 marbles in each row Number of rows = 3 Total number of marbles = 2 × 3 = 6 (iii) 3 marbles in each row Number of rows = 2 Total number of marbles = 3 × 2 = 6 (iv) He could not think of any arrangement in which each row had 4 marbles or 5 marbles. So, the only possible arrangement left was with all the 6 marbles in a row. Number of rows = 1 Total number of marbles = 6 × 1 = 6 From these calculations Ramesh observes that 6 can be written as a product of two numbers in different ways as 6 = 1 × 6; 6 = 2 × 3; 6 = 3 × 2; 6 = 6 × 1 3.1 Introduction Chapter 3 P P Pl l la a ay y yi i in n ng g g w w wi i it t th h h N N Nu u um m mb b be e er r rs s s PLAYING WITH NUMBERS 47 From 6 = 2 × 3 it can be said that 2 and 3 exactly divide 6. So, 2 and 3 are exact divisors of 6. From the other product 6 = 1 × 6, the exact divisors of 6 are found to be 1 and 6. Thus, 1, 2, 3 and 6 are exact divisors of 6. They are called the factors of 6. Try arranging 18 marbles in rows and find the factors of 18. 3.2 Factors and Multiples Mary wants to find those numbers which exactly divide 4. She divides 4 by numbers less than 4 this way. 1) 4 (4 2) 4 (2 3) 4 (1 4) 4 (1 â€“ 4 â€“ 4 â€“ 3 â€“ 4 0 0 1 0 Quotient is 4 Quotient is 2 Quotient is 1 Quotient is 1 Remainder is 0 Remainder is 0 Remainder is 1 Remainder is 0 4 = 1 × 4 4 = 2 × 2 4 = 4 × 1 She finds that the number 4 can be written as: 4 = 1 × 4; 4 = 2 × 2; 4 = 4 × 1 and knows that the numbers 1, 2 and 4 are exact divisors of 4. These numbers are called factors of 4. A factor of a number is an exact divisor of that number. Observe each of the factors of 4 is less than or equal to 4. Game-1 : This is a game to be played by two persons say A and B. It is about spotting factors. It requires 50 pieces of cards numbered 1 to 50. Arrange the cards on the table like this. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 MATHEMATICS 48 Steps (a) Decide who plays first, A or B. (b) Let A play first. He picks up a card from the table, and keeps it with him. Suppose the card has number 28 on it. (c) Player B then picks up all those cards having numbers which are factors of the number on Aâ€™s card (i.e. 28), and puts them in a pile near him. (d) Player B then picks up a card from the table and keeps it with him. From the cards that are left, A picks up all those cards whose numbers are factors of the number on Bâ€™s card. A puts them on the previous card that he collected. (e) The game continues like this until all the cards are used up. (f) A will add up the numbers on the cards that he has collected. B too will do the same with his cards. The player with greater sum will be the winner. The game can be made more interesting by increasing the number of cards. Play this game with your friend. Can you find some way to win the game? When we write a number 20 as 20 = 4 × 5, we say 4 and 5 are factors of 20. We also say that 20 is a multiple of 4 and 5. The representation 24 = 2 × 12 shows that 2 and 12 are factors of 24, whereas 24 is a multiple of 2 and 12. We can say that a number is a multiple of each of its factors Let us now see some interesting facts about factors and multiples. (a) Collect a number of wooden/paper strips of length 3 units each. (b) Join them end to end as shown in the following figure. The length of the strip at the top is 3 = 1 × 3 units. The length of the strip below it is 3 + 3 = 6 units. Also, 6 = 2 × 3. The length of the next strip is 3 + 3 + 3 = 9 units, and 9 = 3 × 3. Continuing this way we can express the other lengths as, 12 = 4 × 3 ; 15 = 5 × 3 We say that the numbers 3, 6, 9, 12, 15 are multiples of 3. The list of multiples of 3 can be continued as 18, 21, 24, ... Each of these multiples is greater than or equal to 3. The multiples of the number 4 are 4, 8, 12, 16, 20, 24, ... The list is endless. Each of these numbers is greater than or equal to 4. multiple ? 4 × 5 = 20 ? ? factor factor Find the possible factors of 45, 30 and 36. 3 3 3 3 6 3 3 3 9 3 3 3 3 12 3 3 3 3 3 15 PLAYING WITH NUMBERS 49 Let us see what we conclude about factors and multiples: 1. Is there any number which occurs as a factor of every number ? Yes. It is 1. For example 6 = 1 × 6, 18 = 1 × 18 and so on. Check it for a few more numbers. We say 1 is a factor of every number. 2. Can 7 be a factor of itself ? Yes. You can write 7 as 7 = 7 × 1. What about 10? and 15?. You will find that every number can be expressed in this way. We say that every number is a factor of itself. 3. What are the factors of 16? They are 1, 2, 4, 8, 16. Out of these factors do you find any factor which does not divide 16? Try it for 20; 36. You will find that every factor of a number is an exact divisor of that number. 4. What are the factors of 34? They are 1, 2, 17 and 34 itself. Out of these which is the greatest factor? It is 34 itself. The other factors 1, 2 and 17 are less than 34. Try to check this for 64, 81 and 56. We say that every factor is less than or equal to the given number. 5. The number 76 has 5 factors. How many factors does 136 or 96 have? You will find that you are able to count the number of factors of each of these. Even if the numbers are as large as 10576, 25642 etc. or larger, you can still count the number of factors of such numbers, (though you may find it difficult to factorise such numbers). We say that number of factors of a given number are finite. 6. What are the multiples of 7? Obviously, 7, 14, 21, 28,... You will find that each of these multiples is greater than or equal to 7. Will it happen with each number? Check this for the multiples of 6, 9 and 10. We find that every multiple of a number is greater than or equal to that number. 7. Write the multiples of 5. They are 5, 10, 15, 20, ... Do you think this list will end anywhere? No! The list is endless. Try it with multiples of 6,7 etc. We find that the number of multiples of a given number is infinite. 8. Can 7 be a multiple of itself ? Yes, because 7 = 7×1. Will it be true for other numbers also? Try it with 3, 12 and 16. You will find that every number is a multiple of itself. Page 5 Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way that each row has the same number of marbles. He arranges them in the following ways and matches the total number of marbles. (i) 1 marble in each row Number of rows = 6 Total number of marbles = 1 × 6 = 6 (ii) 2 marbles in each row Number of rows = 3 Total number of marbles = 2 × 3 = 6 (iii) 3 marbles in each row Number of rows = 2 Total number of marbles = 3 × 2 = 6 (iv) He could not think of any arrangement in which each row had 4 marbles or 5 marbles. So, the only possible arrangement left was with all the 6 marbles in a row. Number of rows = 1 Total number of marbles = 6 × 1 = 6 From these calculations Ramesh observes that 6 can be written as a product of two numbers in different ways as 6 = 1 × 6; 6 = 2 × 3; 6 = 3 × 2; 6 = 6 × 1 3.1 Introduction Chapter 3 P P Pl l la a ay y yi i in n ng g g w w wi i it t th h h N N Nu u um m mb b be e er r rs s s PLAYING WITH NUMBERS 47 From 6 = 2 × 3 it can be said that 2 and 3 exactly divide 6. So, 2 and 3 are exact divisors of 6. From the other product 6 = 1 × 6, the exact divisors of 6 are found to be 1 and 6. Thus, 1, 2, 3 and 6 are exact divisors of 6. They are called the factors of 6. Try arranging 18 marbles in rows and find the factors of 18. 3.2 Factors and Multiples Mary wants to find those numbers which exactly divide 4. She divides 4 by numbers less than 4 this way. 1) 4 (4 2) 4 (2 3) 4 (1 4) 4 (1 â€“ 4 â€“ 4 â€“ 3 â€“ 4 0 0 1 0 Quotient is 4 Quotient is 2 Quotient is 1 Quotient is 1 Remainder is 0 Remainder is 0 Remainder is 1 Remainder is 0 4 = 1 × 4 4 = 2 × 2 4 = 4 × 1 She finds that the number 4 can be written as: 4 = 1 × 4; 4 = 2 × 2; 4 = 4 × 1 and knows that the numbers 1, 2 and 4 are exact divisors of 4. These numbers are called factors of 4. A factor of a number is an exact divisor of that number. Observe each of the factors of 4 is less than or equal to 4. Game-1 : This is a game to be played by two persons say A and B. It is about spotting factors. It requires 50 pieces of cards numbered 1 to 50. Arrange the cards on the table like this. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 MATHEMATICS 48 Steps (a) Decide who plays first, A or B. (b) Let A play first. He picks up a card from the table, and keeps it with him. Suppose the card has number 28 on it. (c) Player B then picks up all those cards having numbers which are factors of the number on Aâ€™s card (i.e. 28), and puts them in a pile near him. (d) Player B then picks up a card from the table and keeps it with him. From the cards that are left, A picks up all those cards whose numbers are factors of the number on Bâ€™s card. A puts them on the previous card that he collected. (e) The game continues like this until all the cards are used up. (f) A will add up the numbers on the cards that he has collected. B too will do the same with his cards. The player with greater sum will be the winner. The game can be made more interesting by increasing the number of cards. Play this game with your friend. Can you find some way to win the game? When we write a number 20 as 20 = 4 × 5, we say 4 and 5 are factors of 20. We also say that 20 is a multiple of 4 and 5. The representation 24 = 2 × 12 shows that 2 and 12 are factors of 24, whereas 24 is a multiple of 2 and 12. We can say that a number is a multiple of each of its factors Let us now see some interesting facts about factors and multiples. (a) Collect a number of wooden/paper strips of length 3 units each. (b) Join them end to end as shown in the following figure. The length of the strip at the top is 3 = 1 × 3 units. The length of the strip below it is 3 + 3 = 6 units. Also, 6 = 2 × 3. The length of the next strip is 3 + 3 + 3 = 9 units, and 9 = 3 × 3. Continuing this way we can express the other lengths as, 12 = 4 × 3 ; 15 = 5 × 3 We say that the numbers 3, 6, 9, 12, 15 are multiples of 3. The list of multiples of 3 can be continued as 18, 21, 24, ... Each of these multiples is greater than or equal to 3. The multiples of the number 4 are 4, 8, 12, 16, 20, 24, ... The list is endless. Each of these numbers is greater than or equal to 4. multiple ? 4 × 5 = 20 ? ? factor factor Find the possible factors of 45, 30 and 36. 3 3 3 3 6 3 3 3 9 3 3 3 3 12 3 3 3 3 3 15 PLAYING WITH NUMBERS 49 Let us see what we conclude about factors and multiples: 1. Is there any number which occurs as a factor of every number ? Yes. It is 1. For example 6 = 1 × 6, 18 = 1 × 18 and so on. Check it for a few more numbers. We say 1 is a factor of every number. 2. Can 7 be a factor of itself ? Yes. You can write 7 as 7 = 7 × 1. What about 10? and 15?. You will find that every number can be expressed in this way. We say that every number is a factor of itself. 3. What are the factors of 16? They are 1, 2, 4, 8, 16. Out of these factors do you find any factor which does not divide 16? Try it for 20; 36. You will find that every factor of a number is an exact divisor of that number. 4. What are the factors of 34? They are 1, 2, 17 and 34 itself. Out of these which is the greatest factor? It is 34 itself. The other factors 1, 2 and 17 are less than 34. Try to check this for 64, 81 and 56. We say that every factor is less than or equal to the given number. 5. The number 76 has 5 factors. How many factors does 136 or 96 have? You will find that you are able to count the number of factors of each of these. Even if the numbers are as large as 10576, 25642 etc. or larger, you can still count the number of factors of such numbers, (though you may find it difficult to factorise such numbers). We say that number of factors of a given number are finite. 6. What are the multiples of 7? Obviously, 7, 14, 21, 28,... You will find that each of these multiples is greater than or equal to 7. Will it happen with each number? Check this for the multiples of 6, 9 and 10. We find that every multiple of a number is greater than or equal to that number. 7. Write the multiples of 5. They are 5, 10, 15, 20, ... Do you think this list will end anywhere? No! The list is endless. Try it with multiples of 6,7 etc. We find that the number of multiples of a given number is infinite. 8. Can 7 be a multiple of itself ? Yes, because 7 = 7×1. Will it be true for other numbers also? Try it with 3, 12 and 16. You will find that every number is a multiple of itself. MATHEMATICS 50 The factors of 6 are 1, 2, 3 and 6. Also, 1+2+3+6 = 12 = 2 × 6. We find that the sum of the factors of 6 is twice the number 6. All the factors of 28 are 1, 2, 4, 7, 14 and 28. Adding these we have, 1 + 2 + 4 + 7 + 14 + 28 = 56 = 2 × 28. The sum of the factors of 28 is equal to twice the number 28. A number for which sum of all its factors is equal to twice the number is called a perfect number. The numbers 6 and 28 are perfect numbers. Is 10 a perfect number? Example 1 : Write all the factors of 68. Solution : We note that 68 = 1 × 68 68 = 2 × 34 68 = 4 × 17 68 = 17 × 4 Stop here, because 4 and 17 have occurred earlier. Thus, all the factors of 68 are 1, 2, 4, 17, 34 and 68. Example 2 : Find the factors of 36. Solution : 36 = 1 × 36 36 = 2 × 18 36 = 3 × 12 36 = 4 × 9 36 = 6 × 6 Stop here, because both the factors (6) are same. Thus, the factors are 1, 2, 3, 4, 6, 9, 12, 18 and 36. Example 3 : Write first five multiples of 6. Solution : The required multiples are: 6×1= 6, 6×2 = 12, 6×3 = 18, 6×4 = 24, 6×5 = 30 i.e. 6, 12, 18, 24 and 30. EXERCISE 3.1 1. Write all the factors of the following numbers : (a) 24 (b) 15 (c) 21 (d) 27 (e) 12 (f) 20 (g) 18 (h) 23 (i) 36 2. Write first five multiples of : (a) 5 (b) 8 (c) 9 3. Match the items in column 1 with the items in column 2. Column 1 Column 2 (i) 35 (a) Multiple of 8 (ii) 15 (b) Multiple of 7 (iii) 16 (c) Multiple of 70 (iv) 20 (d) Factor of 30Read More

222 videos|105 docs|43 tests

### Test: Playing With Numbers - 1

- Test | 10 ques | 10 min
### Test: Playing With Numbers - 2

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### Chapter Notes - Playing with Numbers

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### Examples: Factors and Multiples

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### Worksheet Questions(Part - 1) - Playing with Numbers

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### Common Factors and Common Multiples

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